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BACAAN PESAWAT TITIK
PA
PB
PC
PD
PA
B DET. 1 A C DET. 2 B D DET. 3 C A DET. 4 D B
HORIZONTAL ˚ ‘ ”
136
122
236
350
BELAKANG VERTIKAL BA ˚ ‘ ”
28 40 89 28 40
48 40 90 48 40
52
0
0
0
89 52
90
0
0
0
BT
BB
DEPAN HORIZONTAL VERTIKAL BA ˚ ‘ ” ˚ ‘ ” 119 2 20 91 2 29 78
18
175,7
173,2
170,6
41
28 40 89 28 40
191
180
169
122
28 40 89 28 40
168,5
165,8
162,9
38
23 40 89 23 40
160
129
98
70
36 40 90 23 40
124
120
116
146
0
0
89
0
0
161
150
139
198
51
0
89 51
0
183
180,1
177,2
260 51 40 89 51 40 TABEL 1.1 data pengukuran
213
183
153
88
273
165
72
240
154
29
48
2
138
2
BB
140 169
20 91
BT
109
66
208
143
PERHITUNGAN POLIGON TERTUTUP A. Sudut dalam (𝛽) ∑ 𝛽 = (n – 2) x 180˚ = ( 4 – 2 ) x 180˚ = 360˚ a. 𝛽A = Sudut Horizontal titik D – Sudut Horizontal titik B = 350˚0‘0”- 260˚54‘40” = 89˚08‘20” b. 𝛽B = Sudut Horizontal titik A- Sudut Horizontal titik C = 136˚28‘40”- 41˚28‘40” = 95˚0‘0” c. 𝛽C = Sudut Horizontal titik B – Sudut Horizontal titik D = 122˚48‘40”-38˚23‘40” = 84˚25‘0” d. 𝛽D = Sudut Horizontal titik C – Sudut Horizontal titik A
= 236˚52‘0” - 146˚0‘0” = 90˚52‘0” 1. Kontrol Sudut Dalam ∑ 𝛽 = 𝛽A + 𝛽B + 𝛽C + 𝛽D = 89˚8‘20” + 95˚0‘0” + 84˚ 25‘ 0” + 90˚52‘0” = 359˚25‘20” Koreksian = 360˚0‘0” - 359˚25‘20” = 34˚40” : 4 = 8’40” 2. Hasil Sudut Dalam Setelah Terkoreksi a. 𝛽A = 89˚08‘20” + 8’40” = 89˚17’0” b. 𝛽B = 95˚0‘0” + 8’40” = 95˚8’40” c. 𝛽C = 84˚25‘0” + 8’40” = 84˚33’40” d. 𝛽D = 90˚52‘0” + 8’40” = 91˚0’40” B. Sudut Jurusan (α) a. (α)AB = 119˚2’20” b. (α)BC = (α)AB + 180˚ - 𝛽B = 119˚2’20” + 180˚ - 95˚8’40” = 203˚53’40” c. (α)CD = (α)BC + 180˚ - 𝛽C = 203˚53’40” + 180˚ - 84˚33’40” = 299˚20’0” d. (α)DA = (α)CD - 180˚ - 91˚0’40” = 299˚20’0” - 180˚ - 91˚0’40” = 28˚19’20” C. Perhitungan Jarak ( D ) Rumus : 100(BA – BB ) cos2(90˚-V)
a. DAB = 100(78 – 18) cos2(90˚- 91˚2’20”) = 6000 . 1 = 6000 cm = 60 m b. DBC = 100(191 – 169) cos2(90˚-89˚28’40”) = 2200 . 1 = 2200 cm = 22 m c. DCD = 100(160 – 98) cos2(90˚- 89˚23’40”) = 6200 . 1 = 6200 cm = 62 m d. DDA = 100(161 – 139) cos2(90˚-89˚) = 2200 .1 = 2200 cm = 22 m
TITIK
β˚ 89
A 89 95 B 95 84 C 84 90 D 91
β β' 8 8 17 0 8 8 25 8 33 52 8 0
β" 20 40 0 0 40 40 0 40 40 0 40 40
α˚
α α'
α"
JARAK d(M)
119
2
20
60
203
53
40
22
299
20
0
62
28
19
20
22
ΔX d. sin α 52,2 0,07 52,27 -8,8 0,03 -8,77 -53,94 0,07 -53,87 10,34 0,03 10,37
ΔY d. cos α -23,4 -0,12 -29,52 -20,02 -0,04 -20,06 30,38 -0,12 30,26 19,36 0,04 19,32
A 359 ∑ 360
25 34 0
166 -0,2 ∑ 40 0,2 0 0 TABEL 1.2 hasil perhitungan poligon
0.32 -0,32 0
KOORDINAT X (M) Y (M) 10
10
62,27 -19,52
53,5
-39,58
-0,37
