LAMPIRAN A DATA TABEL
A.1 Tabel Data Mentah Data yang diperoleh pada percobaan ini : Tabel 1.1 Debit 4 Berlawanan Arah WAKTU 5 7 9
T(in) Panas Dingin 64 35 88 44 99 49
T(out) Panas Dingin 55 38 74 50 82 52
Tabel 1.2. Debit 4 Searah WAKTU 5 7 9
T(in) Panas Dingin 78 38 94 43 103 46
T(out) Panas Dingin 65 47 73 54 85 60
A.2 Tabel Data Jadi Tabel 1.3 Debit 4 Berlawanan Arah WAKTU 5 7 9
T(in) Panas Dingin 64 35 88 44 99 49
T(out) Panas Dingin 55 38 74 50 82 52
ΔT Panas 9 14 17
Dingin 3 6 3
ΔT LMTD 5,4614 9,4418 8,0710
Q Panas Dingin 43,2 14,4 67,2 28,8 81,6 14,4
Tabel 1.4. Debit 4 Searah WAKTU 5 7 9
T(in) Panas Dingin 78 38 94 43 103 46
T(out) Panas Dingin 65 47 73 54 85 60
ΔT Panas 13 21 18
Dingin 9 11 14
ΔT LMTD 10,8777 15,4649 15,9163
Q Panas Dingin 62,4 43,2 100,8 52,8 86,4 67,2
LAMPIRAN B PROSEDUR PERHITUNGAN
B.1 Perhitungan ΔT B.1.1. Perhitungan Panas Berlawanan Arah ΔT Panas (5 menit) = T(in) panas – T(out) panas = 64OC - 55 OC = 9 OC ΔT Panas (7 menit) = T(in) panas – T(out) panas = 88OC - 74 OC = 14 OC ΔT Panas (9 menit) = T(in) panas – T(out) panas = 99OC - 82 OC = 17 OC B.1.2 Perhitungan ΔT Dingin Berlawanan Arah ΔT Dingin (5 menit) = T(out) dingin – T(in) dingin = 38OC - 35 OC = 3 OC
ΔT Dingin (7 menit) = T(in) dingin – T(out) dingin = 50OC - 44 OC = 6 OC
ΔT Dingin (9 menit) = T(in) dingin – T(out) dingin = 52OC - 49 OC = 3 OC
B.1..3 Perhitungan ΔT Panas Satu Arah ΔT Panas (5 menit) = T(out) panas – T(in) panas = 78OC - 65 OC = 13 OC
ΔT Panas (7 menit) = T(in) panas – T(out) panas = 94OC - 73 OC = 21 OC
ΔT Panas (9 menit) = T(in) panas – T(out) panas = 103OC - 85 OC = 18 OC
B.1.4 Perhitungan ΔT Dingin Satu Arah ΔT Dingin (5 menit) = T(out) dingin – T(in) dingin = 47OC - 38 OC = 9 OC
ΔT Dingin (7 menit) = T(in) dingin – T(out) dingin = 54OC - 44 OC = 11 OC
ΔT Dingin (9 menit) = T(in) dingin – T(out) dingin = 60OC - 46 OC = 14 OC
B.2 Perhitungan ΔT LMTD B.2.1 Perhitugan ΔT LMTD Berlawanan Arah ΔT LMTD dalam waktu 5 menit ΔT LMTD =
=
∆𝑇1− ∆𝑇2 𝐿𝑛
∆𝑇1 ∆𝑇2
9− 3 𝐿𝑛
9 3
= 5,4614
ΔT dalam waktu 7 menit ΔT LMTD =
=
∆𝑇1− ∆𝑇2 𝐿𝑛
∆𝑇1 ∆𝑇2
14− 6 𝐿𝑛
14 6
= 9,4418
ΔT dalam waktu 9 menit ΔT LMTD =
=
∆𝑇1− ∆𝑇2 𝐿𝑛
∆𝑇1 ∆𝑇2
17− 3 𝐿𝑛
17 3
= 8,0710
B.2. 2 Perhitugan ΔT LMTD Searah ΔT LMTD dalam waktu 5 menit ΔT LMTD =
=
∆𝑇1− ∆𝑇2 𝐿𝑛
∆𝑇1 ∆𝑇2
13− 9 𝐿𝑛
13 9
= 10,8777
ΔT LMTD dalam waktu 7 menit ΔT LMTD =
=
∆𝑇1− ∆𝑇2 𝐿𝑛
∆𝑇1 ∆𝑇2
21− 11 𝐿𝑛
21 11
= 15,4649
ΔT LMTD dalam waktu 9 menit ΔT LMTD =
=
∆𝑇1− ∆𝑇2 𝐿𝑛
∆𝑇1 ∆𝑇2
18− 14 𝐿𝑛
18 14
= 15,9163
B.3 Perhitungan mencari Q B.3.1 Perhitungan Mencari Q Panas Dalam waktu 5 menit Q = m Cp ΔT