Jawab-ruang-sampel-no-9.pdf
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3 12
3!
3 12
3!
3 12
3!
12!
Jumlah cacat 0 = = x = 1x 0 5 0!(3 − 0)! 5!(12 − 5)!
12!
Jumlah cacat 1 = = x = 3x 1 4 1!(3 − 1)! 4!(12 − 4)!
12!
12 x11x10 x9 x8 = 792 5 x 4 x3 x 2
12 x11x10 x9 = 495 4 x3 x 2 12 x11x10
Jumlah cacat 2 = = x = 3x = 110 3x 2 2 3 2!(3 − 2)! 3!(12 − 3)! Jumlah cara untuk mendapatkan jumlah cacat minimal 2 adalah 792 + 495 + 110 = 1.397
3!
3 12
3!
3 12
3!
12!
Jumlah cacat 0 = = x = 1x 0 5 0!(3 − 0)! 5!(12 − 5)!
12!
Jumlah cacat 1 = = x = 3x 1 4 1!(3 − 1)! 4!(12 − 4)!
12!
12 x11x10 x9 x8 = 792 5 x 4 x3 x 2
12 x11x10 x9 = 495 4 x3 x 2 12 x11x10
Jumlah cacat 2 = = x = 3x = 110 3x 2 2 3 2!(3 − 2)! 3!(12 − 3)! Jumlah cara untuk mendapatkan jumlah cacat minimal 2 adalah 792 + 495 + 110 = 1.397
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