Tugas Rekayasa Gempa.docx

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Tugas Rekayasa Gempa 1. Dari Peta respons spectra di kota Manokwari, Papua Barat SS = 1.5 g, S1 = 0.5 g 2. Menentukan Kategori Desain Seismic-KDS (Seismic Design Category - SDC) untuk Manokwari. Koefisien Situs (Site Coefficient): a. Fa untuk SS = 1.5 g Kelas Situs

Ss ≥ 1.25

SB

1.0

SC

1.0

SD

1.0

SE

0.9

b. Fv untuk S1 = 0.5 g Kelas Situs

S1 ≥ 1.25

SB

1.0

SC

1.3

SD

1.5

SE

2.4

3. Menentukan Spectral Respons Percepatan (Spectral Response Acceleration) untuk Manokwari. Nilai SDS dan S1 untuk kota Manokwari Kelas Situs

SDS=2/3(Fa.Ss)

SD1=2/3(Fv.S1)

SB – Batuan

2/3(1.0)(1.5)=1g

2/3(1.0)(0.5)=0.333g

SC -Tanah keras

2/3(1.0)(1.5)=1g

2/3(1.3)(0.5)=0.433g

SD - Tanah sedang

2/3(1.0)(1.5)=1g

2/3(1.5)(0.5)=0.5g

SE - Tanah lunak

2/3(0.9)(1.5)=0.9g

2/3(2.4)(0.5)=0.8g

4. Menggambar kurva spectrum respon desain (design response spectrum) 𝑇 < 𝑇0 ≫≫ 𝑆𝑎 = 𝑆𝐷𝑆 [0.40 + (0.60

𝑇 )] 𝑇0

𝑇0 ≤ 𝑇 ≤ 𝑇𝑆 ≫≫ 𝑆𝑎 = 𝑆𝐷𝑆 𝑇 > 𝑇𝑆 ≫≫ 𝑆𝑎 = 𝑆𝐷1 /𝑇 a. SB – Batuan 𝑇0 = 0.20 𝑇𝑆 =

𝑆𝐷1 0.333 = 0.20 = 0.067 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 1

𝑆𝐷1 0.333 = = 0.333 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 1 0



𝑇 = 0 ≫ 𝑆𝑎 = 1 [0.40 + (0.60 0.067)] = 0.4 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.05 ≫ 𝑆𝑎 = 1 [0.40 + (0.60



𝑇 = 0.067 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 1 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.1 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 1 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.4 ≫ 𝑆𝑎 = 0.333/0.4 = 0.833 𝑑𝑒𝑡𝑖𝑘



𝑇 = 1 ≫ 𝑆𝑎 = 0.333/1 = 0.333 𝑑𝑒𝑡𝑖𝑘

0.05 )] 0.067

= 0.850 𝑑𝑒𝑡𝑖𝑘

SB - Batuan SA (Spektral Percepatan / g)

1.2 1 0.8 0.6 0.4

0.2 0 0

0.2

0.4

0.6

0.8

T (detik)

b. SC – Tanah Keras 𝑇0 = 0.20 𝑇𝑆 = 

𝑆𝐷1 0.433 = 0.20 = 0.087 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 1

𝑆𝐷1 0.433 = = 0.433 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 1 0

𝑇 = 0 ≫ 𝑆𝑎 = 1 [0.40 + (0.60 0.087)] = 0.4 𝑑𝑒𝑡𝑖𝑘

1

1.2

0.05



𝑇 = 0.05 ≫ 𝑆𝑎 = 1 [0.40 + (0.60 0.087)] = 0.746 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.087 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 1 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.1 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 1 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.5 ≫ 𝑆𝑎 = 0.433/0.5 = 0.866 𝑑𝑒𝑡𝑖𝑘



𝑇 = 1 ≫ 𝑆𝑎 = 0.433/1 = 0.433 𝑑𝑒𝑡𝑖𝑘

SC - Tanah Keras SA (Spektral Percepatan / g)

1.2 1 0.8 0.6 0.4 0.2 0

0

0.2

0.4

0.6

0.8

T (detik)

c. SD – Tanah Sedang 𝑇0 = 0.20 𝑇𝑆 =

𝑆𝐷1 0.5 = 0.20 = 0.1 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 1

𝑆𝐷1 0.5 = = 0.5 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 1 0



𝑇 = 0 ≫ 𝑆𝑎 = 1 [0.40 + (0.60 )] = 0.4 𝑑𝑒𝑡𝑖𝑘 0.1



𝑇 = 0.05 ≫ 𝑆𝑎 = 1 [0.40 + (0.60



𝑇 = 0.1 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 1 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.2 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 1 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.6 ≫ 𝑆𝑎 = 0.5/0.6 = 0.833 𝑑𝑒𝑡𝑖𝑘



𝑇 = 1 ≫ 𝑆𝑎 = 0.5/1 = 0.5 𝑑𝑒𝑡𝑖𝑘

0.05 )] 0.1

= 0.7 𝑑𝑒𝑡𝑖𝑘

1

1.2

SD - Tanah Sedang SA (Spektral Percepatan / g)

1.2 1 0.8 0.6 0.4 0.2 0

0

0.2

0.4

0.6

0.8

T (detik)

d. SE – Tanah Lunak 𝑇0 = 0.20 𝑇𝑆 =

𝑆𝐷1 0.8 = 0.20 = 0.178 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 0.9

𝑆𝐷1 0.8 = = 0.889 𝑑𝑒𝑡𝑖𝑘 𝑆𝐷𝑆 0.9 0



𝑇 = 0 ≫ 𝑆𝑎 = 1 [0.40 + (0.60 0.178)] = 0.36 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.05 ≫ 𝑆𝑎 = 1 [0.40 + (0.60 0.178)] = 0.512 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.178 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 0.9 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.2 ≫ 𝑆𝑎 = 𝑆𝐷𝑆 = 0.9 𝑑𝑒𝑡𝑖𝑘



𝑇 = 0.9 ≫ 𝑆𝑎 = 0.8/0.9 = 0.889 𝑑𝑒𝑡𝑖𝑘



𝑇 = 1 ≫ 𝑆𝑎 = 0.8/1 = 0.8 𝑑𝑒𝑡𝑖𝑘

0.05

1

1.2

SE - Tanah Lunak SA (Spektral Percepatan / g)

1 0.8 0.6 0.4 0.2 0

0

0.2

0.4

0.6

0.8

1

1.2

T (detik)

Kurva Spektrum Respons desain (Design Response Spectrum) SA (Spektral Percepatan / g)

1.2 1 0.8 SB

0.6

SC 0.4

SD SE

0.2 0 0

0.2

0.4

0.6

T (detik)

0.8

1

1.2

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