Lado De Los Tubos.docx

Lado de los tubos 𝑎𝑓𝑡 = (

𝑎𝑓𝑡 𝑁𝑡 0.515𝑖𝑛2 252 ) =( ) = 0.15𝑓𝑡 2 𝑓𝑡 2 𝑡𝑢𝑏𝑜 #𝑝𝑎𝑠𝑜𝑠 6 144 2 𝑖𝑛

𝑙𝑏 𝑊𝑝𝑒𝑡𝑟𝑜𝑙𝑒𝑜 149000 ℎ 𝑙𝑏 𝐺𝑡 = = = 993333 2 2 𝑎𝑓𝑡 0.15𝑓𝑡 𝑓𝑡 ℎ ℎ𝑖𝑜 𝑑𝑖 𝐶𝑝𝜇 1/3 𝑑𝑖 𝑣𝑖 𝜌 0.8 𝑑𝑖 = 0.027 ( ) ( ) (𝜑𝑖) ( ) 𝑘 𝑘 𝜇 𝑑𝑜 1/3 𝐵𝑇𝑈 (0.43 )(2.5𝑐𝑝)(2.42) 𝐶𝑝𝜇 1/3 ℎ ( ) =( ) = 3.26 𝑘 0.075

0.8

(

𝑑𝑖 𝑣𝑖 𝜌 ) 𝜇

0.8 0.810𝑖𝑛 𝑙𝑏 ( ) (993333 2 ) 12𝑓𝑡/𝑖𝑛 𝑓𝑡 ℎ =( ) = 1720 (2.5𝑐𝑝)(2.42)

𝑑𝑖 0.810𝑖𝑛 ( )=( ) = 0.81 𝑑𝑜 1𝑖𝑛 ℎ𝑖𝑜 0.075 𝐵𝑇𝑈 = 0.027(3.26)(1720)(0.81) ( ) = 137 2 °𝐹 0.81𝑖𝑛 𝜑𝑖 ℎ𝑓𝑡 ( ) 12𝑓𝑡/𝑖𝑛 A la temperatura de la pared 340°F petroleo= 0.55cp 𝜑𝑖 = (

𝜇 0.14 2.5𝑐𝑝 0.14 ) =( ) = 1.24 𝜇𝑤 0.55𝑐𝑝

Despejando hio ℎ𝑖𝑜 = (137

𝐵𝑇𝑈 𝐵𝑇𝑈 ) (1.24) = 169 2 ℎ𝑓𝑡 °𝐹 ℎ𝑓𝑡 2 °𝐹