Placa De Orificio.docx

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ο‚· π‘„π‘Ÿ = 2

π‘£π‘œπ‘™π‘’π‘šπ‘’π‘›

=

π‘‘π‘–π‘’π‘šπ‘π‘œ

2𝑔(β„Ž2 βˆ’β„Ž1 )

ο‚· 𝑄𝑑 = 𝐴2 π‘₯ √

5 𝑙𝑑𝑠 16.57

=

0.30𝑙𝑑𝑠 𝑠

= 0.00030

= 2.83π‘₯10βˆ’4 π‘₯ 2√

𝐴 1βˆ’(𝐴2 ) 1

0.00038

π‘š3 𝑠

2(9.81)(0.168βˆ’0.086) 2.83π‘₯10βˆ’4 ) 9.62π‘₯10βˆ’4

1βˆ’(

π‘š3 𝑠

ο‚· 𝑒 = π‘„π‘Ÿ βˆ’ 𝑄𝑑 = 0.00030 βˆ’ 0.00038 = βˆ’0.00008 ο‚· 𝐢𝑑 =

π‘„π‘Ÿ 𝑄𝑑

0.0003

=

=

π‘š3 𝑠

= 0.79

0.00038

ο‚· β„Žπ‘ = β„Ž6 βˆ’ β„Ž8 = 0.168 βˆ’ 0.086 = 0.082π‘š ο‚· 𝑉𝑒 =

π‘„π‘Ÿ

=

𝐴1

ο‚· 𝑉𝑠 =

π‘„π‘Ÿ

ο‚· 𝐾=

β„Žπ‘

𝐴2 𝑣𝑒2 2𝑔

0.0003

= 0.31

0.000962

= =

0.00030 0.000283 (0.082)

= 1.1

π‘š 𝑠

π‘š 𝑠

= 16.74

(0.31)2 19.62

Placa de orificio lecturas 2 ο‚· π‘„π‘Ÿ = 2

π‘£π‘œπ‘™π‘’π‘šπ‘’π‘› π‘‘π‘–π‘’π‘šπ‘π‘œ

=

2𝑔(β„Ž2 βˆ’β„Ž1 )

ο‚· 𝑄𝑑 = 𝐴2 π‘₯ √

𝐴 1βˆ’(𝐴2 ) 1

5 𝑙𝑑𝑠 17.76

=

0.28𝑙𝑑𝑠 𝑠

= 0.00028

= 2.83π‘₯10βˆ’4 π‘₯ 2√

0.00037

π‘š3 𝑠

π‘š3 𝑠

2(9.81)(0.175βˆ’0.094) 2.83π‘₯10βˆ’4 ) 9.62π‘₯10βˆ’4

1βˆ’(

=

ο‚· 𝑒 = π‘„π‘Ÿ βˆ’ 𝑄𝑑 = 0.00028 βˆ’ 0.00037 = βˆ’0.000099 ο‚· 𝐢𝑑 =

π‘„π‘Ÿ 𝑄𝑑

0.00028

=

π‘š3 𝑠

= 0.76

0.00037

ο‚· β„Žπ‘ = β„Ž6 βˆ’ β„Ž8 = 0.175 βˆ’ 0.094 = 0.081π‘š ο‚· 𝑉𝑒 =

π‘„π‘Ÿ

ο‚· 𝑉𝑠 =

π‘„π‘Ÿ

ο‚· 𝐾=

β„Žπ‘

=

𝐴1

=

𝐴2

0.00028 0.000962 0.00028

= 0.99

0.000283 (0.081)

=

𝑣𝑒2 2𝑔

= 0.29

π‘š 𝑠 π‘š 𝑠

= 18.90

(0.29)2 19.62

Placa de orificio lecturas 3 ο‚· π‘„π‘Ÿ = 2

π‘£π‘œπ‘™π‘’π‘šπ‘’π‘› π‘‘π‘–π‘’π‘šπ‘π‘œ

2𝑔(β„Ž2 βˆ’β„Ž1 )

