Taller 9 Y 10

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TALLER No. 9

1 C ( x) = 10 + 2 x C ( x) = 2

2 C(x) = 40 + (In2)x 2

( 2)

C(x) = 0 + (In2)(2x) + x 2 1 x2 2 12 C(x) = 2(1) In2 + 2 1 C(x) = 2In2 + 2 C(x) = 2In2 + 0,5 C(x) = 2xIn2 +

C(x) = 1,38 + 0.5 C(x) = 1,88

3 C ( x ) = 0.0001x 3 − 0.09 x 2 + 20 x + 1200 C ( x ) = 0.0001x 3 − 0.09 x 2 + 20 x + 1200 C ( x ) = 0.0003 x 2 − 0.18 x + 20 C ( x ) = 0.0003(1) − 0.18(1) + 20 C ( x ) = 0.0003(1) − 0.18 + 20 C ( x ) = 0.0003 − 0.18 + 20 C ( x ) = 19.82 2

4 C ( x ) = 10 −6 x 3 − (3 *10 −3 ) x 2 + 36 x + 2000

C ( x ) = 10 −6 (3 x 2 ) − (3 * 10 −3 ) x 2 + 36 x + 2000 C ( x ) = 30 x −4 − 30 −3 ( 2 x ) + x 2 ( 0 ) + 36 C ( x ) = 30 x −4 − 60 x −2 + 36 C ( x ) = 30(1)

−4

− 60(1)

−2

+ 36

C ( x ) = 30 −4 − 60 −2 + 36 C ( x ) = 0.0000012 − 0.00027 + 36 C ( x ) = −0.0002765 + 36 C ( x ) = 35.49

5 R ( x ) = x − 0.01x 2 R ( x ) = 1 − 0.02 x

R ( x ) = 1 − 0.02(1) R ( x ) = 0.98

6 R ( x) = 5 x − 0.01x 5 2 0.05 3 2 x 2 0.05 3 2 R( x) = 5 − (1) 2 R( x) = 5 −

R( x) = 5 −

0.05 2

3

R ( x ) = 5 − 0.025

2

3

2

= 5 − 0.0039

R ( x ) = 4.9961

7

R ( x ) = 0.1x − 10 −3 x 2 − 10 −3 x

[

5

2

]

7 5 R ( x ) = 0.1 − 10 −3 ( 2 x ) + x 2 ( 0 ) − 10 −3  5 x 2  + x 2 ( 0 )     2  7 R ( x ) = 0.1 − 20 x −2 + 0 − 25 x 2 + 0  

[

]

R ( x ) = 0.1 − 20 x −2 − 25 x R ( x ) = 0.1 − 20(1)

7

2

− 25(1)

−2

7

2

7

R ( x ) = 0.1 − 20 −2 − 25 2 R ( x ) = 0.1 − 0.0025 − 0.0000128 R ( x ) = 0.097

(

8 R ( x ) = 100 x − ( Log5) x 3 1 + x

)

R ( x ) = 100 x − 0,69 x 3  1 + x 2     1 1 2 R ( x ) = 100 − 0,69 x 3  0 + 1 2 x 2   + 1 + x 2   2,07 x     1

(

)

R ( x ) = 100 − 0,345 x

5

R ( x ) = 100 − 0,345(1) 5

2 5

(

+ 2,07 x 2 + 2,07 x 2

Q P

D

X = 100 − 4 p I = p.Q

I = p (100 − 4 P ) I = 100 p − 4 p 2 I = 100 − 8 p I = 100 − 8(1) I = 100 − 8 I = 92

2

+ 2,07(1) + 2,07(1) 2

R ( x ) = 100 − 0,345 2 + 2,07 2 + 2,07 R ( x ) = 100 − 0,69 + 4,28 + 6,16 R ( x ) = 110,651

9 x + 4 p = 100

5

5

2

5

2

)

10 Q

x + p = 10 P D x = 10 − p

x

1

2

= 10 − p

x = (10 − p ) I = p.Q

2

[ ] I = p[2(10 − p ) + (10 − p ) (1) ] I = p (10 − p )

