Lemper Abs.docx

LEMBAR PERHITUNGAN

1. n CO2 terserap (mol/s) a) Variabel 1 ( 3,4 ml/s) t = 0 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(3,7𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,26 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,26

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 0,89 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 1 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,35 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,35

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 1,21 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 2 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4,2𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,29 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,29

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 1,01 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 3 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,28 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,28

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 0,97 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 4

N CO2 terserap = N Na2CO3 = =

2𝑏 × 𝑁 𝐻𝐶𝑙 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 2(4,2𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,29 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,29

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 1,01𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 5 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(3,6𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,25 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,25

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 0,87 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 6 N CO2 terserap = N Na2CO3 = =

2𝑏 × 𝑁 𝐻𝐶𝑙 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 2(3,8𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,26 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,26

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 0,92 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 7 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(3,4𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,23 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,23

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 0,82 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 8 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(3,1𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,21 mol/L n CO2 terserap = N CO2 terserap × Q NaOH

= 0,21

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 0,75 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 9 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(3,7𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,26 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,26

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 0,89 𝑥 10−3 𝑚𝑜𝑙/𝑠  t = 10 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4,5𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,31 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,31

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 1,09 𝑥 10−3 𝑚𝑜𝑙/𝑠 t

Va (ml)

Vb (ml)

0 1 2 3 4 5 6 7 8 9 10 Rata-Rata

3,4 3,5 1,7 1,5 2,6 2,4 2,1 2,2 2,4 2,9 3,3 2,54

3,7 5 4,2 4 4,2 3,6 3,8 3,4 3,1 3,7 4,5 3,93

N CO2 terserap (mol/L) 0,26 0,35 0,29 0,28 0,29 0,25 0,26 0,23 0,21 0,26 0,31 0,27

b) Variabel 2 t = 0 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4,7𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,32 mol/L n CO2 terserap = N CO2 terserap × Q NaOH

n CO2 terserap (mol/s) 0,89X10-3 1,21X10-3 1,01X10-3 0,97X10-3 1,01X10-3 0,87X10-3 0,92X10-3 0,82X10-3 0,75X10-3 0,89X10-3 1,09X10-3 0,95X10-3

= 0,32

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,46 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 1 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,4𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,37 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,37

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,68 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 2 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,1𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,35 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,35

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,58 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 3 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4,9𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,34 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,34

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,52 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 4 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4,5𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,31 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,31

mol L

× 3,5 𝑥 10−3 𝐿/𝑠

= 1,40 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 5 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖

=

2(4,2𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,29 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,29

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,30 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 6 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,0𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,35 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,35

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,55 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 7 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,2𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,36 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,36

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,61 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 8 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4,6𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,32 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,32

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,43 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 9 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,3𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,37 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,37

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,65 𝑥 10−3 𝑚𝑜𝑙/𝑠

 t = 10 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,5𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,38 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,38

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 1,71 𝑥 10−3 𝑚𝑜𝑙/𝑠 t

Va (ml)

Vb (ml)

0 1 2 3 4 5 6 7 8 9 10 Rata-Rata

4,4 4,8 4,2 4,1 3,9 3,8 4,7 4,5 4,2 4,6 5,0 4,38

4,7 5,4 5,1 4,9 4,5 4,2 5,0 5,2 4,6 5,3 5,5 4,95

N CO2 terserap (mol/L) 0,32 0,37 0,35 0,34 0,31 0,29 0,35 0,36 0,32 0,37 0,38 0,34

c) Variabel 3 t = 0 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(4,8𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,33 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,33

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 1,82 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 1 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,8𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,40 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,40

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 2,20 𝑥 10−3 𝑚𝑜𝑙/𝑠

n CO2 terserap (mol/s) 1,46X10-3 1,68X10-3 1,58X10-3 1,52X10-3 1,40X10-3 1,30X10-3 1,55X10-3 1,61X10-3 1,43X10-3 1,65X10-3 1,71X10-3 1,54X10-3

t = 2 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,6𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,39 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,39

