Zarate Practica 4.docx

6

Cálculos y resultados

Tabla 6.1 Reporte de resultados.

o

𝑪𝑨𝟎

Tiempo (min)

Volumen gastado NaOH (ml).

CC (M)

CA

ln 𝑪𝑨

1/CA

T (°C)

T (K)

0 10 20 30 40 50 60

0 17.2 24.9 28.2 30.5 32.1 32.6

0 0.043 0.06225 0.0705 0.07625 0.08026 0.0815

0.1386 0.0956 0.07635 0.0681 0.06235 0.05834 0.0571

0 0.3714 0.5962 0.7106 0.7988 0.8653 0.8867

7.2150 10.4602 13.0975 14.6842 16.0384 17.1408 17.51

35 35 35 35 35 35 35

308.15 308.15 308.15 308.15 308.15 308.15 308.15

Fórmulas δ=

𝑪𝟏 𝑪𝟐((𝟏+(𝟏−

𝑻 )).𝑪𝟒 𝑪𝟑

𝑚 = 𝜌𝑣 𝑛=

𝐶𝐴° =

𝑚 𝑃𝑀

𝑛ú𝑚𝑒𝑟𝑜 𝑑𝑒 𝑚𝑜𝑙𝑒𝑠 𝑉𝑜𝑙𝑢𝑚𝑒𝑛 𝑡𝑜𝑡𝑎𝑙 𝐶𝐶 =

𝐶𝐵 𝑉𝐵 𝑉𝑐

𝐶𝐴𝑡 = 𝐶𝐴° − 𝐶𝐶 𝑡 o

Datos

PM = 88.11 g/mol NNaOH = 0.2N = 0.2M  = 0.902 g/ml Vacetato = 5 ml Vagua = 100 ml Vtotal = 105 ml = 0.105 L

 Para la masa

𝑚 = 𝜌𝑣 = (0.902

𝑔 ) (5 𝑚𝑙) = 4.51 𝑔 𝑚𝑙

 Para “n”

𝑛=

𝑚 4.51 𝑔 = = 0.0511 𝑚𝑜𝑙 𝑃𝑀 88.11 𝑔/𝑚𝑜𝑙

 Para “concentración inicial”

𝐶𝐴° =

𝑛ú𝑚𝑒𝑟𝑜 𝑑𝑒 𝑚𝑜𝑙𝑒𝑠 0.0511 𝑚𝑜𝑙 𝑚𝑜𝑙 = = 0.4866 𝑉𝑜𝑙𝑢𝑚𝑒𝑛 𝑡𝑜𝑡𝑎𝑙 0.105 𝐿 𝐿

 Para “Cc”

𝐶𝐶 =

𝐶𝐵 𝑉𝐵 𝑉𝑐

𝐶𝐶0𝑚𝑖𝑛 =

(0.2𝑀)(0𝑚𝑙) =0𝑀 80𝑚𝑙

𝐶𝐶10𝑚𝑖𝑛 =

(0.2𝑀)(2.8𝑚𝑙) = 7𝑥10−3 𝑀 80𝑚𝑙

𝐶𝐶20𝑚𝑖𝑛 =

(0.2𝑀)(3.2𝑚𝑙) = 8𝑥10−3 𝑀 80𝑚𝑙

𝐶𝐶30𝑚𝑖𝑛 =

(0.2𝑀)(3.9𝑚𝑙) = 9.75𝑥10−3 𝑀 80𝑚𝑙

𝐶𝐶40𝑚𝑖𝑛 =

(0.2𝑀)(4.5𝑚𝑙) = 0.01125 𝑀 80𝑚𝑙

𝐶𝐶50𝑚𝑖𝑛 =

(0.2𝑀)(5𝑚𝑙) = 0.0125 𝑀 80𝑚𝑙

𝐶𝐶60𝑚𝑖𝑛 =

(0.2𝑀)(5.4𝑚𝑙) = 0.0135 𝑀 80𝑚𝑙

 Para “CA” 𝐶𝐴𝑡 = 𝐶𝐴° − 𝐶𝐶 𝑡 𝐶𝐴0𝑚𝑖𝑛 = (0.4866 − 0)

