Quiz 7
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INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
? Distance? Velocity? Acceleration?
Which is the reference (+) direction?
Values: Constant? Increasing? Decreasing? Positive? Negative? Gradient: What does it represent? Constant? Increasing? Decreasing? Positive? Negative? t Area: What does it represent?
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
displacement, velocity and acceleration: vector quantities positive sign for vector quantity in a linear motion: direction of vector is in reference direction. negative sign for vector quantity in a linear motion: direction of vector is opposite reference direction. -x +v v
-x -v v
negative x
+x +v v
+x -v v
positive x
x=0 If the speed of the car is increasing, a has the same sign as v If its speed is decreasing, a has the opposite sign as v
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
NEXT
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and positive ⇒ the velocity of the graph is constant and positive
All values of x are positive ⇒ the body is at a positive displacement at all times
v
negative x
v
v
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is increasing and positive ⇒ the velocity of the body is increasing and positive
All values of x are positive ⇒ the body is at a positive displacement at all times
v1
negative x
v2
v3
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is decreasing and positive ⇒ the velocity of the body is decreasing and positive
All values of x are positive ⇒ the body is at a positive displacement at all times
v1
negative x
v2
v3
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of x are positive ⇒ the body is at a positive displacement at all times
The gradient of the graph is zero ⇒ the velocity of the body is zero; it is stationary.
negative x
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and negative ⇒ the velocity of the body is constant and negative
All values of x are positive ⇒ the body is at a positive displacement at all times
v
v
negative x
v
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of x are positive ⇒ the body is at a positive displacement at all times
The gradient of the graph is decreasing and negative ⇒ the velocity of the body is decreasing and negative
v3
negative x
v2
v1
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is increasing and negative ⇒ the velocity of the body is increasing and negative
All values of x are positive ⇒ the body is at a positive displacement at all times
v3
v2
negative x
v1
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is zero ⇒ the acceleration of the body is zero; it is moving at constant speed
All values of v are positive ⇒ the body is moving with a positive velocity at all times
v
negative Δx
v
v
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of v are positive ⇒ the body is moving with a positive velocity at all times
The gradient of the graph is positive and constant ⇒ the acceleration of the body is positive and constant; the velocity is increasing at a constant rate v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of v are positive ⇒ the body is moving at a positive velocity at all times Δ
v1
negative Δx
The gradient of the graph is increasing and positive ⇒ the acceleration of the body is increasing and positive; the speed of the body is increasing at an increasing rate v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is decreasing and positive ⇒ the acceleration of the body is decreasing and positive; the speed of the body is increasing at an decreasing rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of v are negative ⇒ the body is moving at a negative velocity at all times
v3
v2
v1
negative Δx
The gradient of the graph is constant and positive ⇒ the acceleration of the body is constant and positive; the direction of the acceleration is opposite that of the motion, causing the speed to decrease.
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and negative ⇒ the acceleration of the body is constant and negative (opp the direction of the velocity); the speed of the body is decreasing at an constant rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is decreasing and negative ⇒ the acceleration of the body is decreasing and negative (opp the direction of the velocity); the speed of the body is decreasing at an decreasing rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is negative and increasing ⇒ the acceleration of the body is increasing and negative (opp direction of velocity); the speed of the body is decreasing at an increasing rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and negative ⇒ the acceleration of the body is constant and negative; the direction of the acceleration is the same as that of the motion, causing the speed to increase.
All values of v are negative ⇒ the body is moving at a negative velocity at all times
v3
v2
v1
negative Δx
positive Δx xo
back
? Distance? Velocity? Acceleration?
Which is the reference (+) direction?
Values: Constant? Increasing? Decreasing? Positive? Negative? Gradient: What does it represent? Constant? Increasing? Decreasing? Positive? Negative? t Area: What does it represent?
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
displacement, velocity and acceleration: vector quantities positive sign for vector quantity in a linear motion: direction of vector is in reference direction. negative sign for vector quantity in a linear motion: direction of vector is opposite reference direction. -x +v v
-x -v v
negative x
+x +v v
+x -v v
positive x
x=0 If the speed of the car is increasing, a has the same sign as v If its speed is decreasing, a has the opposite sign as v
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
NEXT
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and positive ⇒ the velocity of the graph is constant and positive
All values of x are positive ⇒ the body is at a positive displacement at all times
v
negative x
v
v
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is increasing and positive ⇒ the velocity of the body is increasing and positive
All values of x are positive ⇒ the body is at a positive displacement at all times
v1
negative x
v2
v3
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is decreasing and positive ⇒ the velocity of the body is decreasing and positive
All values of x are positive ⇒ the body is at a positive displacement at all times
v1
negative x
v2
v3
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of x are positive ⇒ the body is at a positive displacement at all times
The gradient of the graph is zero ⇒ the velocity of the body is zero; it is stationary.
negative x
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and negative ⇒ the velocity of the body is constant and negative
All values of x are positive ⇒ the body is at a positive displacement at all times
v
v
negative x
v
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of x are positive ⇒ the body is at a positive displacement at all times
The gradient of the graph is decreasing and negative ⇒ the velocity of the body is decreasing and negative
v3
negative x
v2
v1
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is increasing and negative ⇒ the velocity of the body is increasing and negative
All values of x are positive ⇒ the body is at a positive displacement at all times
v3
v2
negative x
v1
positive x x=0
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is zero ⇒ the acceleration of the body is zero; it is moving at constant speed
All values of v are positive ⇒ the body is moving with a positive velocity at all times
v
negative Δx
v
v
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of v are positive ⇒ the body is moving with a positive velocity at all times
The gradient of the graph is positive and constant ⇒ the acceleration of the body is positive and constant; the velocity is increasing at a constant rate v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of v are positive ⇒ the body is moving at a positive velocity at all times Δ
v1
negative Δx
The gradient of the graph is increasing and positive ⇒ the acceleration of the body is increasing and positive; the speed of the body is increasing at an increasing rate v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is decreasing and positive ⇒ the acceleration of the body is decreasing and positive; the speed of the body is increasing at an decreasing rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
All values of v are negative ⇒ the body is moving at a negative velocity at all times
v3
v2
v1
negative Δx
The gradient of the graph is constant and positive ⇒ the acceleration of the body is constant and positive; the direction of the acceleration is opposite that of the motion, causing the speed to decrease.
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and negative ⇒ the acceleration of the body is constant and negative (opp the direction of the velocity); the speed of the body is decreasing at an constant rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is decreasing and negative ⇒ the acceleration of the body is decreasing and negative (opp the direction of the velocity); the speed of the body is decreasing at an decreasing rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is negative and increasing ⇒ the acceleration of the body is increasing and negative (opp direction of velocity); the speed of the body is decreasing at an increasing rate
All values of v are positive ⇒ the body is moving at a positive velocity at all times
v1
negative Δx
v2
v3
positive Δx xo
back
INTERPRETATION : DISPLACEMENT-TIME & VELOCITY-TIME GRAPHS
The gradient of the graph is constant and negative ⇒ the acceleration of the body is constant and negative; the direction of the acceleration is the same as that of the motion, causing the speed to increase.
All values of v are negative ⇒ the body is moving at a negative velocity at all times
v3
v2
v1
negative Δx
positive Δx xo
back
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