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45.Calculate Karl Pearson’s coefficient of correlation from the following data:

(1) Sum of deviation of X=5 (2) Sum of deviation of Y=4 (3) Sum of squares of deviations of X=40 (4) Sum of squares of deviation of Y=50 (5) Sum of products of deviation of X and Y=32 (6) No. Of pairs of observations =10

ANSWER: r=

βˆ‘π‘‘π‘₯βˆ—π‘‘π‘¦ βˆšβˆ‘π‘‘π‘₯2βˆ’βˆ‘π‘‘π‘¦2

r= r= r=

32 √40βˆ—50 32 √2000 32 √44βˆ™7213595

r=0 βˆ™ 7155

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