𝑚𝑜𝑙 𝑚𝑜𝑙 = 0.4866 𝐿 𝐿

𝐶𝐴10𝑚𝑖𝑛 = (0.4866 − 7𝑥10−3 )

𝑚𝑜𝑙 𝑚𝑜𝑙 = 0.4796 𝐿 𝐿

𝐶𝐴20𝑚𝑖𝑛 = (0.4866 − 8𝑥10−3 )

𝑚𝑜𝑙 𝑚𝑜𝑙 = 0.4786 𝐿 𝐿

𝐶𝐴30𝑚𝑖𝑛 = (0.4866 − 9.75𝑥10−3 ) 𝐶𝐴40𝑚𝑖𝑛 = (0.4866 − 0.0112 ) 𝐶𝐴50𝑚𝑖𝑛 = (0.4866 − 0.0125)

𝑚𝑜𝑙 𝑚𝑜𝑙 = 0.4768 𝐿 𝐿

𝑚𝑜𝑙 𝑚𝑜𝑙 = 0.4754 𝐿 𝐿

𝑚𝑜𝑙 𝑚𝑜𝑙 = 0.4741 𝐿 𝐿

𝐶𝐴60𝑚𝑖𝑛 = (0.4866 − 0.0135 )

𝑚𝑜𝑙 𝑚𝑜𝑙 = 0.4731 𝐿 𝐿

 Para “lnCA” 𝑙𝑛𝐶𝐴0𝑚𝑖𝑛 = ln(0.4866) = −0.7203 𝑙𝑛𝐶𝐴10𝑚𝑖𝑛 = ln(0.4796) = −0.7348 𝑙𝑛𝐶𝐴20𝑚𝑖𝑛 = ln(0.4786) = −0.7368 𝑙𝑛𝐶𝐴30𝑚𝑖𝑛 = ln(0.4768) = −0.7406 𝑙𝑛𝐶𝐴40𝑚𝑖𝑛 = ln(0.4754) = −0.7435 𝑙𝑛𝐶𝐴50𝑚𝑖𝑛 = ln(0.4741) = −0.7463 𝑙𝑛𝐶𝐴60𝑚𝑖𝑛 = ln(0.4731) = −0.7484

 Para “k demostrando el orden de reacción” 𝐶𝐴° − 𝐶𝐴𝑡 𝑘= 𝑡 -

Primer orden 𝑙𝑛𝐶𝐴° − 𝑙𝑛𝐶𝐴𝑡 𝑘= 𝑡

-

Segundo Orden 1 1 − 𝑡 ° 𝐶𝐴 𝑘 = 𝐶𝐴 𝑡

Tabla 6.2 Reporte del orden de reacción. Tiempo 10 20 30 40 50 60 n=0

Volumen gastado NaOH (l). 0.0028 0.0032 0.0039 0.0045 0.005 0.0054 k =3.635x10-4

Orden cero

Primer Orden

Segundo orden

7x10-4 4x10-4 3.26x10-4 2.8x10-4 2.5x10-4 2.25x10-4

1.45x10-3 8.25x10-4 6.7666x10-4 5.8x10-4 5.2x10-4 4.6833x10-4

7.0016x10-4 4.0058x10-4 3.2714x10-4 2.7993x10-4 2.5009x10-4 2.2523x10-4

 Para “Orden Cero” 𝐶𝐴° − 𝐶𝐴𝑡 𝑘= 𝑡 𝑘10𝑚𝑖𝑛 =

0.4866 − 0.4796 10

 Para “Primer Orden” 𝑘= 𝑘=

𝑙𝑛𝐶𝐴° − 𝑙𝑛𝐶𝐴𝑡 𝑡

−0.7203 − (−0.7348) 10

 Para “Segundo Orden” 1 1 ° − 𝐶𝐴𝑡 𝐶𝐴 𝑘= 𝑡 1 1 − 2.0550 2.0850 𝑘= 10

o

Gráficas