ο‚· 𝑄𝑑 = 𝐴2 π‘₯ √

𝐴 1βˆ’(𝐴2 ) 1

=

5 𝑙𝑑𝑠 21.39

=

0.23𝑙𝑑𝑠 𝑠

= 0.00023

= 2.83π‘₯10βˆ’4 π‘₯ 2√

0.00035

π‘š3 𝑠

2(9.81)(0.172βˆ’0.0999) 2.83π‘₯10βˆ’4 ) 9.62π‘₯10βˆ’4

1βˆ’(

π‘š3 𝑠

ο‚· 𝑒 = π‘„π‘Ÿ βˆ’ 𝑄𝑑 = 0.00023 βˆ’ 0.00035 = βˆ’0.00012 ο‚· 𝐢𝑑 =

π‘„π‘Ÿ 𝑄𝑑

=

0.00023 0.00035

= 0.66

ο‚· β„Žπ‘ = β„Ž6 βˆ’ β„Ž8 = 0.172 βˆ’ 0.099 = 0.073π‘š ο‚· 𝑉𝑒 =

π‘„π‘Ÿ

ο‚· 𝑉𝑠 =

π‘„π‘Ÿ

𝐴1 𝐴2

= =

0.00023 0.000962 0.00028 0.000283

= 0.24 = 0.81

π‘š 𝑠 π‘š 𝑠

π‘š3 𝑠

=

β„Žπ‘

ο‚· 𝐾=

(0.073)

=

𝑣𝑒2 2𝑔

= 24.87

(0.24)2 19.62

Placa de orificio lecturas 4 ο‚· π‘„π‘Ÿ = 2

π‘£π‘œπ‘™π‘’π‘šπ‘’π‘› π‘‘π‘–π‘’π‘šπ‘π‘œ

2𝑔(β„Ž2 βˆ’β„Ž1 )

ο‚· 𝑄𝑑 = 𝐴2 π‘₯ √

𝐴 1βˆ’(𝐴2 ) 1

5 𝑙𝑑𝑠

=

24.31

=

0.21𝑙𝑑𝑠 𝑠

= 0.00021

= 2.83π‘₯10βˆ’4 π‘₯ 2√

0.00033

π‘š3 𝑠

2(9.81)(0.167βˆ’0.103) 2.83π‘₯10βˆ’4 ) 9.62π‘₯10βˆ’4

1βˆ’(

π‘š3 𝑠

ο‚· 𝑒 = π‘„π‘Ÿ βˆ’ 𝑄𝑑 = 0.00021 βˆ’ 0.00033 = βˆ’0.00012 ο‚· 𝐢𝑑 =

π‘„π‘Ÿ 𝑄𝑑

0.00021

=

= 0.64

0.00033

ο‚· β„Žπ‘ = β„Ž6 βˆ’ β„Ž8 = 0.167 βˆ’ 0.103 = 0.064π‘š ο‚· 𝑉𝑒 =

π‘„π‘Ÿ

ο‚· 𝑉𝑠 =

π‘„π‘Ÿ

ο‚· 𝐾=

=

𝐴1

=

𝐴2 β„Žπ‘ 𝑣𝑒2 2𝑔

0.00021 0.000962 0.00021 0.000283

=

(0.064) (0.22)2 19.62

= 0.22 = 0.74

π‘š 𝑠 π‘š 𝑠

= 25.94

Placa de orificio lecturas 5 ο‚· π‘„π‘Ÿ =

π‘£π‘œπ‘™π‘’π‘šπ‘’π‘› π‘‘π‘–π‘’π‘šπ‘π‘œ

=

5 𝑙𝑑𝑠 28.41

=

0.18𝑙𝑑𝑠 𝑠

= 0.00018

π‘š3 𝑠

π‘š3 𝑠

=

2

2𝑔(β„Ž2 βˆ’β„Ž1 )