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 2,13 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 3 N CO2 terserap = N Na2CO3 = =

2𝑏 × 𝑁 𝐻𝐶𝑙 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 2(5,3𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,37 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,37

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 2,01 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 4 N CO2 terserap = N Na2CO3 = =

2𝑏 × 𝑁 𝐻𝐶𝑙 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 2(5,7𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,39 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,39

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 2,16 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 5 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(6,1𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,42 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,42

mol L

× 4,5 𝑥 10−3 𝐿/𝑠

= 2,31 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 6 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,8𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,40 mol/L

n CO2 terserap = N CO2 terserap × Q NaOH = 0,40

mol L

× 5,5 𝑚𝐿/𝑠

= 2,20 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 7 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,9𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,41 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,41

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 2,24 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 8 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(5,7𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,39 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,39

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 2,16 𝑥 10−3 𝑚𝑜𝑙/𝑠 t = 9 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(6,0𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,41 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,41

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 2,28 𝑥 10−3 𝑚𝑜𝑙/𝑠  t = 10 2𝑏 × 𝑁 𝐻𝐶𝑙

N CO2 terserap = N Na2CO3 = 𝑉𝑎𝑙𝑒𝑛𝑠𝑖 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 =

2(6,3𝑚𝑙) × 0,69𝑁 2 × 10 𝑚𝑙

= 0,43 mol/L n CO2 terserap = N CO2 terserap × Q NaOH = 0,43

mol L

× 5,5 𝑥 10−3 𝐿/𝑠

= 2,39 𝑥 10−3 𝑚𝑜𝑙/𝑠 t

Va (ml)

Vb (ml)

N CO2 terserap (mol/L)

n CO2 terserap (mol/s)

