Spm Addmath1 Ans (kedah)
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2
SULIT
3472/1
SPM Trial Examination 2008 Kedah Darul Aman Marking Scheme Additional Mathematics Paper 1 Question 1 (a)
2
Solution/ Marking Scheme B1: p(2) − 3 = 1
x2 (a) B1: 3y −2 = 2 or g 1 ( x) 3
Answer (a) 2
Marks 2
(b) −5 4 (a) 3
1 2
(b) x 2 2
2
(a) 7
1
(b) 3
1
(c) 5
1
(b) B1: 3 f ( x) 2 3x 2 4 3
4
B2: 1(3 1)
2k 1 2
B1 : 3 4 or (3 )
(a) 2
1
(b) 14
1
(c) 4
1
B2:
52
B1: 7
3
2k 1 2
5
6
7 2
5 5
3
x=2
3
5 2
(5 – 2p)(5 + 2p)
B2 : 3 x 3 2 or 3 x 9 B1 : 27 3 x 3 x 234 or 3 x 33 3 x 234
3472/1
Additional Mathematics Paper 1
SULIT
3
SULIT Question 8
9
Solution/ Marking Scheme
1 B2: 2 log 8 2 log 8 5 2
3472/1 Answer
Marks
(a) x 64
1
(b) x 73
1
1 2p q 2
3
(a) 2
3
(b) −1
1
(a) 8
1
(b) 4
3
6
3
p = 2, q = 5
4
(i) 2:3
1
(ii) 4
2
B1: log 8 4 5 log 8 4 log 8 5 10
(a) B2:
y2 y y6 y2
B1: log 2 ( y 2) log 2 ( y 6) log 2 y log 2 ( y 2) 11 (a) T1 S1 8 (b) B2: T2 20 8 or 12 B1 : S 2 2 22 3 or 20 12
13
n
1 1 B2: 64 2 64(1 0.5 n ) B1: 126 1 0.5
B3 : p 2 1 B2 : 2 1 p B1 : m1 2, or m2
1 or 1 p (2) q p
14 t 6 2 2 1 3 6 (ii) B1 : or t 1 t 3 5
m=2
15 B1: m 2 or n 1
3472/1
2
n = −1
Additional Mathematics Paper 1
SULIT
4
SULIT Question 16
3472/1
Solution/ Marking Scheme
Answer
Marks
6 2 x+ y 5 5
3
ED EB BD =2y +
2 BC 5
= 2y +
2 (3x − 4y) 5
= 2y +
6 8 x− y 5 5
=
B1 : BD
2 BC 5
B2
6 2 x+ y 5 5
OR
ED EA AD = −2y + CD 3 = −2y+ AC CB 5
B1 :
3 =−2y + 3x+ (4y-3x) 5
= −2y + 3x + =
CD
3 CB 5
B2
12 9 y− x 5 5
6 2 x+ y 5 5
17 B3: 45 0 , 75 0 58' (75.96 o ) (both)
45 0 , 225 0 , 0
B2 : tan x 1 , tan x 4 (both)
4 o
75 58' (75.96 ), 255 0 58' (255.96 o )
B1 : 3 tan 2 x 5 tan x 4(tan 2 x 1) 18 1 2 1 (7) (0.5236) (5) 2 (0.5236) or 2 2 1 2 1 2 (7) ( ) (5) ( ) 2 6 2 6 1 2 1 2 B1: (7) (0.5236) or (5) (0.5236) or 2 2 1 2 1 (7) ( ) or (5) 2 ( ) 2 6 2 6
B2 :
3472/1
(a) 0.5236 rad 1 ( ) 6
1
(b) 6.283 cm2 (2 )
3
Additional Mathematics Paper 1
SULIT
5
SULIT Question 19
Solution/ Marking Scheme dr 1 dr B2 : 50 or 50 4 (5) 2 dt 100 dt
3472/1 Answer
Mark
0.5 cms-1
3
3
3
(a) −4.5
1
(b) 35
3
18 x (2 3 x 2 ) 4
3
2
2
(a) 924
1
(b) 917
2
48 45 6
(a) 0.3085
2
k 45 0.5 6
(b) 42
2
B1 :
dV dV 4r 2 or 100 dr dr
B2:
k k 6 3(3 4 5) 3(3 2 5) 7
20
k (3x 5) 1 B1: 1 3 21
(b) B2 : 10 p[4 2] 80
B1 :
g ( x) dx pdx
B2:
dy dy 3(2 3 x 2 ) 4 (6 x ) or 3u 4 (6 x ) dx dx
or 10 or px
22
B1: 3(2 3 x 2 ) 4 or 6 x or 3u 4
23 B1:
24
(b) B1: 12 C 6 5
25
1 10 5
or
C1 7 C 5 5C 2 7 C 4 5C 3 7 C 3 5C 4 7 C 2 5C 5 7 C1
(a) B1 : Z
(b) B1 :
END OF MARKING SCHEME 3472/1
Additional Mathematics Paper 1
