Ne100 Tutorial Assignment#3

  • Uploaded by: Jeremy Clements
  • 0
  • 0
  • June 2020
  • PDF

This document was uploaded by user and they confirmed that they have the permission to share it. If you are author or own the copyright of this book, please report to us by using this DMCA report form. Report DMCA


Overview

Download & View Ne100 Tutorial Assignment#3 as PDF for free.

More details

  • Words: 180
  • Pages: 3
TUTORIAL ASSIGNMENT #3 Soumya Mamidala

Name:

NE100 20356922 (a). x=[-10,10]; y=0.3.*x.^(2.5); >> plot(x,y) Warning: Imaginary parts of complex X and/or Y arguments ignored >> grid on >> xlabel('x') >> ylabel('y(x)') >> title('plot of y(x)=0.3*x^(2.5)') (2 0 3 4 5 6 7 8 9 xy1 p

1 8 6 4 2 .l(0 x0 o 5 )t o f y ( x ) = 0 . 3 * x

(b)>>x=[-10:10]; >> y= 50.*x.^(-3); >> plot(x,y) >> grid on >> xlabel('x')

ID:

>> ylabel('y(x)') >> title('plot of y(x)=50*x^-3') -3 8 -6 1 0 2 4 xy5 p

8 6 5 4 3 2 1 l(0 x0 o t) o f y ( x ) = 5 0 * x

(c). >>t=[1:1000:10000]; >> >> >> >> >> >>

v=20.*exp(-t./25); loglog(t,v) grid on xlabel('t') ylabel('exp(-t/25)') title('plot of v(t)=e^(-t/25)')

(50-4321-p 1 te 2 1 5 0

tlx0 5 0 0

p /o t( 2 5 t )o f/ 2 v5 () t ) = e

(d)

given, m=tan(theta); Form the triangle, tan(theta)=b/a; Therefore m=b/a And the given equation is y=mx+b;  y=(b/a)x+b  y=b(x+a)/a  b=ay/(x+a)

Related Documents

Assignment3.docx
May 2020 20
Cs162056-assignment3.docx
December 2019 18
Tutorial
May 2020 17
Tutorial
April 2020 17

More Documents from ""

Property Disclosure Form Sc
October 2019 30
June 2020 43
Research Nobel Sheet
May 2020 32
Foro Semana 1.docx
December 2019 50
June 2020 36