-9,32
10
10
PA
PB
PC
PD
PA
B DET. 1 A C DET. 2 B D DET. 3 C A DET. 4 D B
HORIZONTAL ˚ ‘ ”
136
122
236
350
BELAKANG VERTIKAL BA ˚ ‘ ”
28 40 89 28 40
48 40 90 48 40
52
0
0
0
89 52
90
0
0
0
BT
BB
DEPAN HORIZONTAL VERTIKAL BA ˚ ‘ ” ˚ ‘ ” 119 2 20 91 2 29 78
18
175,7
173,2
170,6
41
28 40 89 28 40
191
180
169
122
28 40 89 28 40
168,5
165,8
162,9
38
23 40 89 23 40
160
129
98
70
36 40 90 23 40
124
120
116
146
0
0
89
0
0
161
150
139
198
51
0
89 51
0
183
180,1
177,2
260 51 40 89 51 40 TABEL 1.1 data pengukuran
213
183
153
88
273
165
72
240
154
29
48
2
138
2
BB
140 169
20 91
BT
109
66
208
143
PERHITUNGAN POLIGON TERTUTUP A. Sudut dalam (𝛽) ∑ 𝛽 = (n – 2) x 180˚ = ( 4 – 2 ) x 180˚ = 360˚ a. 𝛽A = Sudut Horizontal titik D – Sudut Horizontal titik B = 350˚0‘0”- 260˚54‘40” = 89˚08‘20” b. 𝛽B = Sudut Horizontal titik A- Sudut Horizontal titik C = 136˚28‘40”- 41˚28‘40” = 95˚0‘0” c. 𝛽C = Sudut Horizontal titik B – Sudut Horizontal titik D = 122˚48‘40”-38˚23‘40” = 84˚25‘0” d. 𝛽D = Sudut Horizontal titik C – Sudut Horizontal titik A
= 236˚52‘0” - 146˚0‘0” = 90˚52‘0” 1. Kontrol Sudut Dalam ∑ 𝛽 = 𝛽A + 𝛽B + 𝛽C + 𝛽D = 89˚8‘20” + 95˚0‘0” + 84˚ 25‘ 0” + 90˚52‘0” = 359˚25‘20” Koreksian = 360˚0‘0” - 359˚25‘20” = 34˚40” : 4 = 8’40” 2. Hasil Sudut Dalam Setelah Terkoreksi a. 𝛽A = 89˚08‘20” + 8’40” = 89˚17’0” b. 𝛽B = 95˚0‘0” + 8’40” = 95˚8’40” c. 𝛽C = 84˚25‘0” + 8’40” = 84˚33’40” d. 𝛽D = 90˚52‘0” + 8’40” = 91˚0’40” B. Sudut Jurusan (α) a. (α)AB = 119˚2’20” b. (α)BC = (α)AB + 180˚ - 𝛽B = 119˚2’20” + 180˚ - 95˚8’40” = 203˚53’40” c. (α)CD = (α)BC + 180˚ - 𝛽C = 203˚53’40” + 180˚ - 84˚33’40” = 299˚20’0” d. (α)DA = (α)CD - 180˚ - 91˚0’40” = 299˚20’0” - 180˚ - 91˚0’40” = 28˚19’20” C. Perhitungan Jarak ( D ) Rumus : 100(BA – BB ) cos2(90˚-V)
a. DAB = 100(78 – 18) cos2(90˚- 91˚2’20”) = 6000 . 1 = 6000 cm = 60 m b. DBC = 100(191 – 169) cos2(90˚-89˚28’40”) = 2200 . 1 = 2200 cm = 22 m c. DCD = 100(160 – 98) cos2(90˚- 89˚23’40”) = 6200 . 1 = 6200 cm = 62 m d. DDA = 100(161 – 139) cos2(90˚-89˚) = 2200 .1 = 2200 cm = 22 m
TITIK
β˚ 89
A 89 95 B 95 84 C 84 90 D 91
β β' 8 8 17 0 8 8 25 8 33 52 8 0
β" 20 40 0 0 40 40 0 40 40 0 40 40
α˚
α α'
α"
JARAK d(M)
119
2
20
60
203
53
40
22
299
20
0
62
28
19
20
22
ΔX d. sin α 52,2 0,07 52,27 -8,8 0,03 -8,77 -53,94 0,07 -53,87 10,34 0,03 10,37
ΔY d. cos α -23,4 -0,12 -29,52 -20,02 -0,04 -20,06 30,38 -0,12 30,26 19,36 0,04 19,32
A 359 ∑ 360
25 34 0
166 -0,2 ∑ 40 0,2 0 0 TABEL 1.2 hasil perhitungan poligon
0.32 -0,32 0
KOORDINAT X (M) Y (M) 10
10
62,27 -19,52
53,5
-39,58
-0,37
-9,32
10
10
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