Perhitungan Tangga
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Perhitungan tangga syarat 60 ≤ 2 t + p ≥ 64 ket : n . p=q q = panjang tangga ( 200 ) ( n+1 ) t =T T = tinggi bordes ( 150 ) Penyelesayan : 2 t + p = 62 p = 62 - 2 t - b± n . p=q q p= n 200 p= n
b² - 4 a c 2a
- -438 ±
438
±
438
± 241444 124
438
± 491.37 124
438
+ 491.37 124
( n+1 ) t =T T ( n+1 ) 150 t = ( n+1 ) t =
200 150 = 62 - 2 n ( n+1 ) 200 62 ( n + 1 ) - 2 150 = n ( n+1 ) 200 ( n + 1 ) = ( 62 ( n + 1 ) -
300 ) n
-438 2 - 4 . 62 . -200 2 62
200 7.49 = 26.68
191844 + 49600 124
=
p=
→
26
200 n + 200 = 62 n² + 62 n - 300 n 62 n² + 62 n - 200 n - 300 n - 200 62 n² -438 n -
200
150 ( 7.49 + 1 ) = 17.66 → 18
t =
929.37 124
=
7.49
b² - 4 a c 2a
- -438 ±
438
±
438
± 241444 124
438
± 491.37 124
438
+ 491.37 124
( n+1 ) t =T T ( n+1 ) 150 t = ( n+1 ) t =
200 150 = 62 - 2 n ( n+1 ) 200 62 ( n + 1 ) - 2 150 = n ( n+1 ) 200 ( n + 1 ) = ( 62 ( n + 1 ) -
300 ) n
-438 2 - 4 . 62 . -200 2 62
200 7.49 = 26.68
191844 + 49600 124
=
p=
→
26
200 n + 200 = 62 n² + 62 n - 300 n 62 n² + 62 n - 200 n - 300 n - 200 62 n² -438 n -
200
150 ( 7.49 + 1 ) = 17.66 → 18
t =
929.37 124
=
7.49
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