2

2

I = p ( 20 p − 2 p ) + (10 − p ) I = 20(1) − 2(1) + (10 − 1) 2

2

2

I = 20 − 2 2 + 9 2 I = 20 − 4 + 81 I = 97

11

x

3

2

+ 50 p = 1000

I = 16 x

3

I = 16 x

3

I = 16 x

3

I = 16(1) 3

2

= 1000(16 ) − 50(16) p

2

= 16000 − 800 p

2

− 16000 − 800 p

3

2

− 16000 − 800 p

I = 16 − 16000 − 800 p I = 64 − 16000 − 800 p I = 15936 + 800 p 2

12 10 p + x + 0.01x 2 = 700 x + 0.01x 2 = 700 − 10 p I = x + 0.01x 2 = 700 − 10 p I = 10 x + 0.1x 2 − 7000 + 100 p I = 10(1) + 0.1(1) − 7000 + 100 p I = 10 + 0.1 − 7000 + 100 p I = 10.1 − 7000 + 100 p 2

I = −6989.9 + 100 p

13 U = I − P

U = 100 P − 4 P 2 − (100 + 5 x ) U = 100 P − 4 P 2 − 100 − 5 x U = 100 − 8 P − 5 U = 95 − 8 P

14 U = I − C

( ) U = P (10 − P ) − 60 − X U = (10 P − P ) − 60 − X U = 2(10 P − P )(10 − 2 P ) − 1 U = P 10 − P 2 − ( 60 + x ) 2

2 2 2

U = 20 P − 2 P (10 − 2 P ) − 1 2

15 U = I − C U = 16 x

3

U = 16 x

3

U = 15 x

3

2

3 − 1600 + 800 P −   50 + x 2    

2

− 1600 + 800 P − 50 − x

2

− 1950 + 800 P

3

2

(15 x ) 2 + 800 2 1 U = 45 x 2 + 800 2 1 U = 45 ( 25 ) 2 + 800 2 U = 823 .7 U =3

1

16 U = I − C

U = 10 x + 0.1x 2 − 7000 + 100 p − (1000 + 0.1x 2 ) U = 10 x + 0.1x 2 − 7000 + 100 p − 1000 − 0.1x 2 U = 10 x − 8000 + 100 p

A U U U U

B = 10 x − 8000 + 100 p = 10 (100 ) − 8000 + 100 p = 1000 − 8000 + 100 p = 7000 + 100 p

U U U U

= 10 x − 8000 + 100 p = 10 x − 8000 + 100 (10 ) = 10 x − 8000 + 1000 = 10 x − 7000

17 F (u ) = 95 − 8 p

F (u ) = 95 − 8( 0 ) F (u ) = 95

0 = 95 − 8 p p = 95 − 8 p = 87

18 F (u ) = 20 p − 2 p 2 (10 − 2 p ) − 1

F (u ) = 20( 0 ) − 2( 0 ) (10 − 2( 0 ) ) − 1 F (u ) = 0 − 2( 0) (10 − ( 0 ) ) − 1 2

F (u ) = 10 − 1 F (u ) = 9

0 = 20 p − 2 p 2 (10 − 2 p ) −1 0 = 20 p − 20 p 2 + 4 p 3 −1 0 = 20 p − 20 p 2 + 3 4 p 3 −1 0 = 20 p − 20 p + 4 p −1 0 = 4 p −1 p = 4 −1 = 3

19 p1 = 4 Q1 = 100 p 2 = 5 Q 2 = 80 p 2 − p1 Q 2 − Q1 5−4 m= 80 − 100 1 m= − 20 m = 0.005 m=

p − p1 = m( Q − Q1)

p − 4 = 0.05( Q − 100 ) p − 4 = 0.05Q + 5 p = 0.05Q + 5 + 4 p − 0.005Q − 4 = 5 p − 0.05Q = 9 0.05Q = 9 − p 9− p Q= 0.05

I = P.Q 9 − P  I = P   0.05  9P − P 2 I = 0.05 0.05( 9 − 2 P ) − 9 P − P 2 ( 0 ) I = 0.05 2 0.05( 9 − 2 P ) − 0 I = 0.025 0.45 − 0.1 I = 0.025 0.45 − 0.1 I = 0.025 0.35 P= 0.0025 P = 140

20

P1 = 1 P 2 = 1.50 Q1 = 20000 Q 2 = 45000 1.50 −1 M = 15000 − 20000 0.50 M = = 0.0001 − 5000 P − P1 = M ( Q − Q1) P −1 = 0.0001( Q − 2000 ) P −1 = 0.0001Q + 2 P = 0.0001Q + 3 P + 0.0001Q = 3  3−P  0 = 1 P  0.0001 