ο‚· 𝑄𝑑 = 𝐴2 π‘₯ √

𝐴 1βˆ’(𝐴2 ) 1

= 2.83π‘₯10βˆ’4 π‘₯ 2√

0.00031

2(9.81)(0.166βˆ’0.107) 2.83π‘₯10βˆ’4 ) 9.62π‘₯10βˆ’4

1βˆ’(

π‘š3 𝑠

ο‚· 𝑒 = π‘„π‘Ÿ βˆ’ 𝑄𝑑 = 0.00018 βˆ’ 0.00031 = βˆ’0.00013 ο‚· 𝐢𝑑 =

π‘„π‘Ÿ 𝑄𝑑

0.00018

=

=

π‘š3 𝑠

= 0.58

0.00031

ο‚· β„Žπ‘ = β„Ž6 βˆ’ β„Ž8 = 0.166 βˆ’ 0.107 = 0.059π‘š ο‚· 𝑉𝑒 =

π‘„π‘Ÿ

ο‚· 𝑉𝑠 =

π‘„π‘Ÿ

ο‚· 𝐾=

β„Žπ‘

=

𝐴1

=

𝐴2

0.00018 0.000962 0.00018

= 0.64

0.000283

=

𝑣𝑒2 2𝑔

= 0.19

(0.059) (0.19)2 19.62

π‘š 𝑠 π‘š 𝑠

= 32.10

Placa de orificio lecturas 6 ο‚· π‘„π‘Ÿ = 2

π‘£π‘œπ‘™π‘’π‘šπ‘’π‘› π‘‘π‘–π‘’π‘šπ‘π‘œ

2𝑔(β„Ž2 βˆ’β„Ž1 )

ο‚· 𝑄𝑑 = 𝐴2 π‘₯ √

𝐴 1βˆ’(𝐴2 ) 1

=

5 𝑙𝑑𝑠 30.33

=

016𝑙𝑑𝑠 𝑠

= 0.00016

= 2.83π‘₯10βˆ’4 π‘₯ 2√

0.00031

π‘š3 𝑠

2(9.81)(0.165βˆ’0.109) 2.83π‘₯10βˆ’4 ) 9.62π‘₯10βˆ’4

1βˆ’(

π‘š3 𝑠

ο‚· 𝑒 = π‘„π‘Ÿ βˆ’ 𝑄𝑑 = 0.00016 βˆ’ 0.00031 = βˆ’0.00015 ο‚· 𝐢𝑑 =

π‘„π‘Ÿ 𝑄𝑑

=

0.00016 0.00031

= 0.52

π‘š3 𝑠

=

ο‚· β„Žπ‘ = β„Ž6 βˆ’ β„Ž8 = 0.165 βˆ’ 0.109 = 0.056π‘š ο‚· 𝑉𝑒 =

π‘„π‘Ÿ

ο‚· 𝑉𝑠 =

π‘„π‘Ÿ

=

𝐴1

=

𝐴2 β„Žπ‘

ο‚· 𝐾=

0.00016 0.000962 0.00016

= 0.57

0.000283 (0.056)

=

𝑣𝑒2 2𝑔

= 0.17

π‘š 𝑠 π‘š 𝑠

= 38.02

(0.17)2 19.62

Placa de orificio lecturas 7 ο‚· π‘„π‘Ÿ = 2

π‘£π‘œπ‘™π‘’π‘šπ‘’π‘›

=

π‘‘π‘–π‘’π‘šπ‘π‘œ

2𝑔(β„Ž2 βˆ’β„Ž1 )

ο‚· 𝑄𝑑 = 𝐴2 π‘₯ √

𝐴

1βˆ’(𝐴2 )

5 𝑙𝑑𝑠 36.60

=

014𝑙𝑑𝑠 𝑠

= 0.00014

= 2.83π‘₯10βˆ’4 π‘₯ 2√

𝑠

2(9.81)(0.153βˆ’0.110) 2.83π‘₯10βˆ’4 ) 9.62π‘₯10βˆ’4

1βˆ’(

1

0.00027

π‘š3

π‘š3 𝑠

ο‚· 𝑒 = π‘„π‘Ÿ βˆ’ 𝑄𝑑 = 0.00014 βˆ’ 0.00027 = βˆ’0.00013 ο‚· 𝐢𝑑 =

π‘„π‘Ÿ 𝑄𝑑

=

0.00014 0.00027

= 0.52

ο‚· β„Žπ‘ = β„Ž6 βˆ’ β„Ž8 = 0.153 βˆ’ 0.110 = 0.043π‘š ο‚· 𝑉𝑒 =

π‘„π‘Ÿ

ο‚· 𝑉𝑠 =

π‘„π‘Ÿ

ο‚· 𝐾=

𝐴1 𝐴2 β„Žπ‘ 𝑣𝑒2 2𝑔

= =

0.00014 0.000962 0.00014 0.000283

=

(0.043) (0.14)2 19.62

= 0.14 = 0.49

π‘š 𝑠 π‘š 𝑠

= 43.04

=

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