Solve Qua dratics by Comple ting th e Squ are MATH PRO JECT
MODELING COMPLETING THE SQUARE Use algebra tiles to complete a perfect square trinomial. Model the expression x 2 + 6x. Arrange the xtiles to form part of a square. To complete the square, add nine 1tiles.
You have completed the square.
x2
x x x x x x
x x x
1
1
1
1
1
1
1
1
1
x2 + 6x + 9 = (x + 3)2
SOLVING BY COMPLETING THE SQUARE To complete the square of the expression square of half the coefficient of x.
x2 + bx +
2
( ) ( b 2
x2 + bx, add the
= x+ b 2
2
)
Completing the Square
What term should you add to x2 perfect square?
– 8x so that the result is a
SOLUTION
The coefficient of x is –8, so you should add to the expression.
–8 x – 8x + 2 2
2 –8 , or 16,
( 2)
2
( )
= x2 – 8x + 16 = (x – 4)2
Completing the Square
Factor 2x2
–x–2=0
SOLUTION Write original equation.
2x2 – x – 2 = 0
Add 2 to each side.
2x2 – x = 2 1 x – 2 x=1
Divide each side by 2.
2
x2 –
2
( )
1 1 x+ – 2 4
=1+ 1
16
2 1 2 1 1 1 – – • Add = , or 2 2 16 4
(
to each side.
)( )
Completing the Square
x2 –
( )
1 1 x+ – 2 4
(
1 x– 4
x–
2 2 1 1 1 – – • 1 Add = , or 2 2 16 4
2
2
)
(
=1+ 1
16
to each side.
17 = 16
1 = ± 4
x=
Write left side as a fraction.
17 4
1 ± 4
1 The solutions are + 4
)( )
Find the square root of each side.
17 4
1 4
Add to each side.
1 17 – ≈ 1.28 and 4 4
17 ≈ – 0.78. 4
Completing the Square
1 The solutions are + 4 CHECK
1 17 – ≈ 1.28 and 4 4
17 ≈ – 0.78. 4
You can check the solutions on a graphing calculator.
CHOOSING A SOLUTION METHOD Investigating the Quadratic Formula
Perform the following steps on the general quadratic equation ax2 + bx + c = 0 where a ≠ 0.
ax2 + bx = – c
Subtract c from each side.
bx –c x + a+ = a
Divide each side by a.
2
( )= a +( ) b –c + b x + = ( 2a ) a 4a
bx b x + + a 2a 2
2
–c
b 2a 2
2
2
(
b x+ 2a
)
2
– 4ac + b 2 = 2 4a
2
Add the square of half the coefficient of x to each side. Write the left side as a perfect square. Use a common denominator to express the right side as a single fraction.
CHOOSING A SOLUTION METHOD Investigating the Quadratic Formula
(
)
b x+ 2a
2
2 – 4ac + b = 2
4a
b ± x+ = 2a
2
b − 4ac 2a
± b2 − 4ac b x= –
2a
2a
–b ± b − 4ac 2
x=
2a
Use a common denominator to express the right side as a single fraction. Find the square root of each side. Include ± on the right side. Solve for x by subtracting the same term from each side. Use a common denominator to express the right side as a single fraction.