49. If $3,000.00 is deposited into an account paying 3% interest compounded annually (at the end of each year), how much money is in the account after 4 years? (Round to the nearest cent.) Space to show work
Principal P = $3000 Interest rate r = 3% = 0.03 Period = 4 years N =1 Formula for calculating compound interest:
Where, •
P = principal amount (initial investment)
•
r = annual nominal interest rate (as a decimal)
•
n = number of times the interest is compounded per year
•
t = number of years
•
A = amount after time t
A=3000(1+0.03)4=3000*1.1255 =$3376.53
50.
Write
as a percent. 1 8
Space to show work
percent=18*100=1008=12.5%
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51.
Complete the statement.
18 kg = ________ g Space to show work
1 kg = 1000g
So 18kg = 18000 g
52.
Complete the following statement.
12 ft = ________ in.
Space to show work
1 ft = 12 in So 12 ft = 12*12 = 144 in
53.
Complete the statement. (Round to the nearest hundredth.)
2.1 kg = ________ oz
Space to show work
1 kg = 35.27396 oz So 2.1 kg = 2.1× 35.27396 oz = 74.075 ≈ 74.08
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54.
Complete the following statement.
20 lb = ________ oz
Space to show work
1lb = 16 oz So 20lb = 20×16 = 320 oz
55.
Complete the statement.
461 mm = ________ m Space to show work
1000mm = 1m So 461mm = 4611000=0.461m
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