GROUP 5
Student 1 Chau Ping 2 Szeto Kwok Fai 3 Moy Yee Ping
Student ID S98038000 S98037010 S98037350
Trigonometric Ratios
Contents Introduction to Trigonometric Ratios Unit Circle Adjacent , opposite side and hypotenuse of a right angle triangle. Three types trigonometric ratios Conclusion
Introduction Trigonometric Ratios
Trigonometry ( 三角幾 何 ) means “Triangle” and “Measurement” In F.2 we concentrated on right angle triangles. triangles
Unit Circle A Unit Circle Is a Circle With Radius Equals to 1 Unit.(We Always Choose Origin As Its centre)
Y 1 units
x
Adjacent , Opposite Side and Hypotenuse of a Right Angle Triangle.
se nu te
po hy
Opposite side
θ Adjacent side
φ
se nu te
po hy
Adjacent side
Opposite side
Three Types Trigonometric Ratios There are 3 kinds of trigonometric ratios we will learn. ✡
sine ratio
✡
cosine ratio
✡
tangent ratio
Sine Ratios Definition of Sine Ratio. Application of Sine Ratio.
Definition of Sine Ratio.
1
θ If the hypotenuse equals to 1 Sinθ = Opposite sides
Definition of Sine Ratio.
θ For any right-angled triangle Sinθ =
Opposite side hypotenuses
Exercise 1
In the figure, find sin θ
Sinθ =
= θ=
Opposite Side hypotenuses 4 7 34.85° (corr to 2 d.p.)
θ 4 7
Exercise 2 In the figure, find y
Sin35° =
Sin35° =
y
Opposite Side hypotenuses y 11
y=
11 sin35°
y=
6.31 (corr to 2.d.p.)
35°
11
Cosine Ratios Definition of Cosine. Relation of Cosine to the sides of right angle triangle.
Definition of Cosine Ratio.
1
θ If the hypotenuse equals to 1 Cosθ =
Adjacent Side
Definition of Cosine Ratio.
θ For any right-angled triangle Cosθ =
Adjacent Side hypotenuses
Exercise 3
In the figure, find cos θ
cosθ =
= θ=
adjacent Side hypotenuses 3 8 67.98° (corr to 2 d.p.)
3
θ 8
Exercise 4 In the figure, find x
Cos 42° =
Cos 42° = x= x=
6
Adjacent Side
42°
hypotenuses 6 x 6 Cos 42° 8.07 (corr to 2.d.p.)
x
Tangent Ratios Definition of Tangent. Relation of Tangent to the sides of right angle triangle.
Definition of Tangent Ratio.
θ For any right-angled triangle tanθ =
Opposite Side Adjacent Side
Exercise 5 3 In the figure, find tan θ
tanθ =
= θ=
Opposite side adjacent Side 3 5 78.69° (corr to 2 d.p.)
5
θ
Exercise 6 In the figure, find z
tan 22° =
tan 22° = z= z=
z
Opposite side adjacent Side 5 z 5 tan 22° 12.38 (corr to 2 d.p.)
5
22°
Conclusion opposite side sin θ = hypotenuse adjacent side cos θ = hypotenuse opposite side tan θ = adjacent side
Make Sure that the triangle is right-angled
END