3P − P 2 0.0001 0.0001( 3 − 2 P ) − 3P − P 2 ( 0 ) 0= 0.00001 2 0.003 − 0.0002 P 0= 0.0000001 U = I − [CF + ( CV .Q ) ] 3P − 2 P U = − [10000 + ( 0.80Q ) ] 0.0001 3P − 2 P U = −10000 − 0.80Q 0.0001 0.0003 − 0.002 P U = − 0.80Q 0.0000001 0.0003 − 0.002 P 0= − 0.80Q 0.0000001 0.0003 − 0.0002 P= − 0.80Q 0.0000001 P = 10000 − 0.80 0=

P = 9999..2

A U U U U U

B 3P − P 2 = −10000 − 0.80Q 0.0001 3(1.80 ) − 1.80 2 = − 10000 − 0.80Q 0.0001 5.4 − 3.24 = −10000 − 0.80Q 0.0001 2.16 = − 10000 − 0.80Q 0.0001 = 11600 − 0.80Q

21 C ( x ) = AX

2

C ( x ) = 2 AX

U U U U U

C 3P − P 2 = − 10000 − 0.80 Q 0.0001 3(1.90 ) − 1.90 2 = − 10000 − 0.80 Q 0.0001 5.7 − 3.61 = − 10000 − 0.80 Q 0.0001 2.09 = − 10000 − 0.80 Q 0.0001 = 10900 − 0.80 Q

+ BX + C 2

+B

+ BX + C X AX 2 BX C C’ ( x ) = + + X X X C C’ ( x ) = AX + B + X AX C’ ( x ) =

AX

2

AX + B + C X 2 AX 2 + 2 AXB + 2 AXC + AXB + B 2 + BC C’ ( x ) = X 2 ZX + 2 ZXC + ZXB + B 2 + BC C’ ( x ) = X C’ ( x ) =

22 NO ES VERDAD PORQUE NO TODS LAS VARIABLES QU ESTAN ELEVADAS ESTAN MULTIPLICANDO A LA X

23

C ( F ) = 4 + 0.36 I + 0.48 I 1.44 2 4 C ( F = 0.36 ) + I 4 ∆S + ∆C = ∆I

3

4

∆S = ∆I − ∆C ∆S = 16 − 4 + 0.36 I + 0.48 I ∆S = 16 − 4 = 12 ∆S = 16 − 0.36 = 15.64 ∆S = 16 − 0.15 = 15.52 ∆S = 12 − 15.64 I − 15.52 I ∆S = 15.64 +

46.56 4

3

4

3

4

3P − P 2 − 10000 − 0.80 Q 0.0001 3( 2 ) − 2 2 = − 10000 − 0.80 Q 0.0001 6−4 = − 10000 − 0.80 Q 0.0001 2 = − 10000 − 0.80 Q 0.0001 = 10000 − 0.80 Q

U = U U U U

TALLER No. 10

1

 p  dx   e =      x  dp     p  dx    e =    x p  dp   

p 2  0( 0 ) − ( k )(1)    x  P2  2 p 0−k    e= 2  x   p  e=

 x   p2  − xp 2 e= xp 2 e = −1 e=

p2 x

   

2 A x x x x

= 500(10 − p ) = 500(10 − 2 ) = 500( 8) = 4000

 2  e = [500(10 − p ) ]  4000   2  e = [500( − 1) − (10 − p )( 0) ]  4000   2   2  e = ( − 500 + 0) =  ( − 500 )  4000   4000  − 1000 e= 4000 e = −0.25

B x x x x

= 500 (10 − p ) = 500 (10 − 5) = 500 ( 5) = 2500

 5  e = [ 500 (10 − p ) ]  2500   5  e = [ 500 ( − 1) − (10 − p )( 0 ) ]  2500   5   5  e = ( − 500 + 0 ) =  ( − 500 )  2500   2500  − 2500 e= 2500 e = −1

C

x = 500 (10 − p ) x = 500 (10 − 6 ) x = 500 ( 4 ) x = 2000

 5 e =  2000  5 e =  2000

 [ 500 (10 − p ) ] 

 [ 500 ( − 1) − (10 − p )( 0 ) ]   5   5  e = ( − 500 + 0 ) =  ( − 500 ) 2000    2000  − 30000 e= 2000 e = −1.5

3 A x = 400 − 100 p

x = 400 − 100 (1) x = 400 − 100 x = 300  p  dx   e =      x  dp   1  e = ( 400 − 100 p )  300   1  e = ( − 100 )  300  − 100 e= 300 e = −0.33

