Tgs 1 Statistik.docx

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1. Diketahui data hasil penelitian sebagai berikut. 10

10

10

10

11

11

12

12

12

13

14

14

14

14

15

15

15

16

16

17

17

18

18

18

18

18

18

19

19

20

20

20

21

21

23

24

25

25

26

26

2. Rentang Rumus

= Xmax – Xmin = 26 – 10 = 16

3. Banyak Kelas Rumus

= 1+ 3,3 logn = 1 + 3,3 log 40 = 1 + 5,3 = 6,3 = 6

4. Panjang Kelas Rumus

=P =P

𝑟𝑒𝑛𝑡𝑎𝑛𝑔 𝐾 16 6

= 2,66 = 3

5. Tabel Distribusi Frekuensi Nilai

Frekuensi

10 – 12

9

13 – 15

8

16 – 18

10

19 – 21

7

22 – 24

2

25 – 27

4

Total

40

Frekuensi Relatif

6. Median a. Data Tunggal 𝑋̅ = 2665 𝑋̅ = 40

𝑋̅ = 63,9 b. Data Kelompok Rumus

= 𝑋̅ =

Ket

= ti = titik tengah fi = frekuensi kelas ke i

No

Nilai

Frekuensi (fi)

Midpoint (ti)

Frek. Midpoint (fixti)

1

10 – 12

9

11

99

2

13 – 15

8

14

112

3

16 – 18

10

17

170

4

19 – 21

7

20

140

5

22 – 24

2

23

46

6

25 – 27

4

26

104

40

Jadi,

𝑋̅

= =

671 40

= 16,7

671

7. Modus a. Data Tunggal Data yang sering muncul. 10, 11, 12,..........................25, 26 Yabg sering muncul = 18 b. Data Kelompok Rumus

=

Ket

= Mo = Modus Bb = batas bawah Mo yang mengandung nilai Mo P = panjang kelas F1 = nilai frek. Mo – frek. Sebelum kelas Mo F2 = nilai frek. Mo – frek. Setelah kelas Mo

Mo

No

Nilai

Frekuensi

Tepi kelas

1

10 – 12

9

9,5

2

13 – 15

8

12,5

3

16 – 18

10

15,5

4

19 – 21

7

18,5

5

22 – 24

2

21,5

6

25 – 27

4

24,5

𝐹1

= Bb + p (𝐹1+𝐹2) 2

= 15,5 + 3 (2+3) = 18,5 . 0,4 = 16,7

8. Median a. Data Tunggal Median

= = =

𝑛+1 2 40+1 2

= 20 data no 20 & 21

17+18

= 17,5

2

b. Data Kelompok Rumus

= Bb + p (

Ket

= Bb =

𝑛−𝑗𝑓 𝐹

)

P = panjang kelas n= f= jf =

Me

No

Nilai

Frekuensi

Tepi kelas

1

10 – 12

9

9,5

2

13 – 15

8

12,5

3

16 – 18

10

15,5

4

19 – 21

7

18,5

5

22 – 24

2

21,5

6

25 – 27

4

24,5

= Bb + p ( = 15,5 + 3 ( = 16,4

𝑛−𝑗𝑓 𝐹

) .40−17

10

)

9. Diagram

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