Ispit 12.09

  • November 2019
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  • Words: 356
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Zadatak 1 Razredna sredina xi 83 88 93 98 103 108 113 0

88 93 98 103 108 113 118 0 UKP

Širina razreda (xsi-artsr) na kvadrat (xsi-artsr) putana fi treću (xsi-artsr) puta fi na četvrtu kumulanta puta fi manje od

ii

(Xsi- X )2* fi

(Xsi- X )3* fi

(Xsi- X )4* fi

fi 3 1 14 10 9 2 1 0

Xsi 85.5 90.5 95.5 100.5 105.5 110.5 115.5 0

xsi * fi 256.50 90.50 1337.00 1005.00 949.50 221.00 115.50 0.00

5 5 5 5 5 5 5 0

577.55 78.77 210.22 12.66 337.64 247.53 260.02 0.00

-8013.46 -699.04 -814.60 14.24 2068.05 2753.79 4192.75 0.00

111186.80 6204.02 3156.57 16.02 12666.80 30635.86 67608.13 0.00

40

703.5

3975.00

5

1724.38

-498.28

231474.19

3 4 18 Mo 28 Me 37 39 40 40

-41.63 -8.88 -54.25 11.25 55.13 22.25 16.13 0.00 0.00 0.00

Aritmetička sredina

99.38

MOD se računa prema koregiranoj frekvenciji

Mo = l1 +

(b −a ) i ( b − a ) + (b − c)

96.82

b-a=

13

b-c= (b-a)+(b-c)=

4 17

b = frekvencija (koregirana) modalnog razreda (najčešća) a = frekvencija (koregirana) razreda ispred modalnog razreda c = frekvencija (koregirana) razreda iza modalnog razreda l1 = donja granica modalnog razreda i = veličina razreda modalnog razreda

Zadatak 2 Rangiraj vrijednosti numeričkih varijabli. Izračunaj koeficjent korelacije ranga Spearmana i izreci zaključak xi

yi

r(x)

r(y)

di =r(xi)-r(yi)

di * di

122 98 103 110 100 91 97 113 121 102 97 111 119 101 99 1584

80 100 102 91 100 111 109 100 89 104 111 102 98 111 123 1531

15 4 9 10 6 1 2.5 12 14 8 2.5 11 13 7 5 120

1 6 8.5 3 6 13 11 6 2 10 13 8.5 4 13 15 120

14 -2 0.5 7 0 -12 -8.5 6 12 -2 -10.5 2.5 9 -6 -10 0

196 4 0.25 49 0 144 72.25 36 144 4 110.25 6.25 81 36 100 983

n

r s =1− 6 *di*di= (n*n*n)-n= rs=

6∑ d i i =1 3

2

n −n

, -1 ≤ rs ≤ 1

5898 3360 1.76 -0.76

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