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LAMPIRAN F ALAT TRANSPORTASI FLUIDA DAN ALAT PENUNJANG F.2 Alat Penunjang F.2.1 Kompresor (C-101) Fungsi : Menaikan tekanan dari 3,54 bar ke 8,71 bar. 1. Menghitung Laju Alir Volumetrik Tekanan masuk (P1) : 3,54 bar = 3,5 atm = 7406,77 lbf/ft2 Tekanan keluar (P2) : 8,71 bar = 8,6 atm = 18199,49 lbf/ft2 Laju alir massa (N) : 1266,72 kg/jam = 21,84 kmol/jam : 30 oC = 303K

Tin N × R × Tin

mv =

P1 kmol

=

mol

atm

21,84 jam × 103 jam ×0,082 L mol.K× 303 K 3,5 atm

= 1596,902 L/jam = 15,969 m3/jam = 9,399 ft3/menit = 0,1566 ft3/detik

2. Menghitung Daya Kompresor HP =

3,03 × 10−5 × k k−1

Dimana:

HP =

P2

P1 × mv × [[P ] 1

− 1] (Peters,Timmerhaus hal.524)

mv

= laju alir volumetric (ft3/menit)

P1

= tekanan masuk (lbf/ft2)

P2

= tekanan keluar (lbf/ft2)

k

= ratio panas spesifik (cp/cv) = 1,1669

η

= efisiensi kompresor = 75%

3,03 × 10−5 × 1,2202 1,2202−1

HP η

=

2,0588 0,75

(Aspen hysys) 1,2202−1

× 7406,77 × 9,3991 ×

= 2,0588 HP HP actual =

𝑘−1 𝑘

=2,745 HP

7406,77 1,2202 [[18199,49 ]

− 1]

Efisiensi motor (η) = 85% , maka: P=

HPactual η

=

2,745 0,85

= 3,229 HP = 2,409 kWatt 3. Menghitung diameter pipa ekonomis (De) ρ/campuran = 688,61 kg/m3 = 42,989 lb/ft3

(Aspen hysys)

Diameter pipa ekonomis (De) dihitung dengan persamaan: De = 3,9 (mv)0,45 × (ρ)0,13

(Timmerhaus,1991)

= 3,9 (0,1566)0,45 × (42,989)0,13 = 2,76 in

Dipilih material pipa commercial steel 3 in schedule 40: Diameter dalam (ID)

= 3,068 in = 0,2555 ft

Diameter luar (OD)

= 3,5 in = 0,291 ft

Luas penampang (A)

= 0,0513 ft2

(Appendix A.5 Geankoplis)

F.2.2 Kompresor (C-102) Fungsi : Menaikan tekanan dari 8,71 bar ke 17,22 bar. 1. Menghitung Laju Alir Volumetrik Tekanan masuk (P1) : 8,71 bar = 8,6 atm = 18199,49 lbf/ft2 Tekanan keluar (P2) : 17,22 bar = 17 atm = 35975,74 lbf/ft2 Laju alir massa (N) : 1267,3 kg/jam = 21,85 kmol/jam : 93 oC = 366 K

Tin mv =

N × R × Tin P1 kmol

=

mol

atm

21,85 jam × 103 jam ×0,082 L mol.K× 366 K 8,6 atm

= 785,389 L/jam = 7,8538 m3/jam = 4,6226 ft3/menit = 0,0770 ft3/detik

2. Menghitung Daya Kompresor HP =

3,03 × 10−5 × k k−1

Dimana:

HP =

P2

P1 × mv × [[P ]

𝑘−1 𝑘

1

− 1] (Peters,Timmerhaus hal.524)

mv

= laju alir volumetric (ft3/menit)

P1

= tekanan masuk (lbf/ft2)

P2

= tekanan keluar (lbf/ft2)

k

= ratio panas spesifik (cp/cv) = 1,1669

η

= efisiensi kompresor = 75%

3,03 × 10−5 × 1,2325 1,2325−1

(Aspen hysys) 1,2325−1

× 18199,49 × 4,6226 ×

35975,74 1,2325 [[18199,49]

− 1]

=1,8537 HP HP actual =

HP η

=

1,8537 0,75

=2,471 HP

Efisiensi motor (η) = 85% , maka: P=

HPactual η

=

2,471 0,85

= 2,907 HP = 2,169 kWatt 3. Menghitung diameter pipa ekonomis (De) ρ/campuran = 615,29 kg/m3 = 38,412 lb/ft3

(Aspen hysys)

Diameter pipa ekonomis (De) dihitung dengan persamaan: De = 3,9 (mv)0,45 × (ρ)0,13

(Timmerhaus,1991)

= 3,9 (0,0770)0,45 × (38,412)0,13 = 1,97 in

Dipilih material pipa commercial steel 2 in schedule 40: Diameter dalam (ID)

= 2,067 in = 0,172 ft

Diameter luar (OD)

= 2,375 in = 0,197 ft

Luas penampang (A)

= 0,0233 ft2

(Appendix A.5 Geankoplis)

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