Ejercicio 4.12.docx
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Ejercicio 4.12: Si la longitud del tanque de la figura 4.24 es de 1.2 m, calcule la fuerza total que se ejerce sobre su fondo. 𝐹𝑏 = 𝑝𝑏. 𝐴 ; 𝐴 = 2.0 × 1.2 𝑚² = 2.4 𝑚² 𝑃𝑏 = 200𝑘𝑃𝑎 + 𝑦(1.5 𝑚) + 𝑦𝑤 (2.6 𝑚) 𝑘𝑁
𝑃𝑏 = 200𝑘𝑃𝑎 + (0.80) (9.81 𝑚³) (1.5 𝑚) + (9.81)(2.6) = 237.3 𝑘𝑃𝑎 𝑁
𝐹𝑏 = (237.3 × 10³ 𝑚²) (2.4 𝑚²) = 569 × 10³ 𝑁 = 569𝑘𝑁
𝑃𝑏 = 200𝑘𝑃𝑎 + (0.80) (9.81 𝑚³) (1.5 𝑚) + (9.81)(2.6) = 237.3 𝑘𝑃𝑎 𝑁
𝐹𝑏 = (237.3 × 10³ 𝑚²) (2.4 𝑚²) = 569 × 10³ 𝑁 = 569𝑘𝑁
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