SULIT 1449/2 Matematik Kertas 2 Mei 2008 2½ jam
1449/2
SEKOLAH-SEKOLAH MENENGAH NEGERI PAHANG PEPERIKSAAN PERCUBAAN SPM 2008
MATEMATIK Kertas 2 PERATURAN PERMARKAHAN
UNTUK KEGUNAAN PEMERIKSA SAHAJA
Question 1(a)
Solution and Mark Scheme
Marks K1
3
(b) K2
2
3.
⎛ 1 4 22 3 ⎞ ⎜ × × ×7 ⎟ ⎝2 3 7 ⎠ ⎞ ⎛ 1 4 22 ⎞ ⎛ 1 22 1155 = ⎜ × × 7 2 × h ⎟ + ⎜ × × × 7 3 ⎟ ⎝3 7 ⎠ ⎝2 3 7 ⎠ 154h = 1309 h = 8.5 cm
Kenalpasti sudut ∠ BFC or ∠ CFB 9 Tan ∠ BFC = 8 ∠ BFC = 41.630 or 410 38’
K1 K1 K1 N1
P1 4 K1K1 N1
4(a)
True
P1
(b)
If 3x = 1 then x = 0
K1
If x = 0 then 3x = 1
K1
(c)
2(3)n + n ; n = 1, 2,3, …
4
5
K1K1 4
5.
9v + 6w = 42 atau setara 10v = 40 atau setara v=4 w=1
K1 K1 N1 N1
6
7 (a)
4p2 -4p-15 =0 (2p+3)(2p-5) =0 −3 5 p= atau p = 2 2 4 m kl = 3 LM; x=2 -4 = -
(b)
K1 K1 N1N1 P1
K1
−4 x + 4 atau 3y = -4x + 12 3
(b)
9 (a)
k=4 v=6
P1 P1
⎛ x⎞ 1 ⎜⎜ ⎟⎟ = ⎝ y ⎠ (7 × −2) − (−6 × 3)
⎛ − 2 6⎞ ⎟⎟ ⎜⎜ ⎝ − 3 7⎠
⎛ 5⎞ ⎜⎜ ⎟⎟ ⎝1⎠
NI N1
22 ⎤ 22 ⎡ 120 ⎡ 105 ⎤ ⎢⎣ 360 × 2 × 7 × 7⎥⎦ atau ⎢⎣ 360 × 2 × 7 × 14⎥⎦
K1
44 77 + 3 3
1 cm. 3 ⎡ 120 22 2 ⎤ ⎡ 60 22 2 ⎤ ⎡ 105 22 2⎤ ⎢⎣ 360 × 7 × 7 ⎥⎦ or ⎢⎣ 360 × 7 × 7 ⎥⎦ or ⎢⎣ 360 × 7 × 14 ⎥⎦
68
2 2⎞ ⎛ 1 ⎜ 51 + 179 − 25 ⎟ 3 3⎠ ⎝ 3 1 616 2 205 cm 2 atau cm 3 3
6
K2
x= -1 y = -2
7 + 7 + 14 +
(b)
KI N1
y-intercept is 12 8 (a)
5
N1
4 (6) + catau setara 3
MN; y =
4
K1
NI K1
K1
N1
6
10(a)
(b)(i)
(ii)
11(a) (b)
(c)
16 25
⎛ 15 14 ⎞ ⎛ 10 9 ⎞ ⎜ × ⎟+⎜ × ⎟ ⎝ 25 24 ⎠ ⎝ 25 24 ⎠ 1 2 ⎛ 16 15 ⎞ ⎜ × ⎟ ⎝ 25 24 ⎠ 2 5
6s 6 − 12 8−0
K1 K1
N1 5 K1
N1
P1 K1 6 N1
-0.75
⎡1 ⎤ 156m = ⎢ (6 + u )6⎥ + 6u ⎣2 ⎦ u = 10
K1 N1
Question
12(a)
(b)
Solution and Mark Scheme
Marks
3
K1
-2
K1
2
Graph Axes drawn in correct direction, uniform scale for − 5 ≤ x ≤ 1 and − 2 ≤ y ≤ 7
P1
7 point and *2 points correctly plotted or curve passes through these points for − 5 ≤ x ≤ 1 .
