Tugas Muatan Terbagi Rata2.docx

MEKANIKA BAHAN Tugas muatan terbagi rata sebagiandan muatan titik

NAMA :ROCKY FAUZI NIM :(A0114006)

FAKULTAS TEKNIK JURUSAN TEKNIK SIPIL UNIVERSITAS TUNAS PEMBANGUNAN SURAKARTA

Mencari RA dan RB  Mencari RA RA = ∑MB = 0 RA . L – q . d . ½ . d – (P1 . (b+c+d) – (P2. (c+d) RA . 9,4 – 1,6 . 3,6 . ½ . 3,6 – (2,6. (1,6+2,6 +3,6) – (1,6. (2,6+3,6) RA . 9,4 – 10,368 – 20,28 – 9,92 RA . 9,4 – 40,568 𝟒𝟎,𝟓𝟔𝟖 RA = 𝟗,𝟒 RA = 4,316 T

=0 =0 =0 =0

 Mencari RB RB = ∑MA = 0 RB . L . q . d (1/2 . d + c + b + a) – ( P2 (b + a) – P1 . a RB . 9,4 . 1,6 . 3,6(1/2. 3,6+2,6+1,6 +1,6) – (1,6(1,6 + 1,6) – 2,6 .1,6 RB . 9,4 . 5,76 . 7,6 – 5,12 – 4,16 RB . 9,4 – 53,056 RB =

𝟓𝟑,𝟎𝟓𝟔 𝟗,𝟒

RB = 5,644 T

 CHECK ∑ KV = 0 (RA+RB) – ((q . d) + P1+P2) =0 4,316 + 5,644 – ((1,6 . 3,6) + 2,6 + 1,6) = 0 9,96 – 9,96 = 0 (OK)

=0 =0 =0 =0

 Mencari titik X MX = RA . x – q . x . ½ . x MX = RA . x – ½ . q . 𝒙𝟐

𝒅𝒎𝒙 𝒅𝒙

=0

RA . x – ½ . q . 𝒙𝟐 RA – ½ . q . 2x RA – q . x = 0 4,316 – 1,6 . x X=

=0 =0

=0 =0 =0

𝟒,𝟑𝟏𝟔 𝟏,𝟔

X = 2,698 m

 Mencari P P=q.d P = 1,6 . 3,6 P = 5,76 T  Mencari MX = M max MX = RA . x – ½ . q . x2 = 4,316 . 2,698 – ½ 1,6 . (2,698)2 = 11,645 – 0,8 . 7,279 = 11,645 – 5,823 = 5,823 TM

 Mencari M1 M1 = RA. a M1 = 4,316 . 1,6 M1 = 6,906 TM

 Mencari M2 M2 = RA . (a+b) – P1 . b M2 = 4,316 . ( 1,6 + 1,6 ) – 2,6 . 1,6 M2 = 13,811 – 4,16 M2 = 9,651TM  Mencari MI MI = RA ( a+b+c ) – P1 (b+c) – P2 . c MI = 4,316 (1,6+1,6+2,6) – 2,6(1,6+2,6) – 1,6 . 2,6 MI = 4,316 5,8 – 10,92 – 4,16 MI = 25,033 – 10,92 – 4,16 MI = 9,953 TM