Mkk - 16416 - Metalurgi Fisik.rtf

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Nama NPM Prodi

: Usep Miptahudin : 16210719545 : PVTM 4

1.

Hitunglah APF dari struktur atom BCC ? √3 √3 π a 3 3

Vs = 4/3πR = 4/3π ( Vc = a3 APF =

V N atom x s Vc

=

4

√3π 3 a 16 1x 3 a

a)=

=

√3π 8

16

= 0,68

2. Hitung densitas dari Fe dengan struktur atom BCC ? Dik. n = 2 atom A = 55,85 gr/mol R = 0,124 nm = 1,24 x 10-8 cm NA = 6,02 x 1023 atom/mol Dit. ρ ............? Jawab : ρ=

2 x 55,85

64 ( 1,24 x 10−8 ) x (6,02 x 1023) 3√3 111,7 ρ= 14,1 3 ρ=7,92 g/cm

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