Variation

  • November 2019
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NAME__________________________________

PEARL ACADEMY Anjali Apartment Near Sapna Hall Makarpura road Vadodara-390 009 Cell:-9825283326 9426765811

VARIATION Practice Exercise - l ___________________________________________________________________________________

1. If X ∝Y , when X = 3, Y = 6, find Y when X = 4 2. If Y ∝X , when X = 16, Y = 2, find X when Y = 3 1 3. If X ∝Y , when X = 2, Y = 2, find X when Y = 2 4. If X ∝Y , when X = 4, Y = 2, find Y when X = 18 5. If X is in direct variation with Z and when X=11 then Z=363, find Z when X=3 6. If X ∝ Y3, when X = 8, Y = 2, find X when Y = 9 and also find Y when X = 64 7. X2 ∝

Y , When Y = 64, X = 2 , find Y when X = 3

8. X ∝

Y , when X = 3 Y =81, find Y when X = 4

9. If X ∝Y2 , when X = 6, Y = 2, find X when Y = 6 and also find Y when X=24

10. If X ∝

1 , when X = 3, Y = 30, find Y when X = 2 and also find X when Y

Y=10 11. If X ∝ Y=5

3

Y , when X = 27, Y = 6, find Y when X = 64 and also find X when

12. The cube of Y varies directly as the square of XD, when Y=2 X=4, find Y 1 when X= 2 13. The cube of X varies inversely as the square root of Y, X=1 when Y=36, find Y when X=2 14. X ∝

1 and when X=2, Y=14, then find the value of Y for X=& Y

1

1 1 1 for X=20, Y = , find X for Y = and find Y for X=5 Y 4 2 1 16. X ∝ , when Y=25, X=2, find X if Y=100 Y 1 17. Y ∝ , when X =16, Y = $, find the value of Y for X =64 X 18. The cube of X varies as the inverse of square root of Y. When X= 2, Y =16, find Y when X =1 15. X ∝

19. Y∝

1 3

for X =512, Y=2 find Y when X =343 and Y when X =216

X

20. X3 ∝ Y2 ∴ Y ∝ ________ 21. X2 ∝

22. X2 ∝

1 ∴ Y ∝ _________ Y4 1 Y

∴ Y ∝ _________

23. X5 ∝ Y5 ∴ Y ∝ _________ 24.

X ∝ Y2 ∴ Y ∝ _________

25. 3X2 = 5Y3 ∴ Y ∝ _________ 26. XY3 = non zero constant, ∴ Y ∝ _________ 2

27. Y ∝ X 3 and Y =12 when X =8. Then X =_________ when Y =48 1

1

28. X 2 varies inversely as Y 3 , Y=8 when X = 9, find X when Y =216 29. X ∝Yn where n = -2, when X =8, Y = Y= 2

1 , Then X = ____________ when 4

1 3

30. X 3 ∝

1 2

Y3

, when X =8 , Y =27, find X when Y =216

2

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