Parallel & Perpendicular Part 2

Parallel & Perpendicular Part 2

Okay we learned that parallel lines have the SAME SLOPE.

y = (3/2)x + 3 y = (3/2)x - 4

…and the slopes of perpendicular lines are “opposite flips” of each other.

__ 4 y= x-3 6

_ y=

__ x + 5

What if we are given a specific point ? Well, just plug it into the POINT-SLOPE Form, and solve it!

y – y1 = m(x – x1)

EXAMPLE: Write the formula for a line that is parallel to y = 4x + 4, and runs through the point (2,-3)

y – y1 = m(x – x1) y – (-3) = 4(x – 2) Hmmm.

So,Parallel m must y +means 3 = 4xsame –8 equal 4 !! -3 -3 slope!

y = 4x - 11