Msa 6 - Week 1 - Key

MSA Review Grade 6 Week 1 Proble Objective m 1 2 3

6.1.B.1.c 6.6.A.1.c 6.6.C.1.c

4 5 6 7 8 9 10 11 12 13 14 15 16 17 18

6.2.A.1.b 6.3.C.1.a 6.5.B.1.b 6.4.A.1.a 6.6.A.1.a 6.1.C.1.a 6.2.A.1.c 6.3.C.1.c 6.4.B.1.b 6.6.A.1.b 6.1.C.1.a 6.2.A.2.b 6.1.C.2.a 6.2.A.2.c 6.2.A.2.c

Answer Calculator Inactive C D A Calculator Active D A B D C B B B A C C C B A Calculator Active Part A: 180˚ – (38˚ + 103˚) = 180˚ – 141˚ = 39˚ Part B: I know that there are a total of 180˚ in any triangle. I added the two known angles together, and then subtracted from the total of 180˚. I know that 38 plus 103 is 141. The total of 180 degrees minus the 141 degrees of the two known angles is the third angle of 39 degrees.

19

6.4.A.1.b

Calculator Active Part A: Calories Burned 19 20 21 22 23 24

2, 5 2, 4 7 0, 6, 7 8, 9 8, 9

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MSA Review Grade 6 Week 1 Part B: My stem-and-leaf plot is correct, because the stems are the digits for the tens and hundreds place. Then across from each stem, I have the leaves, which are the digits in the ones place for each of the data points. If Monica burns 172 calories on her next workout, the stem-andleaf plot would need two more stems. The plot would need 17 and 18 for stems. I would need to add the stem of 17 because those are the digits in the tens and hundreds place for the new data point. I would also need a stem of 18, because previously the lowest stem was 19, and even though there is no data point in the 180’s, you can not skip a stem.

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