Tubesku 1.docx
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1. TEORI
A. Jelaskan perbedaan struktur statis tentu dan struktur statis tak tentu? B. Jelaskan metode distribusi momen? C. Faktor-faktor apa saja yang dibutuhkan dalam analisis metode Cross?
2.
Carilah Distribution Factor (DF) masing-masing batang!
C
Sendi : SF = 3EI/L Jepit : SF = 4EI/L
A D B
E
Kekakuan Batang : KBA = KBC =
3EI LAB 4EI LBC
= =
3(2EI) 3 4(2EI) 3
=2
KBD =
= 2,667
KBE =
4EI LBD 4EI LBE
= =
4(EI)
= 1,333
3 4(3EI) 6
=2
Faktor Distribusi: F.DBA =
F.DBC =
FDBA FDBA + FDBC + FDBD + FDBE FDBC FDBA + FDBC + FDBD + FDBE
= =
2 2 + 2,667 + 1,333 + 2 2,667 2 + 2,667 + 1,333 + 2
= 0,25 = 0,334
F.DBE =
F.DBC =
FDBE FDBA + FDBC + FDBD + FDBE FDBC FDBA + FDBC + FDBD + FDBE
= =
1,333 2 + 2,667 + 1,333 + 2 2 2 + 2,667 + 1,333 + 2
= 0,666 = 0,25
A. Jelaskan perbedaan struktur statis tentu dan struktur statis tak tentu? B. Jelaskan metode distribusi momen? C. Faktor-faktor apa saja yang dibutuhkan dalam analisis metode Cross?
2.
Carilah Distribution Factor (DF) masing-masing batang!
C
Sendi : SF = 3EI/L Jepit : SF = 4EI/L
A D B
E
Kekakuan Batang : KBA = KBC =
3EI LAB 4EI LBC
= =
3(2EI) 3 4(2EI) 3
=2
KBD =
= 2,667
KBE =
4EI LBD 4EI LBE
= =
4(EI)
= 1,333
3 4(3EI) 6
=2
Faktor Distribusi: F.DBA =
F.DBC =
FDBA FDBA + FDBC + FDBD + FDBE FDBC FDBA + FDBC + FDBD + FDBE
= =
2 2 + 2,667 + 1,333 + 2 2,667 2 + 2,667 + 1,333 + 2
= 0,25 = 0,334
F.DBE =
F.DBC =
FDBE FDBA + FDBC + FDBD + FDBE FDBC FDBA + FDBC + FDBD + FDBE
= =
1,333 2 + 2,667 + 1,333 + 2 2 2 + 2,667 + 1,333 + 2
= 0,666 = 0,25
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