0 1 2 3 4 5 6 7 8 9 10 Rata-Rata

4,5 5,3 5,2 4,8 5,1 5,6 5,3 5,5 5,2 5,4 5,8 5,25

4,8 5,8 5,6 5,3 5,7 6,1 5,8 5,9 5,7 6,0 6,3 5,73

1,81X10-3 2,20X10-3 2,13X10-3 2,01X10-3 2,16X10-3 2,31X10-3 2,20X10-3 2,24X10-3 2,16X10-3 2,28X10-3 2,39X10-3 2,17X10-3

0,33 0,40 0,39 0,37 0,39 0,42 0,40 0,41 0,39 0,41 0,43 0,40

2. KGA (Tetapan Perpindahan massa CO2 Fase gas) ℰ=

𝑉𝑣𝑜𝑖𝑑

=

𝑉𝑡

=

𝑉𝑣𝑜𝑖𝑑 𝜋𝐷2 𝐻 4

135𝑐𝑚3 3,14 × 3,32 × 30,3 𝑐𝑚 4

= 0,52 𝐴=

𝜋 × 𝐷2 4

=

3,14 × 3,32 𝑐𝑚 4

= 8,55𝑐𝑚2 a) Variabel 1 𝐾𝐺𝐴 =

𝑟𝑎𝑡𝑎−𝑟𝑎𝑡𝑎 𝑛 𝐶𝑂2 𝑡𝑒𝑟𝑠𝑒𝑟𝑎𝑝 𝐴×𝑍×ℇ×𝑃 0,95×106

= 8,55×0,9×0,52×(7,4×106 ) = 3,21 x 10-11 b) Variabel 2 𝐾𝐺𝐴 =

𝑟𝑎𝑡𝑎−𝑟𝑎𝑡𝑎 𝑛 𝐶𝑂2 𝑡𝑒𝑟𝑠𝑒𝑟𝑎𝑝 𝐴×𝑍×ℇ×𝑃 1,54×106

= 8,55×1,6×0,52×(7,4×106 ) = 5,2 × 10−11 c) Variabel 3 𝐾𝐺𝐴 =

𝑟𝑎𝑡𝑎−𝑟𝑎𝑡𝑎 𝑛 𝐶𝑂2 𝑡𝑒𝑟𝑠𝑒𝑟𝑎𝑝 𝐴×𝑍×ℇ×𝑃 2,17×106

= 8,55×2,1×0,52×(7,4×106 ) = 7,33 × 10−11 Variabel

n CO2 terserap

KGA

3,4

0,95x10-3

3,21× 10−11

4,5

1,54x10-3

5,2× 10−11

5,5

2,17x10-3

7,33 × 10−11

3. KLA a) Variabel 1 𝑔

−Δ𝑃 = Δ𝑍 × (𝜌𝐻𝑔 − 𝜌𝐶𝑂2 ) 𝑔𝑐 = 0,9 𝑐𝑚 × (13554 = 20197,8 kg/𝑚 2𝛼×𝑔𝑐×(

𝑉𝐶𝑂2 = √

=√

𝑘𝑔 𝑚3

− 1264 𝑘𝑔/𝑚3 )

9,8 1

2

−∆𝑃 )Σ𝐹 𝜌𝐶𝑂2

𝑆1 −1 𝑆2

20197,8 kg/𝑚2 )(1) 1264 𝑘𝑔/𝑚3 3,46×10−4 𝑚2 −1 1,77×10−4 𝑚2

2(1)×1 𝑚/𝑠2 ×(

= 5,79 m/sec 𝑄 𝐶02 = 𝑉𝐶𝑂2 × 𝑆2 = 5,79

𝑚 𝑠𝑒𝑐

× (1,77 × 10−4 𝑚2 )

= 1,02 × 10−3 𝑚3 /𝑠𝑒𝑐 b) Variabel 2 𝑔

−Δ𝑃 = Δ𝑍 × (𝜌𝐻𝑔 − 𝜌𝐶𝑂2 ) 𝑔𝑐 = 1,6 𝑐𝑚 × (13554

𝑘𝑔 𝑚3

− 1264 𝑘𝑔/𝑚3 )

9,8 1

= 192707,2 kg/𝑚2 2𝛼×𝑔𝑐×(

𝑉𝐶𝑂2 = √

=√

−∆𝑃 )Σ𝐹 𝜌𝐶𝑂2

𝑆1 −1 𝑆2

192707,2 kg/𝑚2 )(1) 1264 𝑘𝑔/𝑚3 −4 2 3,46×10 𝑚 −1 1,77×10−4 𝑚2

2(1)×1 𝑚/𝑠2 ×(

= 14,83 m/sec 𝑄 𝐶02 = 𝑉𝐶𝑂2 × 𝑆2 = 14,83

𝑚 𝑠𝑒𝑐

× (1,77 × 10−4 𝑚2 )

= 2,63 × 10−3 𝑚3 /𝑠𝑒𝑐 c) Variabel 3 𝑔

−Δ𝑃 = Δ𝑍 × (𝜌𝐻𝑔 − 𝜌𝐶𝑂2 ) 𝑔𝑐 = 2,1 𝑐𝑚 × (13554 = 252928,2 kg/𝑚 2𝛼×𝑔𝑐×(

𝑉𝐶𝑂2 = √

2

−∆𝑃 )Σ𝐹 𝜌𝐶𝑂2

𝑆1 −1 𝑆2

𝑘𝑔 𝑚3

− 1264 𝑘𝑔/𝑚3 )

9,8 1

252928,2 kg/𝑚2 )(1) 1264 𝑘𝑔/𝑚3 −4 2 3,46×10 𝑚 2 −1 1,77×10−4 𝑚

2(1)×1 𝑚/𝑠2 ×(

=√

= 20,47 m/sec 𝑄 𝐶𝑂2 = 𝑉𝐶𝑂2 × 𝑆2 = 20,47

𝑚 𝑠𝑒𝑐

× (1,77 × 10−4 𝑚2 )

= 3,62 × 10−3 𝑚3 /𝑠𝑒𝑐 𝜌 NaOH 1% (20oC)

