Tugas 1 (1835974) Mekanika Fluida.docx

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NAMA NPM MK

TUGAS 1 (1835974) 1. a. b. c. d. e. f.

60 mil/jam 35 lb/in² 2 gram/cm³ 22 slug/jam 20 ft³/menit 50 kWh

= 60 x 1.609,34 m/3600 s = 35 x 6.984,76 Pa = (2x1/1000 kg)/(1/10x105 m3) = 22 x 14,594 kg/ 3600 s = 20 x 0,0283 m3/ 60 s = 50 x 3,6x106 J

= 26,8224 m/s = 241.317 Pa = 2.000 kg/m³ = 0,089185 kg/s = 0,00943895 m³/s = 180x106 J

2. Diketahui : a = 3 m/s2 m = 1,5 ton = 1500 kg Ditanyakan : a. F pada Jalan datar ? b. F pada Jalan naik 20° ? Jawab : a. F = m x a = 1.500 kg x 3 m/s2 = 4.500 N b. F = m x a x cos ɵ = 1.500 kg x 3 m/s2 x cos 20° = 4.500 kg.m/s2 x 0,94 = 4.230 kg.m/s2 = 4.230 N 3. Diketahui : Berat = 850 N (g = 9,81 m/s²) Gravitasi planet lain = 5,4 ft/s² = 1,64592 m/s² Ditanyakan : Berat di planet lain? Jawab : 850 N x 1,64592 m/s² = 142,6 N 9,81 m/s² 4. a. 20° = …. Kelvin ? = 5/5 x (20° - 0°) + 273° b. 20° = …. Fahrenheit ? = 9/5 x (20° - 0°) + 32° c. 20° = …. Rankine ? = 9/5 x (20° - 0°) + 492°

= 293° Kelvin = 68° Fahrenheit = 528° Rankine

5. Diketahui : Tekanan benda = 28 Kpa Ketinggian = 2000 m Ditanyakan : Tekanan Absolut ? Jawab : a. P abs = P atm + P gage = 79,5 Kpa + 28 Kpa = 107,5 Kpa b. 107,5 Kpa x 1,013 bar = 1,075 bar 101,3 Kpa 1 bar = 14,5038 lb/in² Maka 1,075 bar = 15,59155 lb/in² c. 107,5 Kpa x 76 cmHg = 80,65 cmHg 101,3 Kpa d. 107,5 Kpa x 34 ft H2O = 36,08 ft H2O 101,3 Kpa

: : :

HANA YUDIANA 17070037 MEKANIKA FLUIDA

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