2nd Q- Math4 Answer Key-admu
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2Q – MATH ANSWER KEY I. 1. 2. 3. 4. 5.
DIVISION 526 R 3 562 R 2 150 R 3 68 74 R 13
1. C 2. A 3. C
LOM 1. 2 674 ÷ 15 = n 2. (1 853 ÷ 16) + 1 200 = n 3. 3 545 ÷ (5 x 5) = n PROBLEM SOLVING 1. P188.61 savings of Frodo 2. 35 loot bags
III. COMPARING AND ORDERING A. 1. < 2. < 3. = 4. < 5. > 6. = B. least to greatest 1. A C B D 2. C A D B 3. D A C B C. greatest to least 1. D C B A 2. D B A C 3. B C A D
IV. ROUNDING OFF A. 1. C 2. A 3. D 4. A 5. B 6. C 7. A 8. D 9. D 10. B B. 1. 45.70 2. 9 300.00 3. 5 374.00 4. 0.50 5. 543.21
II. CONCEPT OF DECIMALS A. 1. 0.72 2. 0.18 3. 2.30 B. 4-6 shading C. 1. 0.3 2. 1.75 3. 1 4. 0.6 5. 1.9 D. number lines E. 1. 34.5 2. 746.25 3. 2 530.48 4. 65.4 6. 75.03 F. 1. hundredths 2. 800 3. 0 4. 9 5. 9 237 861.55 6. 9 237 861.03 7. 92 378 610 V. + AND – OF DECIMALS A. 1. 65.93 + (24.5+62.4)=n n=152.83 2. 602.47 – 245.64 = n n = 356.83 3. (63.24 + 53+ 25) – 110.32 = n n = 30.92 4. 62.53 – (14.25 +32.74)=n n= 15.54 B. 1. 53.49 2. 2.12 3. 18.87
VI. x OF DECIMALS A. 1. D 2. B 3. A 4. E B. 1. 0.7 X 0.3 = 0.21 2. 4.2 X 3 = 12.6 3. 4 X 0.3 = 1.2 4. 0.5 X 0.02 = 0.01 5. 0.3 6. 0.32 7. 4.2
VII. PROBLEM SOLVING 1. (P244.45 X2) – (P188.45X2) = N N=PHP112 2. P3000 – (P800+P750+P569.5 5) = n; n=PHP880.45 3. A) 2.9+1.2+4.3=n n=8.4 B) n – (8.4 X P6) =P49.60 n = PHP100 4. 15.4 x 21 = 323.4 liters 5. 40.5 x 0.4=n n = 16.2 kilograms 6. 50 x 4.4 = n n = 220 kilos 7. (P200+P50+P7.50) x 100 = n n= P25 750 is the total bill
DIVISION 526 R 3 562 R 2 150 R 3 68 74 R 13
1. C 2. A 3. C
LOM 1. 2 674 ÷ 15 = n 2. (1 853 ÷ 16) + 1 200 = n 3. 3 545 ÷ (5 x 5) = n PROBLEM SOLVING 1. P188.61 savings of Frodo 2. 35 loot bags
III. COMPARING AND ORDERING A. 1. < 2. < 3. = 4. < 5. > 6. = B. least to greatest 1. A C B D 2. C A D B 3. D A C B C. greatest to least 1. D C B A 2. D B A C 3. B C A D
IV. ROUNDING OFF A. 1. C 2. A 3. D 4. A 5. B 6. C 7. A 8. D 9. D 10. B B. 1. 45.70 2. 9 300.00 3. 5 374.00 4. 0.50 5. 543.21
II. CONCEPT OF DECIMALS A. 1. 0.72 2. 0.18 3. 2.30 B. 4-6 shading C. 1. 0.3 2. 1.75 3. 1 4. 0.6 5. 1.9 D. number lines E. 1. 34.5 2. 746.25 3. 2 530.48 4. 65.4 6. 75.03 F. 1. hundredths 2. 800 3. 0 4. 9 5. 9 237 861.55 6. 9 237 861.03 7. 92 378 610 V. + AND – OF DECIMALS A. 1. 65.93 + (24.5+62.4)=n n=152.83 2. 602.47 – 245.64 = n n = 356.83 3. (63.24 + 53+ 25) – 110.32 = n n = 30.92 4. 62.53 – (14.25 +32.74)=n n= 15.54 B. 1. 53.49 2. 2.12 3. 18.87
VI. x OF DECIMALS A. 1. D 2. B 3. A 4. E B. 1. 0.7 X 0.3 = 0.21 2. 4.2 X 3 = 12.6 3. 4 X 0.3 = 1.2 4. 0.5 X 0.02 = 0.01 5. 0.3 6. 0.32 7. 4.2
VII. PROBLEM SOLVING 1. (P244.45 X2) – (P188.45X2) = N N=PHP112 2. P3000 – (P800+P750+P569.5 5) = n; n=PHP880.45 3. A) 2.9+1.2+4.3=n n=8.4 B) n – (8.4 X P6) =P49.60 n = PHP100 4. 15.4 x 21 = 323.4 liters 5. 40.5 x 0.4=n n = 16.2 kilograms 6. 50 x 4.4 = n n = 220 kilos 7. (P200+P50+P7.50) x 100 = n n= P25 750 is the total bill
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