Uk Regresi Liniear.xlsx

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SOAL UJI KOMPETENSI I REGRESI LINEAR

Abdul Aziz 17106030037

Suatu instrumen sensor amonia SnO2 akan digunakan untuk menentukan kadar NH3 terlarut Dari uji validasi metode diperoleh hasil pengukuran larutan standar sbb:

[ NH3 ] 1 2 5 10 15 25

RI (volt) 0.903333 0.773333 0.713333 0.693333 0.673333 0.636667

Rio (Vo) 0.863 0.863 0.863 0.863 0.863 0.863

delta RI (volt) 0.040333 0.089667 0.149667 0.169667 0.189667 0.226333

a. Tentukan adakah korelasi linier respon instrumentasi dengan konsentrasi NH3 ! b. Tentukan persamaan regresi yang paling sesuai untuk data tersebut ! c. Tentukan batas deteksi dan batas kuantifikasi dari metode tersebut !

JAWABAN a.

r^2 = r= n= n-2 =

0.805 0.8972179222 6 4

1-r = akar n-2 = akar 1-r = t hitung = t kritis =

t hitung > t kritis maka Ho ditolak atau hubungan antara variabel x dan y linear

b.

[ NH3 ] 1 2 5 10 15 25

delta RI (volt) 0.040333 0.089677 0.149677 0.169677 0.189677 0.226333

Grafik Hubungan RI (volt) dengan [NH3] 1 0.9 0.8 0.7 0.6 0.5

f(x) = - 0.0083518569x + 0.8129566169 R² = 0.6437491843

Grafik Hubungan RI (volt) dengan [NH3] 1 0.9 0.8

f(x) = - 0.0083518569x + 0.8129566169 R² = 0.6437491843

0.7 0.6 0.5 0.4 0.3 0.2 0.1 0

0

5

10

y= R² = Slope = Intersep = c.

y-yB = Sy/x yBar =

0.0067x + 0.0796

x 1 2 5 10 15 25

yi 0.040333 0.089667 0.149667 0.169667 0.189667 0.226333

15

20

0.0067x + 0.0796 0.8057 0.0067 0.0796

3*Sy/x

yBar 0.0863 0.093 0.1131 0.1466 0.1801 0.2471 Total

n= n-2 = Sy/x = yb =

6 4 0.0336009737 Intersep

yi-yBar -0.045967 -0.003333 0.036567 0.023067 0.009567 -0.020767

25

Abdul Aziz 17106030037

r NH3 terlarut

0.195 2 0.4415880433 4.0635969919 2.7764451052

n antara variabel x dan y linear

dengan [NH3]

Grafik Hubungan [NH3] dengan delta 0.25 0.2 0.15

f(x) = 0.0066845151x + 0.0796120207 R² = 0.8057464302

dengan [NH3]

Grafik Hubungan [NH3] dengan delta 0.25

f(x) = 0.0066845151x + 0.0796120207 R² = 0.8057464302

0.2 0.15 0.1 0.05

20

25

(yi-yBar)^2 0.00211297 0.00001111 0.00133715 0.00053209 0.00009153 0.00043127 0.00451610

30

LoD y-yB y y= x= x=

0

0

3Sy/x 3Sy/x 3Sy/x + yB 0.1804029211 (y-0.00796)/0.0067 15.0452121039 Jadi, Limit of Detection nya adalah 15.0452

LoQ = 10Sy/x y-yB = 10Sy/x y= 10Sy/x + yB y= 0.415609737 x= (y-0.00796)/0.0067 x= 50.150707013 Jadi, Limit of Quantification nya adalah 50.15071

5

10

15

20

n [NH3] dengan delta RI (volt)

.0796120207

n [NH3] dengan delta RI (volt)

.0796120207

0

15

20

25

30

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