Slope Homework

  • June 2020
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/ @ ALgebra

_~Finding the Slope of a Line You are already familiar with the concept slope. When you walk uphill, you walk up a slope. When you walk downhill, you walk d wn a slope. A graphed line, like a hill, has a slope. The slope of a line is given as a number. When you move been two points on the line, the slope is found by dividing the chang value by the corresponding change in x value.

• A line that goes up from left to right has a poive slope. • A line that goes down from left to right has ~egative slope. In Example 1, the slope of the line is 2.

In; xample 2, the slope of the line is -(

EXRMPLE1

JMPLE 2

Slope

= ~ =

r

j

2 Y

: /lC.~a~ge If--Il. ~ [/

~ It--J!

i

[! ··thtiigeffk~s

-

-$

-4 - -~ -

7

i

~n Y

-s-4i umts.

3

2 units,' 6 x

Y Slope

r!~



Chang~;' ", ("-.:

,

_-f.. = -1 2

u

;

is u~~~s=~->~ 2

Change in x is:2 Jnfits~ '\. i

-

;•

-

-

-

-2 -1 0

:'\.

. ··········,·····---,..1- •........... _ ,

.",.

.....-I-L2-:

l: 'I , / Ii

=

%) = -1.

4;

'"

'" "

:'\.

'\.

'"

5

6

The line above has positive sLop because it goes up from left to ght.

The line above has negative sLope because it goes down from left to right. Y

Zero Slope and Undefined Slope Two types of lines have neither posi e nor negative slope. • A horizontal line has zero sl£ e. The x-axis (or any horizontalliq ) is a line with 0 slope. • A vertical line has an undefi ed slope. The concept of slope does t >tapply to a vertical line. The y-axis (or .'.ny vertical line) isa line with undefine, slope.

3·2-

-'L:

Zero slope

1--·

-

-.

-i

-

o

1. 2

~ J

4<.

,~ Undefined slope

Graphing

1. Name the slope of each line as positive, negative, zero, or undefined. y

Equations

~

2. Find the numerical value of the slope of line E. Identify the x- and y-intercepts. Y

~

E ~. /

J

I

/ j"(L

~,

--

L

..•....

.

- -,

- ...". ...2.

... ~.

.._

......

.

...................

Ii

"',- '/1 i

6-

..........

iri-.....

" "

.1

i

-

- - -

- --

~.~. f

! ..... -

j

F ~ 6-

~

D

0

LineA:

LineB:

J

Line C: Wl"

Slope of line E is

~

~

x-intercept = (",0)

LineD:~

3. Find the numerical value of the slope of line F. Identify the x- and y-intercepts.

'\'

.6-

f-':i 6)"\.

'-'I -

sIope - changeinx - 4-3 - 1 - 5

.•.., ...

4-

b. (0,2) and (1,4)

0

'-

1

2

9-

_.L .. " \1-- ~~.L2 ~.

-J

I r\ '\

S

'\

Slope of line F is

-~2

(number)

x-intercept =

(3,1) and (4, 6) _changeiny_6-1_2_

5

. r\

-,

i

4. Subtract the coordinates to find the slope of the line that passes through each pair of points. Part a is done as an example. a.

--' ....

~

-;

_

-\

(number)

y-intercept = (t(), -)

- - -

!

/.



3

t

C

/ f

0

4

I

,

-

"

I

<

-,

If)

f

q~, 0)

y-intercept = (0 ' '})

,

c. (1,2) and (-2, 5)

-1

\

@ Algebra

JGraphing a Linear Equation When solutions of a linear equation such as y = 3x - 1 are plotted on a coordinate grid, they always lie on a straight line. Drawing this line of solutions is called graphing the equation. To graph a linear equation, follow these steps. STEP 1

Choose three vaLues for x and find the matching vaLues for y. Write each pair of vaLues in a TabLeof VaLues.

STEP 2

PLotthe three points on a coordinate grid; then connect them with a Line extending to the edges of the grid.

Graph the equation y = 3x - 1. STEP 1

Let x

= 0,

1, and 2. SoLvethe equation 1 for these three vaLues. Make a TabLeof VaLues.

y

= 3x -

J

'-

value

y= 3x.~ 1.

x

Y

x=O

y=3(0)-1=-1

0

-1

x=l

= 3(1) Y = 3(2)

- 1=2

1

2

- 1 =" 5

2

5

x

Y

x=2

':: -

-

5 " = 1" 0 x-intercept y-intercept = 0 -).. slope = (

I

6

x

_; _ •0

:

.'

-~

_

4

"

y

_' _

i 2

.

Table of Values

_

0

l~.l

1. y=x-2

o

-: -

f. ...-'-6

Graph each equation. As a first step, complete the Table of Values. Then find the x- and y-intercepts and slope for each graphed line.

o

-

·····!IfRi·2[l"".-:

:. ....

PLotthe points A = (0, -1) B = (1, 2) C = (2, 5). Conne.ct them with a Line that extends to the edges of the grid.

STEP 2

,

i

: ~t

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