Thinkfree-997447135.fluidos.docx

1,70) m = 450 g W=? W = mg W = 0,45 kg (9,8 m/s2) W = 4,41 N

1,84) γ = 130,4 KN/m3 W = 2,25 KN V=¿ 𝑣=

𝑤 γ

𝑣=

2,25 KN 130,4 KN/m3

𝑣 = 0,0173 𝑚3

1,85) Ø =150 mm h = 10 mm m =1,56 Kg ρ=¿ γ=¿ Gs = ¿ 

V = Ah V = π (0,15 m)2 (0,25) (0,1 m) V = 1,767 x10-3 m3



ρ=

𝑚 𝑣

ρ=

(1,56 𝐾𝑔) 1,767 x10−3 m3

ρ=

(1,56 𝐾𝑔) 1,767 x10−3 m3

ρ = 882,85 Kg/m3



γ = ρg γ = 882,85 Kg/m3 (9,8 m/s2) γ = 8651,93 N/m3



Gs =

γ fluido γ agua

882,85 Kg/m3 Gs = 9810 Kg/m3 Gs = 0,88

3,37) h = 12,5 ft → 3,82 m P=? P = γh P = 9810 N/m3 (3,82 m) P = 37474,2 Pa

3,38) h = 50 ft → 15,24 m P=?

P = γh P = 9810 N/m3 (15,24 m) P = 149504,4 Pa

3,44) h = 28,5 ft → 8,69 m Gs = 0,95 P=? 

Gs =

γ fluido γ agua

0,95 =

γ fluido 9810 Kg/m3

γ fluido = 9319,5 N/m3 

P =γh P = 9319,5 N/m3 (8,69 m) P = 80986,46 Pa

3,50) h2 = ? hT = 18m Gs = 0,86 P = 158 Pa 

Gs =

γ aceite γ agua

0,86 =

γ fluido 9810 Kg/m3

γ aceite = 8436,6 N/m3 

P = Paceite + Pagua

P = 8436,6 N/m3 (18 m - h2) + 9810 N/m3 (h2) 158000 Pa = 151858,8 Pa - 8436,6 N/m3 (h2) + 9810 N/m3 (h2) 6141,2 Pa = 1373,4 N/m3 (h2) h2 = 4,47 m

3,63) Gsaceite = 0,85 32 in → 0,8128 m 10 in → 0,254 m 9 in → 0,2286 m PA – PB = ? PA + P1 + P2 – P3 = PB PA – PB = –P1 – P2 + P3 PA – PB = –(9810 N/m3)( 0,85)(0,3302 m) – (9810 N/m3) (0,2286 m) + (9810 N/m3)( 0,85)(0, 8128 m) PA – PB = 1781,6 Pa

3,63) Gsaceite = 0,9 Gsmercurio = 13,54 PA = ? PA + P1 – P2 + P3 – P4 = 0 PA = – P1 + P2 – P3 + P4 PA = – (9810 N/m3)(0,9)(0,375 m) + (9810 N/m3)(13,54)(0,25 m) – (9810 N/m3)(0,3 m) + (9810 N/m3)(13,54)(0,475 m) PA = 90045,99 Pa