Ex 9

Statics – Exercise No. 9 6.51 Determine the force in member BD and the components of the reaction at C. Answer: FBD = 375 N (C) ; Cx = 205 N ; Cy = 360 N

6.89 The frame shown consists of members AD and EH, which are connected by two links. Determine the force in each link for the given loading. Answer: FDG = 6 KN (T); FCF = 9 KN (C); Ax = 1.8 KN ; Ay = 2.4 KN Ex = 1.8 KN ; Ey = 3.2 KN

6.92 A vertical load P of magnitude 750 N is applied to member ABC. Members ABC and DEF are parallel and are placed between two frictionless walls and connected by the link BE. Knowing that a = 0.75 m, determine the reactions at points A, C, D, and F. Answer: C = 375 N ; A = 1875 N ; Dy = 750 N ; Dx = 1500 N F = 3000 N

6.104 A 3600-kg steel ingot is lifted by lifted by a pair of tongs as shown. Determine the forces exerted at C and E on tong BCE. Answer: C = 20.5 KN ; E = 27.1 KN 40.70

7.5 A 4.5-kg uniform rod ABCDE has been bent Determine the internal forces (a) at point C, (b) obtained results draw the free body diagrams moments for the elements AB, BC, BDE. Answer: (a) FC = 55.18 N ; MC = 12.57 Nm

and is held by a wire sling as shown. just to right of point B, (c) using the with numerical values of forces and (b) FB = 55.2 N

; MC = 11.04 Nm

1

1

All the questions are taken from Ferdinand P. Beer and E. Russell Johnston Jr. “Vector Mechanics for Engineers, Statics” Second SI Metric Edition, McGraw-Hill Book Company.