Lab-3-
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LAB -3-
Ionic Reaction Purpose: The purpose of this lab is to study the effect of solubility of some ionic products on the pathway of an ionic reaction. An ionic reaction is a process through which aqueous ionic species react together to form a water insoluble product that falls out of solution and can be isolated. The general formula for an ionic reaction: (m) An+ + (n) Bm- AmBn (solid) Example: Fe2+(aqueous) + CO32- (aqueous) FeCO3 (insoluble precipitate) We will study the ionic reaction between Cu++ cation (Cupric) with several anions Materials: An aqueous solution of CuSO4: The cation is Cu2+ and the Anion is SO42Concentration = 0.063 M Aqueous test solutions: NaCl aqueous solution; Concentration = [NaCl] = 0.086 M NaOH aqueous solution; [NaOH] = 0.17 M KOH aqueous solution; [KOH] = 0.057 M NH4[FeIII(SO4)2] aqueous solution; concentration = 0.019 M Na2WO4 aqueous solution; [Na2WO4] = 0.031 M NaB4O7 aqueous solution; [NaB4O7] = 0.013 M What is the anion in each salt?
Procedure: Place 1.5 ml of the aqueous CuSO4 solution in 6 different test tubes inside a test tube rack. To each test tube add a designated amount of the test solution and record your results. Use the disposable plastic pipette to transfer the liquids. NaCl: Add 1 ml Do you form a precipitate? Yes Write the net ionic reaction if any?
No
Which are the spectator ions? NaOH: 0.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? KOH: 1.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? NH4[FeIII(SO4)2]: 1.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? Na2WO4: 1.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? NaB4O7: 1.5 ml Do you form a precipitate?
Yes
Write the net ionic reaction if any? Which are the spectator ions? Which Copper salts are insoluble in water? Conclusion:
No
This experiment demonstrates that the solubility of the product determines the path of an ionic reaction.
Ionic Reaction Purpose: The purpose of this lab is to study the effect of solubility of some ionic products on the pathway of an ionic reaction. An ionic reaction is a process through which aqueous ionic species react together to form a water insoluble product that falls out of solution and can be isolated. The general formula for an ionic reaction: (m) An+ + (n) Bm- AmBn (solid) Example: Fe2+(aqueous) + CO32- (aqueous) FeCO3 (insoluble precipitate) We will study the ionic reaction between Cu++ cation (Cupric) with several anions Materials: An aqueous solution of CuSO4: The cation is Cu2+ and the Anion is SO42Concentration = 0.063 M Aqueous test solutions: NaCl aqueous solution; Concentration = [NaCl] = 0.086 M NaOH aqueous solution; [NaOH] = 0.17 M KOH aqueous solution; [KOH] = 0.057 M NH4[FeIII(SO4)2] aqueous solution; concentration = 0.019 M Na2WO4 aqueous solution; [Na2WO4] = 0.031 M NaB4O7 aqueous solution; [NaB4O7] = 0.013 M What is the anion in each salt?
Procedure: Place 1.5 ml of the aqueous CuSO4 solution in 6 different test tubes inside a test tube rack. To each test tube add a designated amount of the test solution and record your results. Use the disposable plastic pipette to transfer the liquids. NaCl: Add 1 ml Do you form a precipitate? Yes Write the net ionic reaction if any?
No
Which are the spectator ions? NaOH: 0.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? KOH: 1.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? NH4[FeIII(SO4)2]: 1.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? Na2WO4: 1.5 ml Do you form a precipitate?
Yes
No
Write the net ionic reaction if any? Which are the spectator ions? NaB4O7: 1.5 ml Do you form a precipitate?
Yes
Write the net ionic reaction if any? Which are the spectator ions? Which Copper salts are insoluble in water? Conclusion:
No
This experiment demonstrates that the solubility of the product determines the path of an ionic reaction.
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