K2
smooth and continuous curve without any straight line and passes through all 9 correct points using the given scale for −5 ≤x ≤ 3 .
N1
4
Note: 7 or 8 points correctly plotted, award K1 (c)(i) (ii)
(d)
4.65 ≤ y ≤ 4.80
P1
− 0.2 ≤ x ≤ − 0.4 − 3.85 ≤ x ≤ − 3.65
P1 P1
Identify equation y = - x
K1
Straight line y = - x correctly drawn
K1
3
Values of x : − 3.85 ≤ x ≤ − 3.7 0.7 ≤ x ≤ 0.9
N1
3
Note: Values of y and x obtained by computations, award P0N0
12
Question
Solution and Mark Scheme
Marks
13(a)
Correct shape with rectangles KLPS and PQRS . All solid lines. KL > DL > LI
K1
Measurements correct to ± 0.2 cm (one way) and All angles at vertices of rectangles = 90o ± 1o
K1 3
N1
Question
Solution and Mark Scheme
Marks
(b)
Question
Correct shape with rectangle MJHI and trapezium ABMH . All solid lines.
K1
JB > JI = MH > BM > MJ = HI
K2
Measurements correct to ± 0.2 cm (one way) and All angles at vertices of rectangles = 90o ± 1o
N2
Solution and Mark Scheme
5
Marks
(c)
Correct shape with rectangles HGIL and MHJI and square ADHG. All solid lines.
K1
JL > DL = AI > DG = HG > GL = HI=MJ
K1
Measurements correct to ± 0.2 cm (one way) and All angles at vertices of rectangles = 90o ± 1o
K1
N2
5 12
Question
Solution and Mark Scheme
Marks
14(a)
120o E θ E , award P1
Note: 120o or (b)
P2
40 x 60 x cos 450
K2
1697.06
N1
2
3
Notes: cos 45 used correctly, award K1 (c)
(d)
4500 or 750 60 75 - 45
K1
300S
N1
K1
10800 750 =
3
K1 10800 T
K2
14.4
N1
4
12
Question
Solution and Mark Scheme
Marks
15(a)(i)
P1
( 8, -1) Note: point (8 , -1) marked on the diagram award P1
(ii)
(5 , 5)
P2
Note: point (5 , 5) marked on diagram, award P1 ( 9, 5 )
(iii)
P2
Rotation 180o , centre (3,3)
(iv)
5
P3
Note: 1. P2: Rotation 180o, Rotation 180o , centre G 2. P1: Rotation 180o (v) Enlargement centre N(6,1) with scale factor 3
P3
Note: 1. P2: Enlargement centre N or Enlargement scale factor 2 2. P1: Enlargement
(ii)
160 22
K1
40
N1
8 12
Question
Solution and Mark Scheme
Marks
16(a)
Mass(kg) 30 35 40 45 50 55
-
34 39 44 49 54 59
Frequency
Midpoint
5 6 9 8 7 5
32 37 42 47 52 57
I II III IV V VI
Class interval :
(III to VI)
P1
Frequency
:
(I to VI)
P2
Midpoint
:
(I to VI)
P1 4
Note: Allow one mistake in frequency for P1.
(b)
32(5) + 37(6) + 42(9) + 47(8) + 52(7) + 57(5) 5+6+9+8+7+5
K2
44.63
N1 3
Notes: Allow two mistakes for K1. ( c)
Axes drawn in correct direction, uniform scale for 29.5 ≤ x ≤ 59.5 and 0 ≤ y ≤ 9
P1
Using lower boundry or upper boundry or midpoint or class interval for x-axis.
K1
* 6 bar correctly drawn Note: * 5 bar correctly drawn, award N1
N2
(d)
4
K1 example: Most of the telephone bill is between 40 to 44
1 12
Graph for Question 16 Graf untuk Soalan 16
9
8
7
6
5
4
3
2
1
29.5
34.5
39.5
44.5
49.5
54.5
END OF MARK SCHEME
59.5