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A) DISEΓO DE LA FLECHA: c. V (lb) 2418,58
L (in) -906.966 M (lb.in)
7255.74
L (in)
Para 0<x<9 de izquierda a derecha M1-2= 242*X π¦=
1 π3 β (242 β + πΆ1 β π + πΆ2 ) πΈπΌ 6
Donde C1 = -1814.61 y C2=0
π¦=
1 π3 β (242 β β 1 814.61 β π) πΈπΌ 6
Para 0<x<2 de derecha a izquierda M2-3= 242*X π¦=
1 π3 β (242 β + πΆ3 β π + πΆ4 ) πΈπΌ 6
Donde C3 = 5810.39 y C4=0
1
π¦ = πΈπΌ β (1088 β
x
π3 6
+ 5810.39 β π)
y 0 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 6.5 7 7.5 8 8.5 9 9.5 10 10.5 11
0 -0.37391189 -0.37809894 -0.37543044 -0.3636212 -0.34038604 -0.30343979 -0.25049724 -0.17927323 -0.08748256 0.027159946 0.166939472 0.334141202 -0.34523803 -0.30703809 -0.14300564 0.043815482 0.254849558 0.354107148 0.311031585 0.137120067 0
pendiente 0.4 0.3 0.2 0.1 0 -0.1 -0.2 -0.3 -0.4 -0.5
0
2
4
6
8
10
12
L (in) -906.966 M (lb.in)
7255.74
L (in)
Para 0<x<9 de izquierda a derecha M1-2= 242*X π¦=
1 π3 β (242 β + πΆ1 β π + πΆ2 ) πΈπΌ 6
Donde C1 = -1814.61 y C2=0
π¦=
1 π3 β (242 β β 1 814.61 β π) πΈπΌ 6
Para 0<x<2 de derecha a izquierda M2-3= 242*X π¦=
1 π3 β (242 β + πΆ3 β π + πΆ4 ) πΈπΌ 6
Donde C3 = 5810.39 y C4=0
1
π¦ = πΈπΌ β (1088 β
x
π3 6
+ 5810.39 β π)
y 0 1 1.5 2 2.5 3 3.5 4 4.5 5 5.5 6 6.5 7 7.5 8 8.5 9 9.5 10 10.5 11
0 -0.37391189 -0.37809894 -0.37543044 -0.3636212 -0.34038604 -0.30343979 -0.25049724 -0.17927323 -0.08748256 0.027159946 0.166939472 0.334141202 -0.34523803 -0.30703809 -0.14300564 0.043815482 0.254849558 0.354107148 0.311031585 0.137120067 0
pendiente 0.4 0.3 0.2 0.1 0 -0.1 -0.2 -0.3 -0.4 -0.5
0
2
4
6
8
10
12
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