Voltage Drop Calculation
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BUSDUCT - 1A Proposed Busbar Rating
= 2500 Amps
Line Voltage (V)
= 400 Volts
Maximum Demand (MD)
= 810.9 kW
Temperature Coeffient of Resistance (α)
= 0.00385
Maximum Current (I)
= MD*1000 / √3 V Cos Φ = 810.9*1000 / (1.732*400*0.9) = 1300.5196 Amps
Resistance (mΩ/M) at 95oC
= 0.0222 mΩ/M (As per catalogue)
o
= 0.0085 mΩ/M (As per catalogue)
o
= R95(1+ α(50-95))
Reactance (mΩ/M) at 95 C Resistance (mΩ/M) at 50 C, R
= 0.0183539 mΩ/M Reactance (mΩ/M) at 50oC, X
= 0.0085 mΩ/M
Cos Φ
= 0.9
Sin Φ
= 0.43589
Voltage Drop upto 1st Tap off (∆Va) Load Distribution Factor (€)
= 1
Busduct Length (L) upto 1st Tap off
= 156 Meters
Voltage Drop of Full Load (∆Va)
= €.√3.L.I.(R Cos Φ + X Sin Φ) 10 Volts
-3
= 7.1063462 Volts Voltage Drop after 1st Tap off (∆Vb) Load Distribution Factor (€)
= 0.5
Busduct Length (L) After 1st Tap off
= 54 Meters
Voltage Drop of Distributed Load (∆Vb)
-3 = €.√3.L.I.(R Cos Φ + X Sin Φ) 10 Volts
= 1.2299445 Volts
% Voltage Drop (%V)
= (∆Va + ∆Vb)*100 / V = 2.084073 %
= 2500 Amps
Line Voltage (V)
= 400 Volts
Maximum Demand (MD)
= 810.9 kW
Temperature Coeffient of Resistance (α)
= 0.00385
Maximum Current (I)
= MD*1000 / √3 V Cos Φ = 810.9*1000 / (1.732*400*0.9) = 1300.5196 Amps
Resistance (mΩ/M) at 95oC
= 0.0222 mΩ/M (As per catalogue)
o
= 0.0085 mΩ/M (As per catalogue)
o
= R95(1+ α(50-95))
Reactance (mΩ/M) at 95 C Resistance (mΩ/M) at 50 C, R
= 0.0183539 mΩ/M Reactance (mΩ/M) at 50oC, X
= 0.0085 mΩ/M
Cos Φ
= 0.9
Sin Φ
= 0.43589
Voltage Drop upto 1st Tap off (∆Va) Load Distribution Factor (€)
= 1
Busduct Length (L) upto 1st Tap off
= 156 Meters
Voltage Drop of Full Load (∆Va)
= €.√3.L.I.(R Cos Φ + X Sin Φ) 10 Volts
-3
= 7.1063462 Volts Voltage Drop after 1st Tap off (∆Vb) Load Distribution Factor (€)
= 0.5
Busduct Length (L) After 1st Tap off
= 54 Meters
Voltage Drop of Distributed Load (∆Vb)
-3 = €.√3.L.I.(R Cos Φ + X Sin Φ) 10 Volts
= 1.2299445 Volts
% Voltage Drop (%V)
= (∆Va + ∆Vb)*100 / V = 2.084073 %
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