Solid Slabs

  • November 2019
  • PDF

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Design of Reinforced Concrete Slabs Ultimate b a ts

= = =

8.0 5.8 17

m Long Direction m Short Direction cm Thickness of Slab

ts min = 16.57 cm Safe Input Date Condition Ok L.L flooring owt

fcu = fy =

250 kg/cm2 3600 2400 2800 3600 4000 4500

0.25 t/m2 0.15 t/m2 0.43 t/m2

Condition of Slab in direction of a

Continous Two 3 Ends

Condition of Slab in direction of b

Continous Two 3 Ends

km (a) km (b)

12 12

ma = mb =

r = mb*b/ma*a =

0.76 0.76

1.38

α (Short Direction )= β (Long Direction) = W ultimate =

0.54 0.18 1.21 t/m2

Wα = 0.65 t/m2 Wβ = 0.22 t/m2 code 1.6;1.5

for Short Direction As min = 2.55 M= 1.823 ====>>As cal = 4.03 for Long Direction As >As Min. M= 1.182 ====>>As cal = 2.58

As for M I-I = 4.03 As for M II-II = 2.58

= =

6 5

10 10

2 Ok 2 Min 5/m'

= 8.0 17

5 10

= 5.8

6 10

= 5.8

6 10

Designed By : Eng/ Ayman G Abbas

[email protected]

[email protected]

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