Tutorial 2
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1.
Five capacitors are combined in parallel. Their total capacitance is their sum, i.e. Ctotal = C1 + C2 + C3 + C4 + C5. Calculate the uncertainty in the total capacitance if their values are: (820 ± 20) x 10-9 F (220 ± 40) x 10-9 F
2.
(560 ± 10) x 10-9 F (180 ± 40) x 10-9 F
(470 ± 10) x 10-9 F
Calculate the difference, with its associated uncertainty, between the following two readings: 57.6 ± 0.2 cm and 50.0 ± 0.1 cm
3.
The wavelength of the laser light has been calculated from the gradient of a graph to be 0.0064 ± 0.0002. Use the equation λ = gradient × d to calculate the value, with its associated uncertainty, of the wavelength λ where d has the value (1.00 ± 0.01) × 10−4 m.
4. L (±1) cm
y (± 0.1) cm 1
2
3
4
x (cm) 5
Averag e 6.4 ± 0.3
250 300
7.6
7.8
7.7
7.6
7.8
350
9.0
8.8
9.1
8.9
9.2
400
10.2
10.2
10.3
10.0
10.3
450
11.4
11.6
11.4
11.6
11.5
500
12.9
12.6
12.9
12.8
12.8
The table shows data that has been collected from an experiment. Calculate the missing averages. Report figures to correct number of S.F. with associated uncertainty. Use the equation: Y = 4x + 2 to calculate x with its associated uncertainty.
5. Frequenc y,f (Hz) ± 20 Hz
Current, I (mA)
Average Current, Iave (mA)
200
15.7
15.9
17.5
16.8
17.0
400
34.1
34.5
33.0
32.7
32.0
600
49.0
48.3
48.7
52.6
48.8
800
66.4
66.9
65.5
64.5
67.2
1000
79.0
83.7
83.4
80.3
85.0
Uncertainty in Iave (mA)
The table shows data collected from another experiment. a) Calculate the Average Current with its associated uncertainty. b) Graph the data on the grid below with error bars. c) Include an error line. d) Calculate the gradient with its associated uncertainty e) Show the relationship between Frequency and Current.
Average Circuit Current, Iave
Graph of Average Circuit Current Against Frequency
100
90
80
70
60
50
40
30
20
10
0 0
200
400
600
Frequency, f (Hz)
800
1000
Five capacitors are combined in parallel. Their total capacitance is their sum, i.e. Ctotal = C1 + C2 + C3 + C4 + C5. Calculate the uncertainty in the total capacitance if their values are: (820 ± 20) x 10-9 F (220 ± 40) x 10-9 F
2.
(560 ± 10) x 10-9 F (180 ± 40) x 10-9 F
(470 ± 10) x 10-9 F
Calculate the difference, with its associated uncertainty, between the following two readings: 57.6 ± 0.2 cm and 50.0 ± 0.1 cm
3.
The wavelength of the laser light has been calculated from the gradient of a graph to be 0.0064 ± 0.0002. Use the equation λ = gradient × d to calculate the value, with its associated uncertainty, of the wavelength λ where d has the value (1.00 ± 0.01) × 10−4 m.
4. L (±1) cm
y (± 0.1) cm 1
2
3
4
x (cm) 5
Averag e 6.4 ± 0.3
250 300
7.6
7.8
7.7
7.6
7.8
350
9.0
8.8
9.1
8.9
9.2
400
10.2
10.2
10.3
10.0
10.3
450
11.4
11.6
11.4
11.6
11.5
500
12.9
12.6
12.9
12.8
12.8
The table shows data that has been collected from an experiment. Calculate the missing averages. Report figures to correct number of S.F. with associated uncertainty. Use the equation: Y = 4x + 2 to calculate x with its associated uncertainty.
5. Frequenc y,f (Hz) ± 20 Hz
Current, I (mA)
Average Current, Iave (mA)
200
15.7
15.9
17.5
16.8
17.0
400
34.1
34.5
33.0
32.7
32.0
600
49.0
48.3
48.7
52.6
48.8
800
66.4
66.9
65.5
64.5
67.2
1000
79.0
83.7
83.4
80.3
85.0
Uncertainty in Iave (mA)
The table shows data collected from another experiment. a) Calculate the Average Current with its associated uncertainty. b) Graph the data on the grid below with error bars. c) Include an error line. d) Calculate the gradient with its associated uncertainty e) Show the relationship between Frequency and Current.
Average Circuit Current, Iave
Graph of Average Circuit Current Against Frequency
100
90
80
70
60
50
40
30
20
10
0 0
200
400
600
Frequency, f (Hz)
800
1000
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