2x Unidad 1

  • June 2020
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// -------- Solución 1 ------------#include #define LIMINF 1 #define LIMSUP 10000 using namespace std; int main() { int const n=100; short int datos[n]; srand(time(NULL)); for(int i=0;idatos[i+1]) { temp=datos[i]; datos[i]=datos[i+1]; datos[i+1]=temp; hubocambio = true; }; etapa++; } while (hubocambio); // -------- Fin Cálculo de Resultados ----------printf("Dato Menor: %d\n",datos[0]); printf("Dato Mayor: %d\n",datos[n-1]); system("pause"); return 0; }

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// ------------ Solución 2 ------------#include #define LIMINF 1 #define LIMSUP 10000 using namespace std; int main() { int const n=100; short int datos[n]; srand(time(NULL)); for(int i=0;imayor) mayor=datos[i]; } // ------ Inicia Cálculo de Resultados ---------printf("Dato Menor: %d\n",menor); printf("Dato Mayor: %d\n",mayor); system("pause"); return 0; } /$&203/(-,'$'6(38('(2%7(1(5'(0$1(5$6

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// Programa 1 #include #define LIMINF 1 #define LIMSUP 10000 using namespace std;

int main() { int const n=10000; short int datos[n]; srand(time(NULL));

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// ------ Inicia Cálculo de Resultados ----------



double contador=0;



int temp; int etapa = 1; bool hubocambio; contador += 3; do { hubocambio = false;

   

contador += 2; //la declaración “int i=0” también cuenta



for(int i=0;i
contador++; if (datos[i]>datos[i+1]) {

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} etapa++; contador += 2; // etapa++ y while } while (hubocambio); // ------ Fin Cálculo de Resultados ----------

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final = clock(); printf("Tiempo Transcurrido: %10.3f seg\n", float(final-inicial)/CLOCKS_PER_SEC); printf("Contador : %f\n",contador); printf("Dato Menor: %d\n",datos[0]); printf("Dato Mayor: %d\n",datos[n-1]); system("pause"); return 0; }

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// Programa 2 #include #define LIMINF 1 #define LIMSUP 10000 using namespace std; int main() { int const n=500000; short int datos[n]; srand(time(NULL)); // semilla

/* for(int i=0;i
contador += 2; for(int i=0;i
contador += 2; // los 2 if if (datos[i]<menor) {menor=datos[i];contador++; } if (datos[i]>mayor) {mayor=datos[i];contador++; } } // ------ Fin Cálculo de Resultados ----------

final = clock(); printf("Tiempo Transcurrido: %10.3f seg\n", float(final-inicial)/CLOCKS_PER_SEC); printf("Contador : %f\n",contador); printf("Dato Menor: %d\n",menor); printf("Dato Mayor: %d\n",mayor); system("pause"); return 0; }



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PROGRAMA 1 DATOS ALEATORIOS N Contador Tiempo 1,000 1,497,318 0.06 2,000 6,038,834 0.33 5,000 37,422,768 0.94 10,000 149,026,394 3.52 20,000 602,414,994 13.34 50,000 3,739,551,608 79.59 100,000 14,974,791,796 293.52 200,000 500,000 1,000,000

PROGRAMA 1 DATOS ORDENADOS N Contador Tiempo 1,000 1,006 0 2,000 2,006 0 5,000 5,006 0 10,000 10,006 0 20,000 20,006 0 50,000 50,006 0 100,000 100,006 0 200,000 200,006 0 500,000 500,006 0 1,000,000 1,000,006 0.06

PROGRAMA 1 DATOS ORDENADOS A LA INVERSA N Contador Tiempo 1,000 2,501,503 0.06 2,000 10,003,003 0.11 5,000 62,507,503 0.87 10,000 250,012,723 3.08 20,000 999,987,727 11.65 50,000 6,249,672,724 73.98 100,000 24,998,347,699 304.73 200,000 500,000 1,000,000

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