B x x x x

= 400 − 100 p = 400 − 100( 2 ) = 400 − 200 = 200

 2  e = ( − 100 )  200  − 200 e= 200 e = −1

C x x x x

= 400 − 100 p = 400 − 100( 3) = 400 − 300 = 100

 3  e =  = −100  100  − 300 e= 100 e = −3

4 A x p + =1 1000 8 x 2 + =1 1000 8 x + 0.25 = 1 1000 x = 1 − 0.25 1000 x = 0.75(1000 ) x = 750 p  2   p ( 0 ) − 8(1)  e = 1 − ( 0 ) − 1000  8 82  750     2   8  e = 0 + 1000   750   64  8   2  e = 1000 −  64   750   2  63992  e =    750  64   2  e = ( 999875)  750  1999.75 e= 750 e = 2.66

B x 4 + =1 1000 8 x + 0.5 = 1 1000 x = 1 − 0 .5 1000 x = 0.5(1000 ) x = 500  4  e = ( 999875)  500  3999.5 e= 500 e = 7.9

C x 4 + =1 1000 8 x + 0.5 = 1 1000 x = 1 − 0 .5 1000 x = 0.5(1000 ) x = 500  4  e = ( 999875)  500  3999.5 e= 500 e = 7.9

5 x = 250 − 30 p + p 2

x = 250 − 30(12 ) + 12 2 x = 250 − 360 + 144 x = 34

(

 12  e =   250 − 30 p + p 2  34   12  e =  ( 0 − 30 + 2 p )  34 

)

 12  e =  ( − 30 + 2 p )  34  − 360 + 24 p e= 34 − 360 + 24(12 ) e= 34 − 360 + 288 e= 34 e = −2.11 Cambio Porcentual en la demanda e= Cambio Porcentual en el Pr ecio CPD = ( CPP )( e ) CPD = ( 8.5% )( − 2.11) CPD = −17,935%

6 A p p p p

= 30 − 0.5 x = 30 − 0.5( 200 ) = 300 − 100 = 200

p = 300 − 0.5 x p + 0.5 x = 300 0.5 x = 300 − p 300 − p x= 0.5  200  300 − p  e =    200  0.5   200  0.5( 0 − 1) − 300 − p ( 0 )  e =   0.5 2  200 

A I = ( 300 − 0.5 x ) x

 200  0.5( − 1)  e =   200  0.25   200  e = ( − 2 )  200  − 400 e= 200 e = −2

I = 300 x − 0.5 2

B

I = 300 x − 0.5 2

p − 300 − 0.5( 400 ) p = 300 − 200 p = 100

 100  e = ( − 2)  400  − 200 e= 400 e = −0.5

= 300( 200) − 0.5( 200 ) = 60000 − 0.5( 40.000 ) = 60000 − 2000 = 40000 B I = ( 300 − 0.5 x ) x

2

I I I I

I I I I

= 300( 400) − 0.5( 400 ) = 120000 − 0.5(160000 ) = 60000 − 80000 = 40000 2

7 x = 4100 − p 2

(

x 2 = 4100 − p 2

)

2

x 2 = 4100 − p x 2 − 4100 = − p

( − 1)

x 2 − 4100 = − p( − 1)

x 2 − 4100 = p p = 4100 − x

A

B p = 4100 − x p = 4100 − 50 p = 4050

p = 4100 − x p = 4100 − 40 p = 4060

(

)

1  4060  2 e =  4100 − p 2    40  1  4060  1 2 − 2 ( 0 − 2 p )  e = 4100 − p    40  2 1 − 4060   1 e = 4100 − p 2 2 − 2 p     40  2

(

)

(

)

(

)

 4060  2 e =  − p 4100 − p  40  −p  4060  e =   40  4100 − p 2

−1

2

 

 4050 e =  50  4050 e =  50

1  2 ( 4100 − p ) 2   

 4050 e =  50  4050 e =  50

1  1 2 −  2 ( 4100 − p ) 2 − 2 p   

1  1 2 −  2 ( 4100 − p ) 2 ( 0 − 2 p )    

1  2 − − p ( 4100 − p ) 2    −p  4050  e =   50  4100 − p 2

− 4060  4060  e =   40  4100 − ( 4060) 2

 4050  e =   50 

− 4060  4060  e =   40  4100 − 16483600 − 4060  4060  e =   40  − 16929500  4060  − 4060 e =   40  − 4057.4

 4050 e =  50  4050 e =  50

 4060  e =  − (1)  40  − 4060 e= 40 e = −101.5

  

− 4050 4100 − ( 4050 )

2

− 4060 4100 − 16402500 − 4060

   − 16398400  4050  − 4060 e =   50  − 4049 .4  4050  e = (1)  50  4050 e= 50 e = 81

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