Voltage Drop Calculation

  • June 2020
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BUSDUCT - 1A Proposed Busbar Rating

= 2500 Amps

Line Voltage (V)

= 400 Volts

Maximum Demand (MD)

= 810.9 kW

Temperature Coeffient of Resistance (α)

= 0.00385

Maximum Current (I)

= MD*1000 / √3 V Cos Φ = 810.9*1000 / (1.732*400*0.9) = 1300.5196 Amps

Resistance (mΩ/M) at 95oC

= 0.0222 mΩ/M (As per catalogue)

o

= 0.0085 mΩ/M (As per catalogue)

o

= R95(1+ α(50-95))

Reactance (mΩ/M) at 95 C Resistance (mΩ/M) at 50 C, R

= 0.0183539 mΩ/M Reactance (mΩ/M) at 50oC, X

= 0.0085 mΩ/M

Cos Φ

= 0.9

Sin Φ

= 0.43589

Voltage Drop upto 1st Tap off (∆Va) Load Distribution Factor (€)

= 1

Busduct Length (L) upto 1st Tap off

= 156 Meters

Voltage Drop of Full Load (∆Va)

= €.√3.L.I.(R Cos Φ + X Sin Φ) 10 Volts

-3

= 7.1063462 Volts Voltage Drop after 1st Tap off (∆Vb) Load Distribution Factor (€)

= 0.5

Busduct Length (L) After 1st Tap off

= 54 Meters

Voltage Drop of Distributed Load (∆Vb)

-3 = €.√3.L.I.(R Cos Φ + X Sin Φ) 10 Volts

= 1.2299445 Volts

% Voltage Drop (%V)

= (∆Va + ∆Vb)*100 / V = 2.084073 %

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