SULIT
SULIT
3472/1
SPM Trial Examination 2008 Kedah Darul Aman Marking Scheme Additional Mathematics Paper 1 Question 1 (a)
2
Solution/ Marking Scheme B1: p(2) − 3 = 1
x2 (a) B1: 3y −2 = 2 or g 1 ( x) 3
Answer (a) 2
Marks 2
(b) −5 4 (a) 3
1 2
(b) x 2 2
2
(a) 7
1
(b) 3
1
(c) 5
1
(b) B1: 3 f ( x) 2 3x 2 4 3
4
B2: 1(3 1)
2k 1 2
B1 : 3 4 or (3 )
(a) 2
1
(b) 14
1
(c) 4
1
B2:
52
B1: 7
3
2k 1 2
5
6
7 2
5 5
3
x=2
3
5 2
(5 – 2p)(5 + 2p)
B2 : 3 x 3 2 or 3 x 9 B1 : 27 3 x 3 x 234 or 3 x 33 3 x 234
3472/1
Additional Mathematics Paper 1
SULIT
3
SULIT Question 8
9
Solution/ Marking Scheme
1 B2: 2 log 8 2 log 8 5 2
3472/1 Answer
Marks
(a) x 64
1
(b) x 73
1
1 2p q 2
3
(a) 2
3
(b) −1
1
(a) 8
1
(b) 4
3
6
3
p = 2, q = 5
4
(i) 2:3
1
(ii) 4
2
B1: log 8 4 5 log 8 4 log 8 5 10
(a) B2:
y2 y y6 y2
B1: log 2 ( y 2) log 2 ( y 6) log 2 y log 2 ( y 2) 11 (a) T1 S1 8 (b) B2: T2 20 8 or 12 B1 : S 2 2 22 3 or 20 12
13
n
1 1 B2: 64 2 64(1 0.5 n ) B1: 126 1 0.5
B3 : p 2 1 B2 : 2 1 p B1 : m1 2, or m2
1 or 1 p (2) q p
14 t 6 2 2 1 3 6 (ii) B1 : or t 1 t 3 5
m=2
15 B1: m 2 or n 1
3472/1
2
n = −1
Additional Mathematics Paper 1
SULIT
4
SULIT Question 16
3472/1
Solution/ Marking Scheme
Answer
Marks
6 2 x+ y 5 5
3
ED EB BD =2y +
2 BC 5
= 2y +
2 (3x − 4y) 5
= 2y +
6 8 x− y 5 5
=
B1 : BD
2 BC 5
B2
6 2 x+ y 5 5
OR
ED EA AD = −2y + CD 3 = −2y+ AC CB 5
B1 :
3 =−2y + 3x+ (4y-3x) 5
= −2y + 3x + =
CD
3 CB 5
B2
12 9 y− x 5 5
6 2 x+ y 5 5
17 B3: 45 0 , 75 0 58' (75.96 o ) (both)
45 0 , 225 0 , 0
B2 : tan x 1 , tan x 4 (both)
4 o
75 58' (75.96 ), 255 0 58' (255.96 o )
B1 : 3 tan 2 x 5 tan x 4(tan 2 x 1) 18 1 2 1 (7) (0.5236) (5) 2 (0.5236) or 2 2 1 2 1 2 (7) ( ) (5) ( ) 2 6 2 6 1 2 1 2 B1: (7) (0.5236) or (5) (0.5236) or 2 2 1 2 1 (7) ( ) or (5) 2 ( ) 2 6 2 6
B2 :
3472/1
(a) 0.5236 rad 1 ( ) 6
1
(b) 6.283 cm2 (2 )
3
Additional Mathematics Paper 1
SULIT
5
SULIT Question 19
Solution/ Marking Scheme dr 1 dr B2 : 50 or 50 4 (5) 2 dt 100 dt
3472/1 Answer
Mark
0.5 cms-1
3
3
3
(a) −4.5
1
(b) 35
3
18 x (2 3 x 2 ) 4
3
2
2
(a) 924
1
(b) 917
2
48 45 6
(a) 0.3085
2
k 45 0.5 6
(b) 42
2
B1 :
dV dV 4r 2 or 100 dr dr
B2:
k k 6 3(3 4 5) 3(3 2 5) 7
20
k (3x 5) 1 B1: 1 3 21
(b) B2 : 10 p[4 2] 80
B1 :
g ( x) dx pdx
B2:
dy dy 3(2 3 x 2 ) 4 (6 x ) or 3u 4 (6 x ) dx dx
or 10 or px
22
B1: 3(2 3 x 2 ) 4 or 6 x or 3u 4
23 B1:
24
(b) B1: 12 C 6 5
25
1 10 5
or
C1 7 C 5 5C 2 7 C 4 5C 3 7 C 3 5C 4 7 C 2 5C 5 7 C1
(a) B1 : Z
(b) B1 :
END OF MARKING SCHEME 3472/1
Additional Mathematics Paper 1
SULIT
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