Design of Hollow Pot Slab Project : Regional Office for CWA at Pamplemousses.
01 0635 AS 5/10/2001
Page Job No. Made by Date
Project Sub-Title : First Floor Slab
Sketch and Plan on Hollow Pot Slab
Sketch
Rib
Plan
Lx
Ly Plan view of a Hollow Pot
Slab Dimensions
Hollow pot slab width, b
=
3.00
m
Hollow Block Dimensions & Thickness of Topping H 205 457 Hollow blocks have same length (L=457mm) and width (W=205mm) but their heights , H varies. Hollow blocks have a minimum crushing strength of 3.50N/mm 2 on gross area. Height of hollow block, H
=
mm
Topping to be placed on top of hollow blocks, t
=
mm
Design of Hollow Pot Slab Project : Regional Office for CWA at Pamplemousses.
02 0635 HM 5/10/2001
Page Job No. Made by Date
Project Sub-Title : First Floor Slab
Exposure Conditions (Cl 3.3.4; BS8110;Part1;1997) Exposure condition, (Table 3.2: BS8110;Part1;1997) Lowest grade of concrete to be used, C30 Nominal cover to all reinforcement including links to meet durability requirements, c d (Table 3.3;BS8110;Part1;1997)
Period of fire resistance, t Nominal cover to all reinforcement including links to meet specified periods of fire resistance, c f (Table 3.4:BS8110;Part1:1997)
Effective cover , ce
= 30 =
=
mm
Cover as Fire Protection (Cl 3.3.6;BS8110;Part1;1997) h
=
=
N/mm2
mm
0
Note
Effective cover mm
Ribbed Dimension
The width of the reinforced concrete rib should be greater or equal to that given in table 3.2;BS8110;Part1;1997 Rib width, b =
The total rib height will be equal to the sum of the topping thickness and the hollow block height, h
=
mm
0
mm
Effective depth , d = h-ce-θl-θm/2 where ce = effective cover θl = Diameter of links θm = Diameter of main steel Links diameter, θl
=
6
mm
Main bar diameter, θm Therefore, effective depth of Rib, d
= =
16
mm mm
Design of Hollow Pot Slab Project : Regional Office for CWA at Pamplemousses.
Page Job No. Made by Date
Project Sub-Title : First Floor Slab
03 0635 HM 5/10/2001
Self weight of hollow pot slab = Superimposed Dead load (Screed, plaster and finishes), =
1.00
Dead load kN/m2 2 kN/m
Live Load (BS6399:Part1:1996),
=
2.50
Live load 2 kN/m
LOAD AT ULTIMATE LIMIT STATE = 1.4 Gk + 1.6 Qk
=
Ultimate design load 2 kN/m 5.4
Distance between center line of two consecutive ribs Load resisted by each rib , wr
= =
0.0
mm kN/m
Moment and Reinforcement Calculations Since the ribs span in one direction , maximum moment will 2 occur at mid-span and will be equal to w rl /8 Maximum moment Mmax
=
kNm
Reinforcement Calculations (Cl 3.4.4.4;BS8110;Part1;1997) Moment coefficient K = M/(bfd2fcu) = Since K< 0.156, therefore no compression reinforcement is required. Lever arm , Z = d[.5+sqrt{(.25-(K/.9)}]
=
mm
=
mm
2
Minimum reinforcement A s min is equal to .15%bh and is less than that required. Area of steel provided, A s prov =
mm
2
Since d-z =(357-339)=18 < hf/2, Neutral Axis lies within flange and beam is designed with b=b f Area of steel required, As req = M/0.95*fy*z where fy = 425N/mm2
Design of Hollow Pot Slab Project : Regional Office for CWA at Pamplemousses.
04 0635 HM 5/10/2001
Page Job No. Made by Date
Project Sub-Title : First Floor Slab
Deflection Check (Cl 3.4.6;BS8110;Part1;1997) Basic span to effective depth ratio for a flanged rib beam, simply supported is obtained from Table 3.9 of BS8110;Part1;1997 bw/b
=
For bw/b less or equal to 0.3, the basic l/d ratio for a simply supported flanged beam = Modification factor (Cl 3.4.6.6 BS8110;Part1;1997) The design service stress in tension reinforcement in a member may be obtained from the equation given below fs = 2*fy*As req/(3*As prov )
=
Modification factor , M.F. is obtained from the formula given below 2 MF = .55 + (477-fs)/[120+(.9+M/bd )] =
Permissible span to effective depth ratio is equal to the basic span to effective ratio multiplied by the modification factor Therefore, Permissible l/d = Actual span to effective depth ratio,
=
Since Permissible span to effective depth ratio is greater than actual span to effective depth ratio, therefore beam satisfies deflection criteria
N/mm
2
Design of Hollow Pot Slab Project : Regional Office for CWA at Pamplemousses.
Page Job No. Made by Date
Project Sub-Title : First Floor Slab
Design shear force V = wl/2 Design shear stress, v = V/bd
= =
05 0635 HM 5/10/2001
Shear Check (Cl 3.6.4; BS8110;Part1;1997) kN N/mm2
Note The calculated design shear stress must be less than 2 0.8sqrtfcu = 4.4 N/mm (Cl 3.6.4; BS8110;Part1;1997) (100As/bd)
1/3
(400/d)1/4 1/3 (fcu/25)
= = =
Note 100As/bd should not be taken as greater than 3 400/d should not be taken as less than 1
Design concrete shear stress is obtained from the formula 1/3 1/4 1/3] given vc= 0.79*[(100As/bd) *(400/d) *(fcu/25) /γm
=
N/mm
=
mm2
2
where γm = 1.25 From table 3.7;BS8110;Part1;1997 it is seen that 0.5vc < v < vc+.4 , hence minimum links for the whole length of beam is to be provided as calculated from the formula given below; (Asv/Sv)*(.95*fyv) = 0.4b Links to be provided : R06-150 which is equivalent to 82mm2
Transverse steel As trans = .15%bh
=
Area of steel provided
=
Topping Reinforcement 2 mm /m 2
mm /m