Tugas Matlab 14s16031 Ramos

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Tugas Matlab Ramos D Hutabalian (14S16031) ELS3204 – Sistem Kendali Institut Teknologi Del

1.

PROBLEM B-7-3 a. Code 1 :

Output dari program diatas adalah sebagai berikut :

num = [1 1]; den = [2 1]; bode(num,den) title('Bode Diagram of G(s) = 1 + s/(1 + 2s)')

Ouput dari program diatas adalah :

2.

PROBLEM B-7-6

a. Code num = [0 0 1 0.5]; den = [1 1 0 1]; bode(num,den) title('Bode Diagram of G(s) = (s + 0.5/(s^3 + s^2 +1)') b. Code 2 : num = [-1 1]; den = [2 1]; bode(num,den) title('Bode Diagram of G(s) = 1 - s/(1 + 2s)')

Output dari program diatas adalah sebagai berikut :

Open - loop poles at S = -1.4656 S = 0.2328 + 𝑗0.7926 S = 0.2328 + 𝑗0.7926 The phase angle curve 0Β° 𝐺(𝑠) =

𝐺(𝑗0) =

𝑠 + 0.5 (𝑠 + 1.4656)(𝑠 βˆ’ 0.2328 βˆ’ 𝑗0.7926)(𝑠 βˆ’ 0.2328 + 𝑗0.7926)

𝑗0 + 0.5 (𝑗0 + 1.4656)(𝑗0 βˆ’ 0.2328 βˆ’ 𝑗0.7926)(𝑗0 βˆ’ 0.2328 + 𝑗0.7926)

𝐺(𝑗0) =

𝑗0 + 0.5 (𝑗0 + 1.4656)(βˆ’0.2328 βˆ’ 𝑗0.7926)(βˆ’0.2328 + 𝑗0.7926)

∠𝐺(𝑗0) = tanβˆ’1 0 βˆ’ tan βˆ’1 0 βˆ’ tan βˆ’1

βˆ’0.7926 0.7926 + tan βˆ’1 βˆ’0.2328 βˆ’0.2328

∠𝐺(𝑗0) = 0Β° βˆ’ 0Β° βˆ’ 0Β° + 0Β° = 0Β° The phase angle curve 180Β° 𝐺(π‘—βˆž =

π‘—βˆž + 0.5 (π‘—βˆž + 1.4656)(π‘—βˆž βˆ’ 0.2328 βˆ’ 𝑗0.7926)(π‘—βˆž βˆ’ 0.2328 + 𝑗0.7926)

∞ ∞ βˆ’ tanβˆ’1 βˆ’0.2328 βˆ’.2328 ∠𝐺(π‘—βˆž) = 90Β° βˆ’ 90Β° + 90Β° + 90Β° = 180Β°

∠𝐺(π‘—βˆž) = tanβˆ’1 ∞ βˆ’ tan βˆ’1 ∞ βˆ’ tan βˆ’1

3.

PRBOLEM B-7-27

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