Matematik > Skema Spm Mat Kertas 2 Set 1

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PERATURAN PEMARKAHAN LEARNING TO SCORE MATEMATIK SPM KERTAS 2 SET 1 Soalan 1

Peraturan Pemarkahan

Markah

(a)

1

(b) 2 3 ⅓ π ×72 × 12 ⅓ π × 3.52 × 6 ⅓ π × 72 ×12 – ⅓ π × 3.52 × 6 3773

2

1 1 1 1 4

3

(a)

∠VCA atau ∠ACV

(b)

8 Tan ∠VCA = 6

∠VCA = 53.13o atau 53o 8’

1 2 1 4

4

(a)

Pernyataan

1

(b)

Jika 102 = 100, maka log10 100 = 2. Jika log10 100 = 2, maka 102 = 100.

1 1

(c)

q boleh dibahagi tepat dengan 2

2 5

5

2p + 2q = 3 atau

2 p – 2q = 4 3

3p= 9 atau -3q = 3 p= 3 q=-1

1 1 1 1

4

1

6

(a)

1

2 c=–8 y = 2x – 8

1 1

(b) m = – 2

1

pintasan - y = 20

1 5

2k2 + 5k – 3 = 0 (2k –1) (k + 3) = 0 1 k = 2 k=–3

7

1 1 1 1 4

8

(a) (b)

1 , p = -6 14  2 − 1  x   3      =    6 4   y   − 5  x  1  4 1  3    =      y  14  − 6 2   − 5 

n=

1 dan y = - 2 2 60 22 1 x x14x14 atau - x7x7 sin 60o atau setara 360 7 2

x= 9

(a)

60 22 1 x x14x14 - x7x7 sin 60o 360 7 2 81.45 (b)

10 (a)

1 22 1 22 x2x x14 atau x2x x7 6 7 3 7 1 22 1 22 x14) +7 + ( x2x x7) 7+7+7+( x2x 6 7 3 7 1 57 3 1 10 × 12 22 10 5 atau 264 132

1, 1 1 1

1,1

6

1 1 1

1 1 1

6

1 1

2

(b)

6 10 5 8 1 4 × + × + × 12 22 12 22 12 22 13 33

2 1 5

11 (a) (b)

1

20

1 × 5 × 60 2

1 1

150 (c)

1

½ × 4 × 80 atau ½(60 + 80)(1)

1

[½ × 4 × 80 + ½(60 + 80)(1)] – 150

1

80 12

13

(a)

k=1 m=–5

1 1

(b)

graf

5

(c)

y = – 0.8 x = – 1.25

1 1

(d)

y = 1-x graf y =1-x

1 1

2.1 ≤ x ≤ 2.2

1

(-1, 2) ( 2,1) (-2,-1)

(a)

(i) (i) (iii)

(b)

(i) V : Pembesaran pada ttik (-2, 1) dengan factor skala 2

6

12

1 2 2 3

Nota: Pembesaran pada titik (-2,1) atau Pembesaran dengan factor skala 2 Pembesaran

(2) (1)

 − 2   4 

2

W: translasi  Nota

Translasi

(1)

3

(ii)

14

(a) (b)

14 X 2* 2 56

1 1 1

30 (i) Kekerapan 3 6 8 7 9 6 1

Titik tengah 142 147 152 157 162 167 172

Sempadan atas 144.5 149.5 154.5 159.5 164.5 169.5 174.5

(ii) (3x142)+(6x147)+(8x152)+(7x157)+(9x162)+(6x167)+(1x172) 40 = 156.375cm (c) Histogram (d) Kelas mod ialah 15

12

2 1 1

2 1 3 1

160-164

12

(a) N

2 cm

M X 2 cm

1 1

6 cm

L 5 cm

J

K

4 cm

1

U

4

Y

N 2 cm

(b) (i)

1

M

Q C

4 cm

2 X

4 cm

Z

Z M (ii)

1

C 1

Q

1 cm X

W

L’

R’

1 1 7 cm

4 cm

U

4 cm

V

3 cm

2

D 12

16

(a)

110o T

(b)

4800 60 4800 – 60 60 20o S

(c)

(d)

penggunaan kos 60o 180 × 60 × kos 60o 5400 60X60

60 X 60 + 4800 560

1,1 1 1 1,1 1 1 1 1 1

15 1

12

5

Lampiran Jawapan Soalan 12

15

10

5

0 -6

-4

-2

0

2

4

6

-5

-10

-15

6

Lampiran Soalan 14

Kekerapan

9 8 7 6 5 4 3 2 1 0 139.5

144.5 149.5 154.5 159.5 164.5 169.5 174.5

Tinggi (cm)

7

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