Perhitungan Crump.docx

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4. Data hasil percobaan

a. Panjang ambang (L) = 0,195 m b. Lebar ambang (B)

= 0,050 m

c. Tinggi ambang

= 0,030 m

Tabel 3.A.1. Data Hasil Percobaan Pelimpah Crump No.

H (m)

h (m)

t1 (s)

t2 (s)

t3 (s)

1 2 3

0,0430 0,0450 0,0500

0,0050 0,0090 0,0150

10,18 4,86 2,79

10 5,21 2,88

10,2 5,43 2,67

5. Perhitungan

a. Menghitung waktu rata-rata (t)

t

t1+t2+t3

=

3

t1 =

10,18+10+10,2 = 10,1267 s 3

t2 =

4,86+5,21+5,43 = 5,1667 s 3 2,79+2,88+2,67

t3 =

3

= 2,7800 s

b. Menghitung debit aliran (Q)

Q =

𝑉 𝑡

Q1 =

0,001 10,1267

= 0,0001 m3 /s

Q2=

0,001 = 0,0002 m3 /s

Q3=

0,001 = 0,0004 m3 /s

5,1667

2,7800

c. Menghitung luas penampang basah (A)

A = BxH A1 = 0,05 x 0,0430 = 0,0022 m2 A2 = 0,05 x 0,0450 = 0,0023 m2 A3 = 0,05 x 0,0500 = 0,0025 m2 d. Menghitung tinggi energi total (H’)

H’ = H +

Q2 2 x g x A2

H’1 = 0,0430 +

H’2 = 0,0450 +

H’3 = 0,0500 +

0,00012 2 x 9,81 x 0,00222

= 0,0431 m

0,00022 2 x 9,81 x 0,00232 0,00042 2 x 9,81 x 0,00252

= 0,0454 m

= 0,0513 m

e. Menghitung koefisien debit (Cd) Q Cd = 1,705 x B x H1,5

0,0001 Cd1 = 1,705 x 0,05 x 0,0089

Cd2 =

0,0002 1,705 x 0,05 x 0,0095

0,0004 Cd3 = 1,705 x 0,05 x 0,0112

= = =

0,1318

0,2470

0,4189

f. Menghitung debit aliran moduler (Qm)

Qm = Cd x g x H x B Qm1 = 0,1318 x 9,81 x 0,0430 x 0,05 = 0,0028 m3 /s Qm2 = 0,2470 x 9,81 x 0,0450 x 0,05 = 0,0055 m3 /s Qm3 = 0,4189 x 9,81 x 0,0500 x 0,05 = 0,0103 m3 /s

g. Menghitung faktor reduksi (f)

f =

𝑄 𝑄𝑚

f1 =

0,0001 =0,0357 0,0028

f2 =

0,0002 = 0,0364 0,0055

f3 =

0,0004 = 0,0388 0,0103

Tabel 3.A.2. Data Hasil Perhitungan Pecobaan Aliran diatas Pelimpah Crump No 1 2 3

H (m) 0,0430 0,0450 0,0500

h (m) 0,0050 0,0090 0,0150

h/H 0,1163 0,2000 0,3000

f 0,0357 0,0364 0,0388

Q (𝑚3 /s) 0,0001 0,0002 0,0004

Qm (𝑚3 /s) 0,0028 0,0055 0,0103

Grafik Hubungan antara h/H dan f 0.4

0.0388, 0.3

h/H

0.3 0.0364, 0.2 0.2 0.0357, 0.1163 0.1 0.0315

0.0365

0.0415

f

Gambar 3.A.9. Grafik hubungan antara h/H dan f.

0.0465

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