Tgs 1 Statistik.docx
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1. Diketahui data hasil penelitian sebagai berikut. 10
10
10
10
11
11
12
12
12
13
14
14
14
14
15
15
15
16
16
17
17
18
18
18
18
18
18
19
19
20
20
20
21
21
23
24
25
25
26
26
2. Rentang Rumus
= Xmax – Xmin = 26 – 10 = 16
3. Banyak Kelas Rumus
= 1+ 3,3 logn = 1 + 3,3 log 40 = 1 + 5,3 = 6,3 = 6
4. Panjang Kelas Rumus
=P =P
𝑟𝑒𝑛𝑡𝑎𝑛𝑔 𝐾 16 6
= 2,66 = 3
5. Tabel Distribusi Frekuensi Nilai
Frekuensi
10 – 12
9
13 – 15
8
16 – 18
10
19 – 21
7
22 – 24
2
25 – 27
4
Total
40
Frekuensi Relatif
6. Median a. Data Tunggal 𝑋̅ = 2665 𝑋̅ = 40
𝑋̅ = 63,9 b. Data Kelompok Rumus
= 𝑋̅ =
Ket
= ti = titik tengah fi = frekuensi kelas ke i
No
Nilai
Frekuensi (fi)
Midpoint (ti)
Frek. Midpoint (fixti)
1
10 – 12
9
11
99
2
13 – 15
8
14
112
3
16 – 18
10
17
170
4
19 – 21
7
20
140
5
22 – 24
2
23
46
6
25 – 27
4
26
104
40
Jadi,
𝑋̅
= =
671 40
= 16,7
671
7. Modus a. Data Tunggal Data yang sering muncul. 10, 11, 12,..........................25, 26 Yabg sering muncul = 18 b. Data Kelompok Rumus
=
Ket
= Mo = Modus Bb = batas bawah Mo yang mengandung nilai Mo P = panjang kelas F1 = nilai frek. Mo – frek. Sebelum kelas Mo F2 = nilai frek. Mo – frek. Setelah kelas Mo
Mo
No
Nilai
Frekuensi
Tepi kelas
1
10 – 12
9
9,5
2
13 – 15
8
12,5
3
16 – 18
10
15,5
4
19 – 21
7
18,5
5
22 – 24
2
21,5
6
25 – 27
4
24,5
𝐹1
= Bb + p (𝐹1+𝐹2) 2
= 15,5 + 3 (2+3) = 18,5 . 0,4 = 16,7
8. Median a. Data Tunggal Median
= = =
𝑛+1 2 40+1 2
= 20 data no 20 & 21
17+18
= 17,5
2
b. Data Kelompok Rumus
= Bb + p (
Ket
= Bb =
𝑛−𝑗𝑓 𝐹
)
P = panjang kelas n= f= jf =
Me
No
Nilai
Frekuensi
Tepi kelas
1
10 – 12
9
9,5
2
13 – 15
8
12,5
3
16 – 18
10
15,5
4
19 – 21
7
18,5
5
22 – 24
2
21,5
6
25 – 27
4
24,5
= Bb + p ( = 15,5 + 3 ( = 16,4
𝑛−𝑗𝑓 𝐹
) .40−17
10
)
9. Diagram
10
10
10
11
11
12
12
12
13
14
14
14
14
15
15
15
16
16
17
17
18
18
18
18
18
18
19
19
20
20
20
21
21
23
24
25
25
26
26
2. Rentang Rumus
= Xmax – Xmin = 26 – 10 = 16
3. Banyak Kelas Rumus
= 1+ 3,3 logn = 1 + 3,3 log 40 = 1 + 5,3 = 6,3 = 6
4. Panjang Kelas Rumus
=P =P
𝑟𝑒𝑛𝑡𝑎𝑛𝑔 𝐾 16 6
= 2,66 = 3
5. Tabel Distribusi Frekuensi Nilai
Frekuensi
10 – 12
9
13 – 15
8
16 – 18
10
19 – 21
7
22 – 24
2
25 – 27
4
Total
40
Frekuensi Relatif
6. Median a. Data Tunggal 𝑋̅ = 2665 𝑋̅ = 40
𝑋̅ = 63,9 b. Data Kelompok Rumus
= 𝑋̅ =
Ket
= ti = titik tengah fi = frekuensi kelas ke i
No
Nilai
Frekuensi (fi)
Midpoint (ti)
Frek. Midpoint (fixti)
1
10 – 12
9
11
99
2
13 – 15
8
14
112
3
16 – 18
10
17
170
4
19 – 21
7
20
140
5
22 – 24
2
23
46
6
25 – 27
4
26
104
40
Jadi,
𝑋̅
= =
671 40
= 16,7
671
7. Modus a. Data Tunggal Data yang sering muncul. 10, 11, 12,..........................25, 26 Yabg sering muncul = 18 b. Data Kelompok Rumus
=
Ket
= Mo = Modus Bb = batas bawah Mo yang mengandung nilai Mo P = panjang kelas F1 = nilai frek. Mo – frek. Sebelum kelas Mo F2 = nilai frek. Mo – frek. Setelah kelas Mo
Mo
No
Nilai
Frekuensi
Tepi kelas
1
10 – 12
9
9,5
2
13 – 15
8
12,5
3
16 – 18
10
15,5
4
19 – 21
7
18,5
5
22 – 24
2
21,5
6
25 – 27
4
24,5
𝐹1
= Bb + p (𝐹1+𝐹2) 2
= 15,5 + 3 (2+3) = 18,5 . 0,4 = 16,7
8. Median a. Data Tunggal Median
= = =
𝑛+1 2 40+1 2
= 20 data no 20 & 21
17+18
= 17,5
2
b. Data Kelompok Rumus
= Bb + p (
Ket
= Bb =
𝑛−𝑗𝑓 𝐹
)
P = panjang kelas n= f= jf =
Me
No
Nilai
Frekuensi
Tepi kelas
1
10 – 12
9
9,5
2
13 – 15
8
12,5
3
16 – 18
10
15,5
4
19 – 21
7
18,5
5
22 – 24
2
21,5
6
25 – 27
4
24,5
= Bb + p ( = 15,5 + 3 ( = 16,4
𝑛−𝑗𝑓 𝐹
) .40−17
10
)
9. Diagram
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