= 1.0207 kg/L

𝜌 NaOH 2% (20oC)

= 1.0428 kg/L

Interpolasi 𝑦 − 𝑦1 𝑥 − 𝑥1 = 𝑦2 − 𝑦1 𝑥2 − 𝑥1 𝑦 − 1.0207 𝑘𝑔/𝐿 2.49% − 2% = 1.0428 𝑘𝑔/𝐿 − 1.0207𝑘𝑔/𝐿 4% − 2% 𝜌 NaOH 2.49% (20oC) = 1.026 kg/L % massa dan vikositas NaOH pada suhu 20oC NaOH 0%: 𝜇 NaOH

= 1.00 centipoise = 1.00 x 10-3 kg/m.s

NaOH 5 %: 𝜇 NaOH

= 1.31 centipoise

= 1.31 x 10-3 kg/m.s 𝑦 − 𝑦1 𝑥 − 𝑥1 = 𝑦2 − 𝑦1 𝑥2 − 𝑥1 2.49% − 0% 𝑥 − 1.00 × 10−3 kg/m. s = (1.31 × 10−3 − 1.00 × 10−3 )kg/m. s 5% − 0% = 1.15x 10-3 kg/m. s

𝜇 NaOH

(Common Fluid – Pumping Sodium Hydroxide with Liquiflo Gear Pumps, 2001) 𝑎= =

6(1−ℰ) 𝑑𝑝 6(1−0,52) 𝑑𝑝

𝐷𝑎 = 2,1 × 10−9 𝑚/𝑠

1)

𝐾𝐺𝐴×𝑑𝑝2 𝐷𝑎

𝑅𝑇 = 4,0777 × (

𝑚𝑜𝑙 3 .𝑚 .𝑠)×𝑑𝑝2 𝑝𝑎 2,1×10−9 𝑚2 /𝑠

(3,21×10−11

(

𝜌𝐶𝑂2 ×𝑄𝐶𝑂2 1,4003 𝜇𝐶𝑂2 ×𝑎

× (𝜌𝐶𝑂

2 ×𝐷𝑎

)

1⁄ 3

𝑚3

(8,314 𝑃𝑎. 𝑚𝑜𝑙 . 𝐾) (303,15𝐾) = 4,0777 ×

𝑚3 𝑚3 ) .𝐾×(1,02×10−3 𝑚𝑜𝑙 𝑠 6(1−0,52) (15×10−6 kg/ms)×( ) 𝑑𝑝

1264 𝑃𝑎.

)

𝜇𝐶𝑂2

1,4003

)

15×10−6 𝑘𝑔/𝑚𝑠

× (1264×2,1×10−9 𝑚2 /𝑠)

1⁄ 3

38,526𝑑𝑝2 = 4,0777 𝑥 (29844,44 𝑑𝑝) 1.4003 𝑥 1,7812 m

𝑑𝑝 = 1,721 x 109

2)

𝐾𝐺𝐴×𝑑𝑝2 𝐷𝑎

𝜌𝐶𝑂2 ×𝑄𝐶𝑂2 1,4003

𝑅𝑇 = 4,0777 × (

𝑚𝑜𝑙 3 .𝑚 .𝑠)×𝑑𝑝2 𝑝𝑎 2,1×10−9

(5,2×10−11

(

)

𝜇𝐶𝑂2 ×𝑎

𝜇𝐶𝑂2

× (𝜌𝐶𝑂

2 ×𝐷𝑎

)

1⁄ 3

𝑚3

(8,314 𝑃𝑎. 𝑚𝑜𝑙 . 𝐾) (303,15𝐾) = 4,0777 × 1,4003

𝑚3 𝑚3 .𝐾×(2,63×10−3 ) 𝑚𝑜𝑙 𝑠 6(1−0,52) (15×10−6 kg/ms)×( ) 𝑑𝑝

1264 𝑃𝑎.

