Well Logging Penentuan Zona Sw.docx

Nama : Ahfasy Kautsar Imam NPM : 1615051040

Tugas 4 Metode Well Logging SOAL: Data suatu survei log rnenunjukkan adanya beberapa lapisan yang potensial. Data tambahan adalah sebagai berikut: Tf = 200OF O Rm @ 78 F = 0,135 ohm-m Rmf @ 78OF = 0,106 ohm-m Rmc @ 75OF = 0,151 ohm-m =1.1 gr/cc f a =1 n =2 Tentukan nilai Sw pada daerah yang produktif !!

Kurva Log

Zona 1 Water Bearing

Zona 2 Water Bearing Zona 3 Water Bearing

Zona 4 Water Bearing

Zona 5 Water Bearing Zona 6 Water Bearing

Zona 7 Water Bearing

Zona 8 Water Bearing

Zona 9 Water Bearing

Zona 10 Water Bearing

Zona

LLD

Neutron Porosity (%)

Density (g/cc)

1 2 3 4 5 6 7 8 9 10

0,72 0,61 0,5 0,75 0,75 0,75 0,61 0,8 1,22 1,31

39 40 45 45 36 39 25 35 31 30

2,30 2,35 2,20 2,25 2,34 2,27 2,37 2,40 2,38 2,50

Zona 1 Neutron Porosity = 39 Density = 2,30

Dolomite 34%

Zona 2 Neutron Porosity = 40 Density = 2,35

Dolomite 33%

Zona 3 Neutron Porosity = 46 Density = 2,20

Dolomite 39%

Zona 4 Neutron Porosity = 46 Density = 2,25

Dolomite 38%

Zona 5 Neutron Porosity = 36 Density = 2,34

Dolomite 32%

Zona 6 Neutron Porosity = 39 Density = 2,27

Dolomite 35%

Zona 7 Neutron Porosity = 25 Density = 2,37

Calcite 23%

Zona 8 Neutron Porosity = 35 Density = 2,40

Calcite 33%

Zona 9 Neutron Porosity = 31 Density = 2,38

Dolomite 28%

Zona 10 Neutron Porosity = 30 Density = 2,50

Calcite 29%

Rt = LLD Zona

Rt

Jenis batuan

Porosity (%)

1 2 3 4 5 6 7 8 9 10

0,72 0,61 0,5 0,75 0,75 0,75 0,61 0,8 1,22 1,31

Dolomite Dolomite Dolomite Dolomite Dolomite Dolomite Calcite Calcite Dolomite Calcite

34 33 39 38 32 35 23 33 28 29

Picked Plot

m = y/x m = 4,21/2,29 = 1,8

 m

Penentuan mencari m: = y/x = 4,21/2,29 = 1,8

 Penentuan Pencarian Rw: Log Rt = -2log porositas + log (aRw)

 Penentuan Sw: Pada Sw 100% kita ambil nilai Ф = 25% dan Rt = 1 = Ro 𝑅𝑜 Rumus: 𝑆𝑤 2 = 𝑅𝑡 a. Rt = 1.6 ohm meter 𝑅𝑜

1

Sw = √ 𝑅𝑡 = √1,6 = 0.79 = 79% b. Rt = 2,5 ohm meter 𝑅𝑜

1

Sw = √ 𝑅𝑡 = √2,5 = 0.63 = 63% c. Rt = 4 ohm meter 𝑅𝑜

1

Sw = √ 𝑅𝑡 = √4 = 0.5 = 50% d. Rt = 7,7 ohm meter 𝑅𝑜

Sw = √



𝑅𝑡

1

= √ = 0.36 = 36% 7,7

GRSH GRsh = 60

GRSH = 60 

GRcl GRcl = 15

GRcl = 15

ZONA PROSPEK HIDROKARBON 1

GR1a = 16 GR1b = 20 GR1c = 17 Rt1 = 45 Rt2 = 250 Rt3 = 65 𝑅𝑡1 +𝑅𝑡2+ 𝑅𝑡3 45 +250+ 65 Rtrata-rata = = 3 3

= 120

Vshale 1 GRsh = 60 GRcl = 15 GRzona1a = 16 IGR

𝐺𝑅− 𝐺𝑅

=𝐺 =

𝑐𝑙

𝑅𝑠ℎ − 𝐺𝑅 𝑐𝑙

16−15 60−15

= 0,02

Vshale = 0,083 (2(3,7×𝑖𝐺𝑅 ) −1) Vshale = 0,083 (2(3,7×0,02) −1) = 0,004

Vshale 2 GRsh = 60 GRcl = 15 GRzona1a = 20 IGR

𝐺𝑅− 𝐺𝑅

=𝐺 =

𝑐𝑙

𝑅𝑠ℎ − 𝐺𝑅 𝑐𝑙

20−15 60−15

= 0,1

Vshale = 0,083 (2(3,7×𝑖𝐺𝑅 ) −1) Vshale = 0,083 (2(3,7×0,1) −1) = 0,024

Vshale 3 GRsh = 60 GRcl = 15 GRzona1a = 17 IGR

𝐺𝑅− 𝐺𝑅

=𝐺 =

𝑐𝑙

𝑅𝑠ℎ − 𝐺𝑅 𝑐𝑙

17−15

= 0,04

60−15 Vshale = 0,083 (2(3,7×𝑖𝐺𝑅 ) −1)

Vshale = 0,083 (2(3,7×0,04) −1) = 0,009 Rata-rata nilai Vshale zona prospek 1 : Vshale =

𝑉𝑠ℎ𝑎𝑙𝑒1 + 𝑉𝑠ℎ𝑎𝑙𝑒2 + 𝑉𝑠ℎ𝑎𝑙𝑒3 3

=

0,004+0,024+0,009 3

= 0,012

ZONA PROSPEK HIDROKARBON 2

GR2 = 19 Rt = 90

Vshale GRsh GRcl GRzona2

= 60 = 15 = 19

IGR

=𝐺

𝐺𝑅− 𝐺𝑅

=

𝑐𝑙

𝑅𝑠ℎ − 𝐺𝑅 𝑐𝑙

19−15

= 0,09

60−15

Vshale = 0,083 (2(3,7×𝑖𝐺𝑅 ) −1) Vshale = 0,083 (2(3,7×0,09) −1) = 0,021