LAMPIRAN F ALAT TRANSPORTASI FLUIDA DAN ALAT PENUNJANG F.2 Alat Penunjang F.2.1 Kompresor (C-101) Fungsi : Menaikan tekanan dari 3,54 bar ke 8,71 bar. 1. Menghitung Laju Alir Volumetrik Tekanan masuk (P1) : 3,54 bar = 3,5 atm = 7406,77 lbf/ft2 Tekanan keluar (P2) : 8,71 bar = 8,6 atm = 18199,49 lbf/ft2 Laju alir massa (N) : 1266,72 kg/jam = 21,84 kmol/jam : 30 oC = 303K
Tin N × R × Tin
mv =
P1 kmol
=
mol
atm
21,84 jam × 103 jam ×0,082 L mol.K× 303 K 3,5 atm
= 1596,902 L/jam = 15,969 m3/jam = 9,399 ft3/menit = 0,1566 ft3/detik
2. Menghitung Daya Kompresor HP =
3,03 × 10−5 × k k−1
Dimana:
HP =
P2
P1 × mv × [[P ] 1
− 1] (Peters,Timmerhaus hal.524)
mv
= laju alir volumetric (ft3/menit)
P1
= tekanan masuk (lbf/ft2)
P2
= tekanan keluar (lbf/ft2)
k
= ratio panas spesifik (cp/cv) = 1,1669
η
= efisiensi kompresor = 75%
3,03 × 10−5 × 1,2202 1,2202−1
HP η
=
2,0588 0,75
(Aspen hysys) 1,2202−1
× 7406,77 × 9,3991 ×
= 2,0588 HP HP actual =
𝑘−1 𝑘
=2,745 HP
7406,77 1,2202 [[18199,49 ]
− 1]
Efisiensi motor (η) = 85% , maka: P=
HPactual η
=
2,745 0,85
= 3,229 HP = 2,409 kWatt 3. Menghitung diameter pipa ekonomis (De) ρ/campuran = 688,61 kg/m3 = 42,989 lb/ft3
(Aspen hysys)
Diameter pipa ekonomis (De) dihitung dengan persamaan: De = 3,9 (mv)0,45 × (ρ)0,13
(Timmerhaus,1991)
= 3,9 (0,1566)0,45 × (42,989)0,13 = 2,76 in
Dipilih material pipa commercial steel 3 in schedule 40: Diameter dalam (ID)
= 3,068 in = 0,2555 ft
Diameter luar (OD)
= 3,5 in = 0,291 ft
Luas penampang (A)
= 0,0513 ft2
(Appendix A.5 Geankoplis)
F.2.2 Kompresor (C-102) Fungsi : Menaikan tekanan dari 8,71 bar ke 17,22 bar. 1. Menghitung Laju Alir Volumetrik Tekanan masuk (P1) : 8,71 bar = 8,6 atm = 18199,49 lbf/ft2 Tekanan keluar (P2) : 17,22 bar = 17 atm = 35975,74 lbf/ft2 Laju alir massa (N) : 1267,3 kg/jam = 21,85 kmol/jam : 93 oC = 366 K
Tin mv =
N × R × Tin P1 kmol
=
mol
atm
21,85 jam × 103 jam ×0,082 L mol.K× 366 K 8,6 atm
= 785,389 L/jam = 7,8538 m3/jam = 4,6226 ft3/menit = 0,0770 ft3/detik
2. Menghitung Daya Kompresor HP =
3,03 × 10−5 × k k−1
Dimana:
HP =
P2
P1 × mv × [[P ]
𝑘−1 𝑘
1
− 1] (Peters,Timmerhaus hal.524)
mv
= laju alir volumetric (ft3/menit)
P1
= tekanan masuk (lbf/ft2)
P2
= tekanan keluar (lbf/ft2)
k
= ratio panas spesifik (cp/cv) = 1,1669
η
= efisiensi kompresor = 75%
3,03 × 10−5 × 1,2325 1,2325−1
(Aspen hysys) 1,2325−1
× 18199,49 × 4,6226 ×
35975,74 1,2325 [[18199,49]
− 1]
=1,8537 HP HP actual =
HP η
=
1,8537 0,75
=2,471 HP
Efisiensi motor (η) = 85% , maka: P=
HPactual η
=
2,471 0,85
= 2,907 HP = 2,169 kWatt 3. Menghitung diameter pipa ekonomis (De) ρ/campuran = 615,29 kg/m3 = 38,412 lb/ft3
(Aspen hysys)
Diameter pipa ekonomis (De) dihitung dengan persamaan: De = 3,9 (mv)0,45 × (ρ)0,13
(Timmerhaus,1991)
= 3,9 (0,0770)0,45 × (38,412)0,13 = 1,97 in
Dipilih material pipa commercial steel 2 in schedule 40: Diameter dalam (ID)
= 2,067 in = 0,172 ft
Diameter luar (OD)
= 2,375 in = 0,197 ft
Luas penampang (A)
= 0,0233 ft2
(Appendix A.5 Geankoplis)