Tugas Kekakuan Pegas.docx

Tugas Getaran Kapal Kekakuan Pegas Nama : Rio Hendrawan Suparno Putra (1510313001)

Diketahui : E = 2,04 x 1011 N/m2 untuk semua soal

b.h³

2 cm

1) a. 4 cm

K= 3 cm

b.

b.h³

I = 12 = K=

3 cm

c.

I= Ø = 4 cm

2) a.

𝐸.𝐼 𝑙

𝜋.𝑟 4

K=

4 𝐸.𝐼 𝑙

=

=

1,5

= 3,63 . 103 Nm

= 6,75 cm4 = 6,75 . 10-8 m4

12 2,04 . 1011 . 6,75 . 10-8

3,14 .24

= 9,18 . 103 Nm

= 12,56 cm4 = 12,56 . 10-8 m4

4 2,04 . 1011 . 12,56 . 10-8 1,5

= 17,08 . 103 Nm

A = p x l = 4 x 2 = 8 cm2 = 8 . 10-4 m2 K=

𝐸.𝐴 𝑙

=

2,04 . 1011 . 8 . 10-4 1

= 16,32 . 107 Nm

A = s x s = 3 x 3 = 9 cm2 = 9 . 10-4 m2 K=

3 cm

𝑙

= 2,67 cm4 = 2,67 . 10-8 m4

12 2,04 . 1011 . 2,67 . 10-8

1,5

=

4 cm

3 cm

𝐸.𝐼

3.3³

=

2 cm

b.

4.2³

I = 12 =

𝐸.𝐴 𝑙

=

2,04 . 1011 . 9 . 10-4 1

= 18,36 . 107 Nm

A = π x r2 = 3,14 x 22 = 12,56 cm2 = 12,56 . 10-4 m2

c. Ø = 4 cm

K=

𝐸.𝐴 𝑙

=

2 cm

3) a.

2,04 . 1011 . 12,56 . 10-4 1

K=

3.𝐸.𝐼 𝑙3

=

= 25,62 . 107 Nm

3 . 2,04 . 1011 . 2,67 . 10-8 (1,5)3

= 4,84 . 103 Nm

4 cm

b.

3 cm

K=

3.𝐸.𝐼 𝑙3

=

3 . 2,04 . 1011 . 6,75 . 10-8 (1,5)3

= 12,24 . 103 Nm

3 cm

c.

K= Ø = 4 cm

3.𝐸.𝐼 𝑙3

=

3 . 2,04 . 1011 . 12,56 . 10-8 (1,5)3

= 22,78 . 103 Nm