1⁄ 3

15×10−6 𝑘𝑔/𝑚𝑠

)

× (1264×2,1×10−9 𝑚2 /𝑠)

62,41𝑑𝑝2 = 4,0777 𝑥 (76951,852 𝑑𝑝) 1.4003 𝑥 1,7812 m 𝑑𝑝 = 7,026 x 109

3)

𝐾𝐺𝐴×𝑑𝑝2 𝐷𝑎

𝜌𝐶𝑂2 ×𝑄𝐶𝑂2 1,4003

𝑅𝑇 = 4,0777 × (

(7,33×10−11 )×𝑑𝑝2 2,1×10−9

)

𝜇𝐶𝑂2 ×𝑎

𝜇𝐶𝑂2

×(

𝜌𝐶𝑂2 ×𝐷𝑎

(8,314)(303,15𝐾) = 4,0777 × (

)

1⁄ 3

1264×(3,62×10−3 ) (15×10−6 )×(

6(1−0,52) ) 𝑑𝑝

1⁄ 3

15×10−6

(1264×2,1×10−9 )

87,974𝑑𝑝2 = 4,0777 𝑥 (105918,518 𝑑𝑝) 1.4003 𝑥 1,7812 m 𝑑𝑝 = 8,357 x 109 𝑑𝑝 𝑟𝑎𝑡𝑎 − 𝑟𝑎𝑡𝑎 =

17,104 𝑥 109 3

= 5,701 x 109

6(1−ℰ)

𝑎 = 𝑑𝑝 𝑟𝑎𝑡𝑎−𝑟𝑎𝑡𝑎 6(1−0,52)

= 5,701 𝑥 109 = 5,052 𝑥 10−10 𝐾𝐿𝐴×𝑑𝑝 𝐷𝑎

= 0,2258 × (

𝜌𝑁𝑎𝑂𝐻×𝑄𝑁𝑎𝑂𝐻 0,3 𝜇𝑁𝑎𝑂𝐻×𝑎

)

𝜇𝑁𝑎𝑂𝐻

× (𝜌𝑁𝑎𝑂𝐻×𝐷𝑎)

0,5

 Kla Variabel 1 (3,5 ml/sec) 𝐾𝑙𝑎×5,701 𝑥 109 𝑚 2,1×10−9 𝑚2 /𝑠

𝑘𝑔 𝐿 ×3,5𝑥10−3 𝐿 𝑠 𝑘𝑔 (1,15×10−3 )×5,052 𝑥 10−10 𝑚𝑠

= 0,2258 × (

𝑘𝑔 𝐿 𝑘𝑔 1,026 ×(2,1×10−9 𝑚2 /𝑠) 𝐿

(

1,15×10−3

0,3

1,026

/𝑚

)

×

0,5

)

𝐾𝑙𝑎 = 5,261 𝑥 10−10 𝑚3 /s  Kla Variabel 2 (4,5 ml/sec) 𝐾𝑙𝑎 × 5,701 𝑥 109 𝑚 2,1 × 10−9 𝑚2 /𝑠

= 0,2258 × (

1,026 (1,15 × 10−3

1,15 × 10−3

×( 1,026

𝑘𝑔 𝐿 × 4,5𝑥10−3 𝐿 𝑠 ) 𝑘𝑔 ) × 5,052 𝑥 10−10 /𝑚 𝑚𝑠

𝑘𝑔 𝐿

𝑘𝑔 × (2,1 × 10−9 𝑚2 /𝑠) 𝐿

0,5

)

0,3

1,4003

)

×

𝐾𝑙𝑎 = 5,673 𝑥 10−10 𝑚3 /s  Kla Variabel 3 (5,5 ml/sec) 𝐾𝑙𝑎 × 5,701 𝑥 109 𝑚 2,1 × 10−9 𝑚2 /𝑠 1,026

