Metrados.docx

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METRADOS Área del terreno: 7 π‘₯ 6 = 42π‘š2 Volumen de excavaciΓ³n para cimiento a 0.80 y 0.60: Eje 1-1 y 2-2: (7π‘₯0.8π‘₯0.4)π‘₯2

= 4.48π‘š3

(5.12π‘₯0.8π‘₯0.4)π‘₯2 = 1.6384π‘š3 3π‘₯0.8π‘₯0.4

= 0.96π‘š3

2.87π‘₯0.8π‘₯0.4

= 0.9184π‘š3

1.7π‘₯0.6π‘₯0.3

= 0.306π‘š3

2π‘₯0.6π‘₯0.3

= 0.36π‘š3

2.85π‘₯0.6π‘₯0.3

= 0.513π‘š3

TOTAL DE VOLUMEN

= 9.18π’ŽπŸ‘

Volumen a vaciar para sobrecimiento: Eje 1-1 y 2-2: (6.25π‘₯0.3π‘₯0.25) = 0.47π‘š3 (5.15π‘₯0.3π‘₯0.25) = 0.39π‘š3 (5.25π‘₯0.3π‘₯0.25)π‘₯2 = 0.40π‘š3 = 0.908π‘š3

(2.87 + 2.63 + 2 + 0.9 + 2 + 1.7)π‘₯0.3π‘₯0.25 TOTAL DE VOLUMEN

= 𝟐. πŸπŸ•π’ŽπŸ‘

Encofrado y desencofrado de sobrecimiento: (6.25π‘₯0.3) = 1.875π‘š3 (5.15π‘₯0.3) = 1.545π‘š3 (5.25π‘₯0.3)π‘₯2 = 3.15π‘š3 (2.87 + 2.63 + 2 + 0.9 + 2 + 1.7)π‘₯0.3 TOTAL PARA ENCOFRAR

= 3.63π‘š3

= 𝟏𝟎. πŸπ’ŽπŸ

Falso piso de 2”: (6.75π‘₯5.75) = 38.81π‘š2 (2.87 + 2.63 + 2 + 0.9 + 2 + 1.7)π‘₯0.25

= 3.025π‘š2

TOTAL PARA EL FALSO PISO(DIFERENCIA)

= πŸ‘πŸ“. πŸ•πŸ–πŸ“π’ŽπŸ

Solado para zapata de 3”: (0.8π‘₯0.8π‘₯0.0762)π‘₯4 = 0.195π‘š3 (1π‘₯1π‘₯0.0762) = 0.0762π‘š3 TOTAL DE VOLUMEN PARA SOLADO DE ZAPATAS = 𝟎. πŸπŸ•π’ŽπŸ‘

Volumen de zapatas: Zapata esquinera: (0.8π‘₯0.8π‘₯0.5)π‘₯4 = 1.28π‘š3

Zapata perimetral: (1π‘₯1π‘₯0.5) = 0.5π‘š3

Metrado de muro de cabeza (altura de muro 2.40m) (3.55π‘₯0.25π‘₯2.34) = 2.132π‘š3 (2.70π‘₯0.25π‘₯1.8) = 1.215π‘š3 (4.25π‘₯0.25π‘₯2.4) = 2.55π‘š3 (3.55π‘₯0.25π‘₯2.34) = 2.132π‘š3 (2π‘₯0.25π‘₯1.8) = 0.9π‘š3 (2.85π‘₯0.25π‘₯2.4) = 1.71π‘š3 (2.4π‘₯0.25π‘₯1.8) = 1.08π‘š3 (4.05π‘₯0.25π‘₯2.4) = 2.43π‘š3 (12.1π‘₯0.25π‘₯2.4) = 7.26π‘š3 TOTAL DE VOLUMEN PARA ASENTAR MURO DE CABEZA = πŸπŸ—. πŸπŸ•πŸ“π‘š3

Metrado de columnas(volumen) (0.25π‘₯0.25π‘₯2.2)π‘₯9 = 1.238π‘š3 TOTAL DE VOLUMEN A VACIAR EN COLUMNAS = 1.238π’ŽπŸ‘ Tarrajeo(exteriores): (7π‘₯0.02π‘₯2.2)π‘₯2 = 0.616π‘š3 (6π‘₯0.02π‘₯2.2)π‘₯2 = 0.528π‘š3 TOTAL DE VOLUMEN A TARRAJEAR EN EXTERIORES = 1.144π’ŽπŸ‘

Metrado de la losa: (6π‘₯7π‘₯0.2) = 8.4π‘š3 (1.4π‘₯0.6π‘₯0.2) = 0.168π‘š3 RESTO TOTAL DEL VOLUMEN = 8.232π’ŽπŸ

(6π‘₯7) = 42π‘š2 TRAGALUZ (1.4π‘₯0.6) = 0.84π‘š2 RESTO TOTAL DEL AREA = 41.16π’ŽπŸ

(41.16π‘₯0.05) = 2.058π‘š3 (7/3) = 23.3 = 24 𝐸𝑆𝑃𝐴𝐢𝐼𝑂𝑆 (0.15π‘₯0.05π‘₯24) = 0.18π‘š3 TOTAL DE VOLUMEN DE CONCRETO = 2.238π’ŽπŸ‘

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