تمارين الإتصال والنهايات

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 ‫ ا"  آ ر‬:‫ ا ى‬, ‫ااد ا أ ش    ا‬ f ( x) =

1 

x² + x + 1 x² + 1

2*‫ ا‬5 ‫ ت‬25‫= ا‬,‫ أ‬B f ) '* @, ‫د‬, 5‫ ه‬7 ‫و‬8* D‫ أ‬B -1 %&‫ و‬o %& f ‫ق‬./‫أدرس ا‬

+5 ‫ول‬E D‫ أ‬B IR − {− 1,0}  x 3# f(x) =,‫أ‬ f ‫ات اا‬$*

π

-

[

-

f ‫  *' ) اا‬+ ‫د‬, -1 %& ‫ و‬1 %& f ‫ق‬./‫أدرس  ا‬ 2 34‫ ا‬+5 5‫ ه‬7 ‫و‬8* 95‫ا‬ f'(x) :‫ ا;و‬.<‫= اا ا‬,‫أ‬

7 ‫ا‬ x
: %  &'‫ ا‬x $ ‫ دا د‬f # f ( x) = x + x ² − 1 | x |≥ 1 f ( x) = sin( , x) 2

| x |π 1

]0 , π 2 [  x 3# 

U(x)=tan x – x ‫ات‬$* ‫أدرس‬

-

]0 , π 3 [  x 3# G ‫ أ‬

x < tan x < x + x 3

2  %  &' ‫ دا د‬f # f ( x) = 1 − cos(2π sin x) o %& f ‫ق اا‬./‫أدرس  ا‬ 3 

8 ‫ا‬ ‫ ' م‬%.., ‫ د‬x # x ‫ 'د‬I4‫@ء ا‬+ E(x) ‫  @ ل‬ : %  &' ‫ دا د‬f # f ( x) = E ( x) sin(πx) [− 1,0[ ‫ت ا‬K+‫ ا‬%& sin( π x) K f(x) =‫ أآ‬[-1,2] : 4 f ‫ أن‬95‫ ا‬B [1,2[ ‫[ و‬0,1[ ‫و‬ x=2 ‫ و‬x=1 ‫ و‬x=0 %& f ‫ق‬./‫ ادرس ا‬M< ‫ أ‬B [-1,2] ‫ل‬+‫ ا‬: f ‫ات اا‬$* ‫ أدرس‬ρ (o, yρ, j ) B'‫ ا‬%& 2 3"‫ ا‬:55‫ا‬ 9 ‫ا‬ O o N@‫ آ‬I ‫ل‬+ : &' ‫ دا‬g ‫ و‬f g ( x) ∀x ∈ I f ( x) = x 3 g ( x) − x+2 g(o)=1 ‫ و‬g'(o)=o G ‫ أ‬P ‫ إذا‬f'(o) =,‫أ‬ 10 ‫ا‬ : ‫ أن‬

C n + 2C n + ........... + nC n = n2 1

2

n

n −1

-

: % ‫ ا'& آ‬x %..‫ ا‬$ f ‫ '> اا ا'د‬ f (x) = x(x-E(x)) 2? '* @, : f ‫ق اا‬./‫أدرس  ا‬ ( x = 0 ‫و‬x ∉ Z ; x ∈ Z * ) 4  : % ‫ ا'& آ‬x %..‫ ا‬$ f ‫ '> اا ا'د‬ F(x)=x(cosx-E(cosx)) X0 =π

π

2 2

X0=0 %& f ‫ل‬4*‫أدرس ا‬

-

%&‫ و‬0 %& f ‫ق‬./‫أدرس ا‬

-

5 ‫ا‬ : % ‫ ا'& آ‬x %..‫ ا‬$ fm ‫ '> اا ا'د‬ x−m f m ( x) = x−m −m fm ‫  *' ) اا‬+ m ‫ ا>را‬B. '>* ‫ أدرس‬2? '* @, : fm ‫ق‬./‫ أدرس ا‬-

6 ‫ا‬

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