= 0,2258 × (

(1,15 × 10−3 1,15 × 10−3

×( 1,026

𝑘𝑔 𝐿 × 5,5𝑥10−3 𝐿 𝑠 ) 𝑘𝑔 ) × 5,052 𝑥 10−10 /𝑚 𝑚𝑠

0,3

0,5

𝑘𝑔 𝐿

𝑘𝑔 × (2,1 × 10−9 𝑚2 /𝑠) 𝐿

)

𝐾𝑙𝑎 = 6,025 𝑥 10−10 𝑚3 /s Debit NaOH (ml/sec) 3,5 4,5 5,5

-ΔP (kg/ms) 20197,8 192707,2 252928,2

dp (m) 1,721 x 109 7,026 x 109 8,357 x 109

𝒌𝑳𝑨 (m3/s) 5,261 𝑥 10−10 5,673 𝑥 10−10 6,025 𝑥 10−10

4. K2 𝑅𝑎 = 𝑄 𝑁𝑎𝑂𝐻 × 𝑁 𝐶𝑂2 𝑡𝑒𝑟𝑠𝑒𝑟𝑎𝑝 𝑟𝑎𝑡𝑎 − 𝑟𝑎𝑡𝑎 (𝑉𝑎−𝑉𝑏)𝑁 𝐻𝐶𝑙

𝑂𝐻 − = 𝑅𝑎 =

𝑒𝑘 × 𝑉𝑡𝑖𝑡𝑟𝑎𝑠𝑖

𝑎 × 𝐻 × 𝜌𝑔𝑎𝑠 ×√𝐷𝑎×𝐾2 ×𝑂𝐻 − 1+



𝑎 × 𝐻 √𝐷𝑎×𝐾2 ×𝑂𝐻− 𝐾𝐺𝑎

Variabel 1 (3,5 ml/sec) Ra

= 3,5 x10-3 L/s x 0,69 N = 2,415 x10-3 mol/sec

[𝑂𝐻 − ] = =

̅̅̅̅ − 𝑉𝑎̅) × 𝑁 𝐻𝐶𝑙 (𝑉𝑏 𝑒𝑘𝑖𝑣𝑎𝑙𝑒𝑛 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 (3,927 − 2,545)10−3 𝐿 × 0,69 𝑁 1 × 0.01 𝐿

= 0,095 𝑁

= 0,095 mol/liter = 0,095 x 103 mol/m3

2,415 x10−3 mol/sec 10−4 𝑚𝑜𝑙 . 𝑃𝑎 × 759938 𝑝𝑎 × √2.1 × 10−9 𝑚2 × 𝐾2 × 0,095 x 103 mol/𝑚3 𝑚3 10−4 𝑚𝑜𝑙 5,052 𝑥 10−10 /m × 2.88 × . 𝑃𝑎 √2.1 10−9 𝑚2 × 𝐾2 × 0,095 x 103 mol/𝑚3 3 𝑚 1+ 2.84 × 10−8 𝑚𝑜𝑙/𝑝𝑎. 𝑚3 . 𝑠

5,052 𝑥 10−10 /𝑚 × 2.88 × =

2

2,415 x10−3 mol/sec

=

𝑚𝑜𝑙 2.1𝑥10−9 𝑚2 . 𝑃𝑎 × √ × 0,095 x 103 mol/𝑚3 3 𝑠 𝑚 2,415 x10−3 mol/s × (759938 𝑝𝑎 − ) 2.84 × 10−8 𝑚𝑜𝑙/𝑝𝑎. 𝑚3 . 𝑠 )

5,052 𝑥 10−10 /𝑚 × 2.88 × 10−4 (

𝐾2 = 3,144 × 1015 m3/mol.sec 

Variabel 2 (4,5 ml/sec) = 4.5 x10-3 L/s x 0,69 N

Ra

= 3,105 x10-3 mol/sec ̅̅̅̅ − 𝑉𝑎̅) × 𝑁 𝐻𝐶𝑙 (𝑉𝑏 𝑒𝑘𝑖𝑣𝑎𝑙𝑒𝑛 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 (0,563)10−3 𝐿 × 0,69 𝑁 = 1 × 0.01 𝐿

