Punto 1c.docx

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Tipo de ejercicios 1 - Integrales inmediatas. Ejercicio c.

3

∫(5 /π‘₯ ) βˆ’ 2 √π‘₯ 2 𝑑π‘₯

Paso 1: aplicando propiedad de integral suma o resta se divide en dos integrales. 3

∫(5 /π‘₯ )𝑑π‘₯ βˆ’ ∫ 2 √π‘₯ 2 𝑑π‘₯ Paso 2: resolvemos la primera integral.

∫(1 /π‘₯ ) = 𝐿𝑛π‘₯ ∫(5 /π‘₯ )𝑑π‘₯ = 5 ∫(1/π‘₯ )𝑑π‘₯ = 5𝐿𝑛π‘₯ Paso 3: solucionamos la segunda integral. En este paso vamos a aplicar ley de los radicales 3

3

βˆšπ‘Žπ‘š = π‘Žπ‘š/𝑛

3

∫ 2 √π‘₯ 2 𝑑π‘₯ = 2 ∫ √π‘₯ 2 𝑑π‘₯ = 2∫π‘₯

2/3

Propiedad integral 𝑛

𝑑π‘₯

∫ π‘₯ 𝑑π‘₯ =

2 +1

π‘₯3

= 2(3 2

+1

)+𝑐

5

=2 (

π‘₯3 5 3

)+𝑐

Aplicamos ley de oreja =

π‘₯ 5/3

=

1 5 3

3π‘₯ 5/3 5

5

=2(

3π‘₯ 3 5

)+𝑐 =

6π‘₯ 5/3 5

+𝑐

π‘₯ 𝑛+1 𝑛+1

+𝑐

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