IN TE RS ECT IO N OF LIN ES GRAP HIC AN D ALG EG RA IC
MATH
PR OJECT
1. Find the equation of the line that goes through: a. (-7,-10) & (7,8) b. (-6,8) & (6,-2) 9 y = x −1 7 5 y = − x +3 6
Finding Intersections of Lines Objectives: 1. Discover how to find the intersections of lines graphically and algebraically.
Finding Intersections of Lines Objectives: 2. Solve problems by finding the intersections of lines.
Two ways to find intersections of lines. 1. Graph the lines…..
What is the point of intersection of the following lines:
y = 3x − 5 4 x − 3 y = 10
y = 3 x − 5 1. Graph the lines. 4 x − 3 y = 10 y=3x-5
Solve 4x-3y=10 for y. 4x-3y=10 -4x -4x -3y= -4x+10
y = 3 x − 5 1. Graph the lines. 4 x − 3 y = 10 y=3x-5
-3y= -4x+10 -3y= -4x+10 -3 -3
4 10 y = x− 3 3
y = 3 x − 5 1. Graph the lines. 4 x − 3 y = 10 y=3x-5
This appears to be the point of (1,-2) intersection.
Two ways to find intersections of lines. 1. Graph the lines. 2. Use algebra when graphing does not give you an accurate answer.
Find the intersection of the following lines. y=4x-7 12x+2y=1 Since one of the equations is already solved for y, plug that y value into the other equation and solve for “x”.
y=4x-7 12x+2y=1
12x+2(4x-7)=1
12x+8x-14=1 3 x= 4
20x=15
You know the x-value. Plug the x-value into either equation and solve for “y”. y=4x-7 12x+2y=1
3 x= 4
y=4x-7 3 x= 4
3 y=4( )-7 4
y=
12 4
-7
y=3-7 y=-4
The point of intersection is: 3 x= 4
y=-4
3 ( ,−4) 4
or…
You graph these two lines and see if this looks good. y=4x-7 12x+2y=1 The point of 3 intersection ( ,−4) 4 is:
y=4x-7 12x+2y=1
1 y = −6 x + 2 Point of intersection.
3 ( , − 4) 4
Graph the two equations below. Estimate the point of intersection.
y=3x+5 & y=-6x-4 When finished solving graphically, solve algebraically. Compare your two answers. Which is more accurate?
When you solve graphically….
y=3x+5 y=-6x-4 The point of intersection looks like it is at (-1,2). Now check algebraically to see if this is correct.
y=3x+5 y=-6x-4 Since both 3x+5 and –6x-4 are equal to “y”, set them equal to each other and solve for “x”. 3x+5=-6x-4
3x+5=-6x-4 3x + 5 = -6x - 4 +6x - 5 +6x -5 9x = -9 x = -1
Since x = -1, plug –1 in for x and solve for y in either equation. y=3x+5
y=-6x-4 y=-6(-1) – 4 y= 6 – 4 = 2
When we graphed we got (-1, 2). When we solved algebraically, we got (-1,2). This is the correct answer!
The wrestling club is planning a t-shirt sale to raise funds for a tournament in Hawaii. The tshirt company charges an $80.00 set-up fee and $5.00 for each t-shirt. The wrestling club will sell the shirts for $15.00 each.
- t-shirt company charges $80.00 set-up fee and $5.00 for each t-shirt - Club sells each shirt for $15.00.
Write an equation to represent cost and an equation to represent profit and graph each.
COST 80.00 set-up fee+5.00 per shirt y=5.00x+80 PROFIT 15.00 PER SHIRT y=15.00x
COST y=5.00x+80 PROFIT y=15.00x What does “x” stand for? -Number of shirts sold.
COST y=5.00x+80 PROFIT y=15.00x What does “y” stand for? -either profit or cost
COST y=5.00x+80 PROFIT y=15.00x How many shirts must be sold before it starts making a profit?
COST y=5.00x+80 PROFIT y=15.00x Graph each equation, the point of intersection is the break-even point.
S a l e s
BREAK-EVEN POINT
It’s hard to tell the exact coordinates of the break-even $ # of shirts point, so now you will calculate the point-of-intersection algebraically.
COST y=5.00x+80
PROFIT y=15.00x
5x+80=15x 80 = 10x x=8 Now calculate the “y” value by putting 8 in for “x”.
COST y=5.00x+80
PROFIT y=15.00x
y=15.00(8) y=120 The coordinates of the breakeven point are (8,120).
Every shirt sold after 8 is profit.