[𝑂𝐻 − ] =

= 0,039𝑁 = 0,039

mol/liter = 0,039 x 103 mol/m3

3,105 × 10−3 mol/sec 10−4 𝑚𝑜𝑙 . 𝑃𝑎 × 759938 𝑝𝑎 × √2.1 × 10−9 𝑚2 × 𝐾2 × 0,039 x 103 mol/𝑚3 𝑚3 10−4 𝑚𝑜𝑙 5,052 𝑥 10−10 /m × 2.88 × . 𝑃𝑎 √2.1 10−5 𝑚2 × 𝐾2 × 0,039 x 103 mol/𝑚3 𝑚3 1+ 2.93 × 10−8 𝑚𝑜𝑙/𝑝𝑎. 𝑚3 . 𝑠

5,052 𝑥 10−10 /𝑚 × 2.88 × =

2

3,105 × 10−3 mol/sec

=

𝑚𝑜𝑙 2,1𝑥10−9 𝑚2 . 𝑃𝑎 × √ × 0,039 x 103 mol/m3 3 𝑠 𝑚 3,105 × 10−3 mol/sec × (759938 𝑝𝑎 − ) 2.93 × 10−8 𝑚𝑜𝑙/𝑝𝑎. 𝑚3 . 𝑠 )

5,052 𝑥 10−10 /𝑚 × 2.88 × 10−4 (

𝐾2 = 1,299 × 1016 m3/mol.sec 

Variabel 3 (5,5 ml/sec) Ra

= 5,5 x10-3 L/s x 0,93 N = 3,795 x10-3 mol/sec ̅̅̅̅ − 𝑉𝑎̅) × 𝑁 𝐻𝐶𝑙 (𝑉𝑏 𝑒𝑘𝑖𝑣𝑎𝑙𝑒𝑛 × 𝑉 𝑡𝑖𝑡𝑟𝑎𝑠𝑖 (0,482)10−3 𝐿 × 0,69 𝑁 = 1 × 0.01 𝐿

[𝑂𝐻 − ] =

= 0,033 𝑁 = 0,033 mol/liter = 0,033 x 103 mol/m3

3,795 x10−3 mol/sec 10−4 𝑚𝑜𝑙 . 𝑃𝑎 × 759938 𝑝𝑎 × √2.1 × 10−9 𝑚2 × 𝐾2 × 0,033 x 103 mol/m3 𝑚3 10−4 𝑚𝑜𝑙 5,052 𝑥 10−10 /m × 2.88 × . 𝑃𝑎 √2.1 10−5 𝑚2 × 𝐾2 × 0,033 x 103 mol/m3 𝑚3 1+ 3,09 × 10−8 𝑚𝑜𝑙/𝑝𝑎. 𝑚3 . 𝑠

5,052 𝑥 10−10 /𝑚 × 2.88 × =

2

3,795 x10−3 mol/sec

=

𝑚𝑜𝑙 2,1𝑥10−9 𝑚2 . 𝑃𝑎 × √ × 0,033 x 103 mol/m3 𝑠 𝑚3 3,795 x10−3 mol/sec × (759938 𝑝𝑎 − ) 3,09 × 10−8 𝑚𝑜𝑙/𝑝𝑎. 𝑚3 . 𝑠 )

5,052 𝑥 10−10 /𝑚 × 2.88 × 10−4 (

𝐾2 = 2,417 × 1016 m3/mol.sec

Debit NaOH (ml/sec) 3,5 4,5 5,5

N ratarata CO2 terserap (mol/L) 0,27 0,34 0,40

Ra (mol/s)

[OH-] {mol/m3)

𝒌𝑮𝑨 (m3/s)

k2 (m3/mol.s)

2,415 x10-3 3,105 x10-3 3,795 x10-3

0,095 x 103 0,039 x 103 0,033 x 103

2.84 × 10−8

3,144 × 1015

2.93 × 10−8 3,09 × 10−8

1,299 × 1016 2,417 × 1016